path的用法和所遇错误

首先上源代码:

 def _path(route, view, kwargs=None, name=None, Pattern=None):
     if isinstance(view, (list, tuple)):
         # For include(...) processing.
         pattern = Pattern(route, is_endpoint=False)
         urlconf_module, app_name, namespace = view
         return URLResolver(
             pattern,
             urlconf_module,
             kwargs,
             app_name=app_name,
             namespace=namespace,
         )
     elif callable(view):
         pattern = Pattern(route, name=name, is_endpoint=True)
         return URLPattern(pattern, view, kwargs, name)
     else:
         raise TypeError('view must be a callable or a list/tuple in the case of include().')

从中可明白错误信息是在第17行,而错误原因则是意外参数或views没有tuple或list类型.

解决方案:则是让view里的函数返回的参数为tuple或者list即可