G 全然背包
<span style="color:#3333ff;">/* /*
__________________________________________________________________________________________________
* copyright: Grant Yuan *
* algorithm: 全然背包 *
* time : 2014.7.18 *
*_________________________________________________________________________________________________*
G - 全然背包
Time Limit:1000MS Memory Limit:30000KB 64bit IO Format:%I64d & %I64u
Submit Status
Description
John never knew he had a grand-uncle, until he received the notary's letter. He learned that his late grand-uncle had gathered a lot of money, somewhere in South-America, and that John was the only inheritor.
John did not need that much money for the moment. But he realized that it would be a good idea to store this capital in a safe place, and have it grow until he decided to retire. The bank convinced him that a certain kind of bond was interesting for him.
This kind of bond has a fixed value, and gives a fixed amount of yearly interest, payed to the owner at the end of each year. The bond has no fixed term. Bonds are available in different sizes. The larger ones usually give a better interest. Soon John realized that the optimal set of bonds to buy was not trivial to figure out. Moreover, after a few years his capital would have grown, and the schedule had to be re-evaluated.
Assume the following bonds are available:
Value Annual
interest
4000
3000 400
250 With a capital of e10 000 one could buy two bonds of $4 000, giving a yearly interest of $800. Buying two bonds of $3 000, and one of $4 000 is a better idea, as it gives a yearly interest of $900. After two years the capital has grown to $11 800, and it makes sense to sell a $3 000 one and buy a $4 000 one, so the annual interest grows to $1 050. This is where this story grows unlikely: the bank does not charge for buying and selling bonds. Next year the total sum is $12 850, which allows for three times $4 000, giving a yearly interest of $1 200.
Here is your problem: given an amount to begin with, a number of years, and a set of bonds with their values and interests, find out how big the amount may grow in the given period, using the best schedule for buying and selling bonds.
Input
The first line contains a single positive integer N which is the number of test cases. The test cases follow.
The first line of a test case contains two positive integers: the amount to start with (at most $1 000 000), and the number of years the capital may grow (at most 40).
The following line contains a single number: the number d (1 <= d <= 10) of available bonds.
The next d lines each contain the description of a bond. The description of a bond consists of two positive integers: the value of the bond, and the yearly interest for that bond. The value of a bond is always a multiple of $1 000. The interest of a bond is never more than 10% of its value.
Output
For each test case, output – on a separate line – the capital at the end of the period, after an optimal schedule of buying and selling.
Sample Input
1
10000 4
2
4000 400
3000 250
Sample Output
14050
*/
#include<iostream>
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<algorithm>
using namespace std; int sm,y,t,n,d,m;
int a[1111],b[1111];
int dp[200000]; int main()
{
cin>>t;
while(t--){
cin>>sm>>y;cin>>n;
for(int i=0;i<n;i++)
{
cin>>d>>b[i];
a[i]=d/1000;} for(int i=0;i<y;i++){
m=sm;m=m/1000;
memset(dp,0,sizeof(dp));
for(int j=0;j<n;j++)
for(int k=a[j];k<=m;k++){
dp[k]=max(dp[k],dp[k-a[j]]+b[j]);
}
sm+=dp[m];}
cout<<sm<<endl;
}
return 0;
}
</span>
G 全然背包的更多相关文章
- HDU 1248寒冰王座-全然背包或记忆化搜索
寒冰王座 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submi ...
- HDU 1248 寒冰王座(全然背包:入门题)
HDU 1248 寒冰王座(全然背包:入门题) http://acm.hdu.edu.cn/showproblem.php?pid=1248 题意: 不死族的巫妖王发工资拉,死亡骑士拿到一张N元的钞票 ...
- HDU 4508 湫湫系列故事——减肥记I(全然背包)
HDU 4508 湫湫系列故事--减肥记I(全然背包) http://acm.hdu.edu.cn/showproblem.php?pid=4508 题意: 有n种食物, 每种食物吃了能获得val[i ...
- A_全然背包
/* copyright: Grant Yuan algorithm: 全然背包 time : 2014.7.18 __________________________________________ ...
- nyist oj 311 全然背包 (动态规划经典题)
全然背包 时间限制:3000 ms | 内存限制:65535 KB 难度:4 描写叙述 直接说题意,全然背包定义有N种物品和一个容量为V的背包.每种物品都有无限件可用.第i种物品的体积是c,价值是 ...
- HDU 1114 Piggy-Bank 全然背包
Piggy-Bank Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit S ...
- poj 1384 Piggy-Bank(全然背包)
http://poj.org/problem?id=1384 Piggy-Bank Time Limit: 1000MS Memory Limit: 10000K Total Submissions: ...
- UVA 10465 Homer Simpson(全然背包: 二维目标条件)
UVA 10465 Homer Simpson(全然背包: 二维目标条件) http://uva.onlinejudge.org/index.php? option=com_onlinejudge&a ...
- [2012山东ACM省赛] Pick apples (贪心,全然背包,枚举)
Pick apples Time Limit: 1000MS Memory limit: 165536K 题目描写叙述 Once ago, there is a mystery yard which ...
随机推荐
- Python Cdn平台文件md5验证
第一步 先用脚本实现基本的md5验证 1.python如何实现文件的下载 方法一: 使用 urllib 模块提供的 urlretrieve() 函数.urlretrieve() 方法直接将远程数据下载 ...
- 关于dispatch_sync死锁问题
首先,我们来看下下面一个例子: 代码:(串行队列里同步线程嵌套) NSLog(@"haha"); dispatch_queue_t queue = dispatch ...
- 老男孩全栈python学习进程表
老男孩Python高级全栈开发工程师-1 0001.开学典礼_ALEX简介 00:55:53 ☆ 0002.职业生涯_来培训的目的 01:12:29 ☆ 0003.课程目标 00:29: ...
- python学习-- Django model -class 主键自增问题
转自:http://blog.csdn.net/mapoor/article/details/8609660 prize_id = models.IntegerField(primary_key=Tr ...
- 洛谷9月月赛II 赛后瞎写
看错比赛时间了....结果发现的时候已经开始了半个小时,并且当时正准备睡午觉qwq 于是就水了个t1就 去睡 跑了 T2 写着写着然后看了一发评讲被辣鸡思路给绕了进去最后发现自己宛若一个智障 类似桶的 ...
- Diango路由控制
路由的格式: #路由配置的格式: urls.py里面写 from diango.conf.urls import url urlpatterns = [ url(正则表达式,views视图函数,nam ...
- 使用sami生成文档
从composer安装sami $ composer require sami/sami composer自动配置完以后,可以先测试一下是否安装成功.只要不带参数的运行一下sami,就会知道结果. $ ...
- 数据表自动生成java代码
MyBatis生成代码需要用到mybatis-generator-core-1.3.2.jar.数据库连接驱动包和一个xml文件,xml文件一般命令为:generator.xml. Xml内容格式如下 ...
- 微软2014实习生及秋令营技术类职位在线测试(题目1 : String reorder)
题目1 : String reorder 时间限制:10000ms 单点时限:1000ms 内存限制:256MB Description For this question, your program ...
- 刷题总结——解方程(NOIP2014)
题目: 题目描述 已知多项式方程: a0+a1x+a2x2+…+anxn=0 求这个方程在[1,m]内的整数解(n 和 m 均为正整数). 输入格式 输入共 n+2 行. 第一行包含 2 个整数 n. ...