Problem Description
Calculate S(n).

S(n)=13+23 +33 +......+n3 .

 
Input
Each line will contain one integer N(1 < n < 1000000000). Process to end of file.
 
Output
For each case, output the last four dights of S(N) in one line.
 
Sample Input
1
2
 
Sample Output
0001
0009
 
 #include <stdio.h>   // 运用数学公式:1^3 +2^3 +3^3 +……+n^3 =[n(n+1)/2]^2

 int main(){
int n;
int result; while(scanf("%d",&n)!=EOF){
n=n%;
result=(n*(n+)/)%;
result=(result*result)%; printf("%04d\n",result);
} return ;
}

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