Problem Description
Calculate S(n).

S(n)=13+23 +33 +......+n3 .

 
Input
Each line will contain one integer N(1 < n < 1000000000). Process to end of file.
 
Output
For each case, output the last four dights of S(N) in one line.
 
Sample Input
1
2
 
Sample Output
0001
0009
 
 #include <stdio.h>   // 运用数学公式:1^3 +2^3 +3^3 +……+n^3 =[n(n+1)/2]^2

 int main(){
int n;
int result; while(scanf("%d",&n)!=EOF){
n=n%;
result=(n*(n+)/)%;
result=(result*result)%; printf("%04d\n",result);
} return ;
}

Calculate S(n)的更多相关文章

  1. [转] PHP计算两个坐标之间的距离, Calculate the Distance Between Two Points in PHP

    Calculate the Distance Between Two Points in PHP There are a lot of applications where it is useful ...

  2. CoreException: Could not calculate build plan: Plugin org.apache.maven.plugins:maven-compiler-plugin:3.1 or one of its dependencies could not be resolved

    CoreException: Could not calculate build plan: Plugin org.apache.maven.plugins:maven-compiler-plugin ...

  3. maven -- 问题解决(二)解决“Could not calculate build plan”问题

    错误提示如下:(eclipse+maven) Could not calculate build plan: Failure to transfer org.apache.maven.plugins: ...

  4. 线段树 + 矩阵 --- ZOJ 3772 Calculate the Function

    Calculate the Function Problem's Link:   http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCod ...

  5. hdu 1012:u Calculate e(数学题,水题)

    u Calculate e Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Tot ...

  6. Calculate its MTBF assuming 2000 FITS for each DRAM

    COMPUTER ORGANIZATION AND ARCHITECTURE DESIGNING FOR PERFORMANCE NINTH EDITION A common unit of meas ...

  7. u Calculate e 分类: HDU 2015-06-19 22:18 14人阅读 评论(0) 收藏

    u Calculate e Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total ...

  8. How to calculate a good InnoDB log file size

    Peter wrote a post a while ago about choosing a good InnoDB log file size.  Not to pick on Peter, b ...

  9. Calculate the formula

    Problem Description You just need to calculate the sum of the formula: 1^2+3^2+5^2+……+ n ^2.   Input ...

  10. How to Calculate difference between two dates in C# z

    Do you need to find the difference in number of days, hours or even minute between the two date rang ...

随机推荐

  1. 【懒人专用系列】Xind2TestCase的初步探坑

    公司最近说要弄Xind2TestCase,让我们组先试用一下 解释:https://testerhome.com/topics/17554 github项目:https://github.com/zh ...

  2. 自动生成 html5 小页面

    StringBuilder htmltext = new StringBuilder();            try            {                //var readP ...

  3. [C++ STL] deque使用详解

    一.deque介绍: deque(双端队列)是一个动态数组,可以向两端发展,因此不论在尾部或头部安插元素都十分迅速. 在中间部分安插元素则比较费时,因为必须移动其它元素. 二.用法 1.头文件 #in ...

  4. 经典矩阵dp寻找递增最大长度

    竖向寻找矩阵最大递增元素长度,因为要求至少一列为递增数列,那么每行求一下最大值就可以作为len[i]:到i行截止的最长的递增数列长度. C. Alyona and Spreadsheet time l ...

  5. 381 Insert Delete GetRandom O(1) - Duplicates allowed O(1) 时间插入、删除和获取随机元素 - 允许重复

    设计一个支持在平均 时间复杂度 O(1) 下, 执行以下操作的数据结构.注意: 允许出现重复元素.    insert(val):向集合中插入元素 val.    remove(val):当 val ...

  6. YumRepo Error: All mirror URLs are not using ftp, http[s] or file

    有台机器使用Yum的时候,报错如下: YumRepo Error: All mirror URLs are not using ftp, http[s] or file. Eg. $releaseve ...

  7. Roslyn导致发布网站时报错:编译失败

    最近新升级了Visual Studio 2017,创建的Web项目Bin目录中多了一个叫roslyn的文件夹,该文件夹导致网站在某些服务器上发布出错 从网上搜索了一下,Roslyn是新出的动态编译工具 ...

  8. Ceph在手,天下我有

    有人问我,你是如何做到统一存储的?我微微一笑,大声告诉他:Ceph在手,天下我有. Ceph是一个统一的分布式存储系统,旨在实现出色的性能,可靠性和可扩展性.认了OpenStack做大哥之后更是一发不 ...

  9. MySQL的主从复制(windows)

    在我们实际的开发中,当系统业务到达一定的程度,可能数据库会到达一定的瓶颈,但实际开发中最容易到达数据库瓶颈的应该是数据库的读性能,一般的业务大多都是读多写少,我们可以通过提高读的性能来提高数据库的整体 ...

  10. [ Nowcoder Contest 175 #B ] 区间

    \(\\\) \(Description\) 给出一个长度为\(N\)的序列\(A[1]...A[N]\),定义一个合法区间 \([L,R]\) 当且仅当区间\(GCD\) 在这个区间内,求最长合法区 ...