#include <stdio.h>
#include <algorithm>
#include <iostream>
#include <string.h>
using namespace std; struct stu
{
char ID[];
int GetTime[];
int LeaveTime[];
}; stu Student[]; int main()
{
int n,i,j;
int m;
while(scanf("%d",&m)!=EOF)
{ for(j=;j<m;j++)
{
scanf("%s %d:%d:%d %d:%d:%d",Student[j].ID,&Student[j].GetTime[],&Student[j].GetTime[],&Student[j].GetTime[],&Student[j].LeaveTime[],&Student[j].LeaveTime[],&Student[j].LeaveTime[]);
} int GetHour,GetMin,GetSec,LeaveHour,LeaveMin,LeaveSec; GetHour=GetMin=GetSec=;
LeaveHour=LeaveHour=LeaveSec=-; int OpenMan,CloseMan; for(j=;j<m;j++)
{
if(Student[j].GetTime[]<GetHour)
{
GetHour=Student[j].GetTime[];
OpenMan=j;
}
else if(Student[j].GetTime[]==GetHour)
{
if(Student[j].GetTime[]<GetMin)
{
GetMin=Student[j].GetTime[];
OpenMan=j;
}
else if(Student[j].GetTime[]==GetMin)
{
if(Student[j].GetTime[]<GetSec)
{
GetSec=Student[j].GetTime[];
OpenMan=j;
}
}
} if(Student[j].LeaveTime[]>LeaveHour)
{
LeaveHour=Student[j].LeaveTime[];
CloseMan=j;
}
else if(Student[j].LeaveTime[]==LeaveHour)
{
if(Student[j].LeaveTime[]>LeaveMin)
{
LeaveMin=Student[j].LeaveTime[];
CloseMan=j;
}
else if(Student[j].LeaveTime[]==LeaveMin)
{
if(Student[j].LeaveTime[]>LeaveSec)
{
LeaveSec=Student[j].LeaveTime[];
CloseMan=j;
}
}
}
} printf("%s %s\n",Student[OpenMan].ID,Student[CloseMan].ID); }
return ;
}

1006. Sign In and Sign Out的更多相关文章

  1. PAT 甲级 1006 Sign In and Sign Out (25)(25 分)

    1006 Sign In and Sign Out (25)(25 分) At the beginning of every day, the first person who signs in th ...

  2. 1006 Sign In and Sign Out (25 分)

    1006 Sign In and Sign Out (25 分) At the beginning of every day, the first person who signs in the co ...

  3. PAT甲 1006. Sign In and Sign Out (25) 2016-09-09 22:55 43人阅读 评论(0) 收藏

    1006. Sign In and Sign Out (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue ...

  4. 1006 Sign In and Sign Out (25)(25 分)思路:普通的时间比较题。。。

    1006 Sign In and Sign Out (25)(25 分) At the beginning of every day, the first person who signs in th ...

  5. pat 1006 Sign In and Sign Out(25 分)

    1006 Sign In and Sign Out(25 分) At the beginning of every day, the first person who signs in the com ...

  6. PAT (Advanced Level) Practice 1006 Sign In and Sign Out (25 分) 凌宸1642

    PAT (Advanced Level) Practice 1006 Sign In and Sign Out (25 分) 凌宸1642 题目描述: At the beginning of ever ...

  7. PTA (Advanced Level) 1006 Sign In and Sign Out

    Sign In and Sign Out At the beginning of every day, the first person who signs in the computer room ...

  8. PAT甲级——1006 Sign In and Sign Out

    PATA1006 Sign In and Sign Out At the beginning of every day, the first person who signs in the compu ...

  9. PAT1006:Sign In and Sign Out

    1006. Sign In and Sign Out (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue ...

  10. PAT Sign In and Sign Out[非常简单]

    1006 Sign In and Sign Out (25)(25 分) At the beginning of every day, the first person who signs in th ...

随机推荐

  1. git初步使用总结

    今天时隔大半年之后再一次接触了git,发现在这学期学习过一点linux之后,对git的学习变得感觉一切都是那么理所当然. 下面仅仅是罗列一下我的学习笔记. 1.下载git可以到百度软件库下载,一般都可 ...

  2. 模拟游客一天的生活与旅游java程序代写源码

    在某个城市的商业区里,有一家首饰店,一家饭店,一家面馆,一家火锅店,一家银行,一家当铺 现在有一群来自四川的游客,一群陕西的游客,一群上海的游客,和以上各店家的工作人员在此区域里,请模拟他们一天的生活 ...

  3. SQL Server 日期 时间类型

    --1毫秒=0.001秒 --1微秒=0.000 001秒 --1纳秒=0.000 000 001秒 --datetime精度不大好,末尾值只能是这3种: .000, .003, or .007 -- ...

  4. u-boot移植为tiny6410步骤

    1. 修改顶层Makefile文件 2. 修改arch/arm/cpu/arm1176/s3c64xx/cpu_init.S 3. 修改arch/arm/cpu/arm1176/s3c64xx/Mak ...

  5. pgpool postgresql集群、中间件

    pgpool-II是一个工作于PostgreSQL服务器端和PostgreSQL客户端之间的中间件,它提供了如下的功能: 1.连接池 pgpool-II中保存了到PostgreSQL服务器的连接,然后 ...

  6. IP地址,子网掩码、默认网关,DNS理论解释

    在网上发现的这篇文章写的非常好,有理论有示例. (一)  问题解析 001.   问:  IP地址,子网掩码,默认网关,DNS服务器,有什么区别呀?我知道没有IP地址就不能上网,我也知道没设DNS就不 ...

  7. [改善Java代码]让工具类不可实例化

    建议42: 让工具类不可实例化 Java项目中使用的工具类非常多,比如JDK自己的工具类java.lang.Math.java.util.Collections等都是我们经常用到的.工具类的方法和属性 ...

  8. hihocoder 1066 无间道之并查集

    #1066 : 无间道之并查集 时间限制:20000ms 单点时限:1000ms 内存限制:256MB 描述 这天天气晴朗.阳光明媚.鸟语花香,空气中弥漫着春天的气息……额,说远了,总之,小Hi和小H ...

  9. 每天一道LeetCode--326. Power of Three

    Given an integer, write a function to determine if it is a power of three. Follow up:Could you do it ...

  10. python学习day4--python基础--购物小程序

    '''购物小程序:用户启动时先输入工资用户启动程序后打印商品列表允许用户选择购买商品允许用户不断购买各种商品购买时检测余额是否够,如果够直接扣款,否则打印余额不足允许用户主动退出程序,退出时打印已购商 ...