Codeforces Round #327 (Div. 2)B(逻辑)
2 seconds
256 megabytes
standard input
standard output
The name of one small but proud corporation consists of n lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slogan. They decided to start with the name.
For this purpose the corporation has consecutively hired m designers. Once a company hires the i-th designer, he immediately contributes to the creation of a new corporation name as follows: he takes the newest version of the name and replaces all the letters xi by yi, and all the letters yi by xi. This results in the new version. It is possible that some of these letters do no occur in the string. It may also happen that xi coincides with yi. The version of the name received after the work of the last designer becomes the new name of the corporation.
Manager Arkady has recently got a job in this company, but is already soaked in the spirit of teamwork and is very worried about the success of the rebranding. Naturally, he can't wait to find out what is the new name the Corporation will receive.
Satisfy Arkady's curiosity and tell him the final version of the name.
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 200 000) — the length of the initial name and the number of designers hired, respectively.
The second line consists of n lowercase English letters and represents the original name of the corporation.
Next m lines contain the descriptions of the designers' actions: the i-th of them contains two space-separated lowercase English letters xi and yi.
Print the new name of the corporation.
6 1
police
p m
molice
11 6
abacabadaba
a b
b c
a d
e g
f a
b b
cdcbcdcfcdc
In the second sample the name of the corporation consecutively changes as follows:






题意:
给出一个长为n的字符串a[],进行m次操作;
每次操作描述为将字符a改成字符b,将字符b改成字符a;
思路:
开一个字符数组str存储a...z26个字符。。直接对str里面的字符进行交换操作。。
然后用a[i]-"a"做下标。。str[a[i]-"a"]即为交换后的字符。。
代码:
#include <bits/stdc++.h>
using namespace std; int main(void)
{
std::ios::sync_with_stdio(false);
int n, m;
string a;
cin >> n >> m >> a;
char str[];
for(int i=; i<; i++)
str[i]=i+'a';
while(m--)
{
char a, b;
cin >> a >> b;
if(a==b) continue;
for(int i=; i<; i++)
{
if(str[i]==a) str[i]=b;
else if(str[i]==b) str[i]=a;
}
}
for(int i=; i<a.size(); i++)
cout << str[a[i]-'a'];
cout << endl;
return ;
}
Codeforces Round #327 (Div. 2)B(逻辑)的更多相关文章
- Codeforces Round #327 (Div. 2) A. Wizards' Duel 水题
A. Wizards' Duel Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/591/prob ...
- Codeforces Round #327 (Div. 2) E. Three States BFS
E. Three States Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/591/probl ...
- Codeforces Round #327 (Div. 2) D. Chip 'n Dale Rescue Rangers 二分 物理
D. Chip 'n Dale Rescue Rangers Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/co ...
- Codeforces Round #327 (Div. 2) C. Median Smoothing 找规律
C. Median Smoothing Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/591/p ...
- Codeforces Round #327 (Div. 2) B. Rebranding 水题
B. Rebranding Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/591/problem ...
- Codeforces Round #327 (Div. 1), problem: (A) Median Smoothing
http://codeforces.com/problemset/problem/590/A: 在CF时没做出来,当时直接模拟,然后就超时喽. 题意是给你一个0 1串然后首位和末位固定不变,从第二项开 ...
- Codeforces Round #327 (Div. 2) B. Rebranding C. Median Smoothing
B. Rebranding The name of one small but proud corporation consists of n lowercase English letters. T ...
- Codeforces Round #327 (Div. 2)
题目传送门 水 A - Wizards' Duel 题目都没看清就写了,1e-4精度WA了一次... /************************************************ ...
- Codeforces Round #327 (Div. 2)-Wizards' Duel
题意: 在一条长度为l的走廊,两个人站在走廊的左右两端分别以p,q的速度走来,问他们相遇时离左端的距离是多少? 思路: 非常简单的暴力题,不解释. 代码如下: #include <iostrea ...
随机推荐
- 比较两个数据库表table结构不同之处
/*--比较两个数据库的表字段差异 hy 适用多种版本库 --*/ /*--调用示例 exec p_comparestructure 'database1','database2' --*/ ) dr ...
- windows server 2008 R2 SP1 安装exchange 2010
一. 先决条件 若在windows server R2 SP1企业版系统上典型安装exchange server2010 SP3,则需要提前确定一下先决条件 AD域环境,域和林的功能级别必须是wind ...
- iOS跳转到另一个程序
我这里只是写了部分东西,如果想看更加详细的,请点击原文链接. 原文链接:http://blog.csdn.net/likendsl/article/details/7553605 原则上iOS的沙 ...
- Android学习笔记(八)——四种基本布局
//此系列博文是<第一行Android代码>的学习笔记,如有错漏,欢迎指正! 布局是一种可用于放置很多控件的容器,它可以按照一定的规律调整内部控件的位置,或是嵌套子布局,从而编写出精美的界 ...
- BZOJ 3665: maths
Sol 矩阵乘法+快速幂+欧拉定理. 首先观察题目可以发现 \(A_n\) 可以表示成关于 \(K\) 和 \(A_0\) 的几次幂的形式. \(A_0\) 就比较简单了 \(m^n\) 所以第一部分 ...
- cacti错误
cacti 错误:CMDPHP: Poller[0] ERROR 解决方案: 找到错误表 desc 表名: 修复此表 mysqlcheck -A -o -r -p -u用户名
- Ubuntu 16.04播放器Rhythmbox乱码解决
使用Rhythmbox进行音乐播放的时候,歌曲名称专辑歌手名称都出现乱码,查看了网上很多教程,要不就是将音频转码,要不就是修改用户环境编码配置.前一种方法对音频有改动,后一种可能无效还有可能会影响系统 ...
- 转:ASP.NET 使用Ajax
之前在Ajax初步理解中介绍了对Ajax的初步理解,本文将介绍在ASP.NET中如何方便使用Ajax,第一种当然是使用jQuery的ajax,功能强大而且操作简单方便,第二种是使用.NET封装好的Sc ...
- 善用VS中的Code Snippet来提高开发效率
http://www.cnblogs.com/anderslly/archive/2009/02/16/vs2008-code-snippets.html http://www.cnblogs.com ...
- PhpExcel笔记,phpExcel中文帮助手册
下面是总结的几个使用方法 include 'PHPExcel.php'; include 'PHPExcel/Writer/Excel2007.php'; //或者include 'PHPExcel/ ...