hduoj 4706 Children's Day 2013 ACM/ICPC Asia Regional Online —— Warmup
http://acm.hdu.edu.cn/showproblem.php?pid=4706
Children's Day
Time Limit: 2000/1000 MS (Java/Others)
Memory Limit: 32768/32768 K (Java/Others)
a e
bdf
c g
Your task is to write different 'N' from size 3 to size 10. The pixel character used is from 'a' to 'z' continuously and periodic('a' is reused after 'z').
Not all the resultsare listed in the sample. There are just some lines. The ellipsis expresseswhat you should write.
分析:
输出由字符组成的‘N’ , 三到十的大小。(模拟一下就可以啦)
AC代码:
#include<cstdio>
#include<cstring>
using namespace std;
char map[][];
int main() {
int k = ;
for(int n = ;n <= ;n++) { //memset(map,'\n',sizeof(map));
for(int i = ;i <= n;i++) {
for(int j = ;j < n;j++) {
if(i == || i == n - || i + j == n - ) {
map[j][i] = k % + 'a';
k++;
} else if(i == n) {
map[j][i] = '\0';
} else map[j][i] = ' ';
}
} for(int i = ;i < n;i++)
printf("%s\n",map[i]);
}
return ;
}
hduoj 4706 Children's Day 2013 ACM/ICPC Asia Regional Online —— Warmup的更多相关文章
- hduoj 4706 Herding 2013 ACM/ICPC Asia Regional Online —— Warmup
hduoj 4706 Children's Day 2013 ACM/ICPC Asia Regional Online —— Warmup Herding Time Limit: 2000/1000 ...
- hduoj 4712 Hamming Distance 2013 ACM/ICPC Asia Regional Online —— Warmup
http://acm.hdu.edu.cn/showproblem.php?pid=4712 Hamming Distance Time Limit: 6000/3000 MS (Java/Other ...
- hduoj 4710 Balls Rearrangement 2013 ACM/ICPC Asia Regional Online —— Warmup
http://acm.hdu.edu.cn/showproblem.php?pid=4710 Balls Rearrangement Time Limit: 6000/3000 MS (Java/Ot ...
- hduoj 4708 Rotation Lock Puzzle 2013 ACM/ICPC Asia Regional Online —— Warmup
http://acm.hdu.edu.cn/showproblem.php?pid=4708 Rotation Lock Puzzle Time Limit: 2000/1000 MS (Java/O ...
- hduoj 4715 Difference Between Primes 2013 ACM/ICPC Asia Regional Online —— Warmup
http://acm.hdu.edu.cn/showproblem.php?pid=4715 Difference Between Primes Time Limit: 2000/1000 MS (J ...
- hduoj 4707 Pet 2013 ACM/ICPC Asia Regional Online —— Warmup
http://acm.hdu.edu.cn/showproblem.php?pid=4707 Pet Time Limit: 4000/2000 MS (Java/Others) Memory ...
- 2013 ACM/ICPC Asia Regional Online —— Warmup
1003 Rotation Lock Puzzle 找出每一圈中的最大值即可 代码如下: #include<iostream> #include<stdio.h> #inclu ...
- HDU 4714 Tree2cycle(树状DP)(2013 ACM/ICPC Asia Regional Online ―― Warmup)
Description A tree with N nodes and N-1 edges is given. To connect or disconnect one edge, we need 1 ...
- HDU 4749 Parade Show 2013 ACM/ICPC Asia Regional Nanjing Online
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4749 题目大意:给一个原序列N,再给出一个序列M,问从N中一共可以找出多少个长度为m的序列,序列中的数 ...
随机推荐
- java编程算法
一.字符串相关操作 String s = " Hello java,hello android,hello OOP,HELLO String,hello JAVASE!"; Sys ...
- session和cookie区别
<?php session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//E ...
- 蓝牙HID协议笔记
1.概述 The Human Interface Device (HID)定义了蓝牙在人机接口设备中的协议.特征和使用规程.典型的应用包括蓝牙鼠标.蓝牙键盘.蓝牙游戏手柄等.该协议改编自USB ...
- Chart控件,把Y轴设置成百分比
这次所有属性设置都用代码(就当整理便于以后查询). 在窗体放置一个Chart控件,未做任何设置:然后编写代码: //设置 chart2.Legends[ ].Enabled = false;//不显示 ...
- 对于HIVE架构的理解
1.Hive 能做什么,与 MapReduce 相比优势在哪里 关于hive这个工具,hive学习成本低,入手快,对于熟悉sql语法的人来说,操作简单,熟悉. 2.为什么说 Hive 是 Hadoo ...
- 【Android测试】【第十节】MonkeyRunner—— 录制回放
◆版权声明:本文出自胖喵~的博客,转载必须注明出处. 转载请注明出处:http://www.cnblogs.com/by-dream/p/4861693.html 前言 在实际项目进行过程中,频繁的需 ...
- IOS的APNS和PushKit门道详述
基本功 iOS在诞生之初为了最大程度的保证用户体验,做了一些高瞻远瞩且影响深远的设计.APNs(Apple Push Notification service)就是其中一项. 早期iOS设备的内存和C ...
- appium testcase1(Java)
官网源码地址 https://github.com/appium/sample-code/blob/47fc0305396b8322b727820ca55a07607395040c/sample-co ...
- iOS 使用Xcode和Instruments调试解决iOS内存泄露(链接转)
http://blog.csdn.net/totogo2010/article/details/8233565
- php数组遍历
<?php $arr = array('a','b','c','d','e','f'); //for语句只能遍历索引数组 for($i = 0; $i < 6; $i++){ echo $ ...