leetcode62—Unique Paths
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).
The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below).
How many possible unique paths are there?

Above is a 7 x 3 grid. How many possible unique paths are there?
Note: m and n will be at most 100.
Example 1:
Input: m = 3, n = 2 Output: 3 Explanation: From the top-left corner, there are a total of 3 ways to reach the bottom-right corner: 1. Right -> Right -> Down 2. Right -> Down -> Right 3. Down -> Right -> Right
Example 2:
Input: m = 7, n = 3 Output: 28
想法:采用动态规划,确立状态转移表达式f(m,n)=f(m-1,n)+f(n-1,m)表示可能性。
class Solution {
public:
int uniquePaths(int m, int n) {
int result[m][n];
; i < m ; i++){
; j < n ; j++){
== i || == j){
result[i][j] = ;
continue;
}
result[i][j] = result[i-][j] + result[i][j-];
}
}
][n-];
}
};
leetcode62—Unique Paths的更多相关文章
- [LeetCode62]Unique Paths
题目: A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). ...
- leetcode-62. Unique Paths · DP + vector
题面 A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). ...
- Leetcode62.Unique Paths不同路径
一个机器人位于一个 m x n 网格的左上角 (起始点在下图中标记为"Start" ). 机器人每次只能向下或者向右移动一步.机器人试图达到网格的右下角(在下图中标记为" ...
- [Swift]LeetCode62. 不同路径 | Unique Paths
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The ...
- [LeetCode] Unique Paths II 不同的路径之二
Follow up for "Unique Paths": Now consider if some obstacles are added to the grids. How m ...
- [LeetCode] Unique Paths 不同的路径
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The ...
- Leetcode Unique Paths II
Follow up for "Unique Paths": Now consider if some obstacles are added to the grids. How m ...
- Unique Paths II
这题在Unique Paths的基础上增加了一些obstacle的位置,应该说增加的难度不大,但是写的时候对细节的要求多了很多,比如,第一列的初始化会受到之前行的第一列的结果的制约.另外对第一行的初始 ...
- LEETCODE —— Unique Paths II [动态规划 Dynamic Programming]
唯一路径问题II Unique Paths II Follow up for "Unique Paths": Now consider if some obstacles are ...
随机推荐
- 杀人游戏(hdu2211)插入法
杀人游戏 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submi ...
- Java - TreeSet源码解析
Java提高篇(二八)------TreeSet 与HashSet是基于HashMap实现一样,TreeSet同样是基于TreeMap实现的.在<Java提高篇(二七)-----TreeMap& ...
- HDU4417(SummerTrainingDay08-N 主席树)
Super Mario Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total ...
- POJ3090(SummerTrainingDay04-M 欧拉函数)
Visible Lattice Points Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 7450 Accepted: ...
- zookeeper3.4.5+Hbase1.2.6安装教程
说明:在安装zookeeper+Hbase之前,我们应该已经将hadoop集群搭建好了(三个节点),并且验证启动成功.因为HBase是一种构建在HDFS之上的分布式.面向列的存储系*统. zookee ...
- pms前端结构
后台采用.net MVC框架,前端采用requirejs.整个系统页面布局基本不变,每个页面只改变Main_Content部分. 模板页cshtml: <!DOCTYPE html> &l ...
- import、export使用介绍
import.export使用介绍 ES6提供的import.export方法, 使组件化开发模式迈向新高度.本文来介绍import.export的语法及使用方法. 根据 export 的导出方式,可 ...
- 个人理解的Lambda表达式的演化过程
之前在组内进行过相关分享,为防止以后再单独整理,故在此将自己的PPT内容存放下. 所以,多数代码都是以图片的方式展现. 委托 什么是委托? 定义:委托是方法的抽象,它存储的就是一系列具有相同签名和返回 ...
- SQLServer 学习笔记之超详细基础SQL语句 Part 6
Sqlserver 学习笔记 by:授客 QQ:1033553122 -----------------------接Part 5------------------- 28 聚合函数 --求平均分 ...
- 免费的局域网协作办公方式—onlyoffice文档协作
局域网内想享受协作办公的乐趣,请移步到这里按照步骤部署.https://blog.csdn.net/hotqin888/article/details/79337881 它是免费开源的,经过作者的一些 ...