HDU 4706:Children's Day
Children's Day
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1733 Accepted Submission(s): 1121
For example, this is a big 'N' start with 'a' and it's size is 3.
a e
bdf
c g
Your task is to write different 'N' from size 3 to size 10. The pixel character used is from 'a' to 'z' continuously and periodic('a' is reused after 'z').
[pre]
a e
bdf
c g
h n
i mo
jl p
k q
.........
r j
[/pre]HintNot all the resultsare listed in the sample. There are just some lines. The ellipsis expresseswhat you should write.
迷失在幽谷中的鸟儿,独自飞翔在这偌大的天地间,却不知自己该飞往何方……
#include <iostream>
#include <cmath>
#include <stdio.h>
#include <string>
#include <cstring>
#include <map>
#include <set>
#include <vector>
#include <stack>
#include <queue>
#include <iomanip>
#include <algorithm>
using namespace std;
char mp[20][20];
char nextc(char c)
{
if(c=='z')return 'a';
else return ++c;
}
int main()
{
char cur='a';
int i,j,k;
for(i=3; i<=10; i++)
{
memset(mp,' ',sizeof(mp));
for(j=0; j<i; j++)
{
mp[j][0]=cur;
cur=nextc(cur);
}
for(j=i-2,k=1; j>0; j--,k++)
{
mp[j][k]=cur;
cur=nextc(cur);
}
for(j=0; j<i; j++)
{
mp[j][i-1]=cur;
cur=nextc(cur);
}
for(j=0; j<i; j++)
{
for(k=0; k<i; k++)
printf("%c",mp[j][k]);
printf("\n");
}
}
return 0;
}
HDU 4706:Children's Day的更多相关文章
- hdu 4706 Children's Day(模拟)
http://acm.hdu.edu.cn/showproblem.php?pid=4706 [题目大意]: 用a-z排出N的形状,输出大小为3-10的N,如果超过z之后,重新从a开始 下面是大小为3 ...
- HDU 4706 Children's Day(简单模拟)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4706 题目大意:要用‘a’-‘z’ 26个小写字母输出倒着写得字母'N'的形状,例如 a ebdfc ...
- HDU 4706 Children's Day (水题)
Children's Day Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)To ...
- hdu 4706:Children's Day(模拟题,模拟输出大写字母 N)
Children's Day Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)To ...
- hdu 4706 Children's Day 2013年ICPC热身赛A题 模拟
题意:按字母顺序排列成n型,简单的模拟题. 当字母排到z时从a开始重新排起. 代码: /* * Author: illuz <iilluzen[at]gmail.com> * Blog: ...
- hduoj 4706 Children's Day 2013 ACM/ICPC Asia Regional Online —— Warmup
http://acm.hdu.edu.cn/showproblem.php?pid=4706 Children's Day Time Limit: 2000/1000 MS (Java/Others) ...
- HDOJ/HDU 1297 Children’s Queue(推导~大数)
Problem Description There are many students in PHT School. One day, the headmaster whose name is Pig ...
- HDU 1297 Children’s Queue (递推、大数相加)
Children’s Queue Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) ...
- hdu 4706
注意一点 空的地方打空格而不是空字符,我因为这wa了一次... #include<cstdio> #include<cstring> #include<cstdlib&g ...
随机推荐
- oc 正则图片<img /> 标签
-(NSString *)getImageAttributeValue:(NSString *)content attributeKey:(NSString *)key { NSString *reg ...
- Java FX中TreeView节点选中和双击事件监听
TreeItem<String> treeRoot = new TreeItem<String>("Root"); treeRoot.setExpanded ...
- .net 调度器怎么实现心跳(socket除了他,没选择吧)
自己写调度器,就要从tcp通信入手:心跳的实现除了使用socket,想不到其他任何方案. socket基本使用demo: Socket Client: static void Main(string[ ...
- Three.js基础探寻九——网格
在学习了几何形状和材质之后,我们就能使用他们来创建物体了.最常用的一种物体就是网格(Mesh),网格是由顶点.边.面等组成的物体:其他物体包括线段(Line).骨骼(Bone).粒子系统(Partic ...
- Java内存分配全面浅析
本文将由浅入深详细介绍Java内存分配的原理,以帮助新手更轻松的学习Java.这类文章网上有很多,但大多比较零碎.本文从认知过程角度出发,将带给读者一个系统的介绍. 进入正题前首先要知道的是Java程 ...
- SpringMvc:处理模型数据
SpringMvc提供了以下途径输出模型数据: -ModelAndView:处理方法返回值类型为ModelAndView,方法体即可通过该对象添加模型数据 -Map或Model:入参为org.spri ...
- Array.prototype.each
Array.prototype.each = function(closure){ //递归合并 return this.length ? [closure(this.slice(0,1))].con ...
- JavaOOP项目 CMS内容管理系统
数据库里创建一个News表,要有标题.作者.时间.内容等列. 1:首先要使用JDBC进行数据库连接,得先在项目里新建一个Folder,把Sqlserver 的驱动jar包导入. 2:使用MyEclip ...
- bean在容器上的生命周期
初始化两种方法: 1,使用init-method属性指定那个方法在bean依赖关系设置好后自动执行. 2,实现initializingBean接口 实现 ...
- cluster集群
http://zwfang09.blog.sohu.com/entry/ Cluster 集群 ,群集 --- 负载均衡 LB ,load-balance --- 高可用集群 HA ,High Ava ...