Given a linked list, determine if it has a cycle in it.

Follow up:
Can you solve it without using extra space?

判断链表中是否有环,不能用额外的空间,可以使用快慢指针,慢指针一次走一步,快指针一次走两步,若是有环则快慢指针会相遇,若是fast->next==NULL则没有环。

值得注意的是:在链表的题中,快慢指针的使用频率还是很高,值得注意。

 /**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
bool hasCycle(ListNode *head)
{
ListNode *pFast=head;
ListNode *pSlow=head; while(pFast&&pFast->next)
{
pSlow=pSlow->next;
pFast=pFast->next->next;
if(pFast==pSlow)
return true;
}
return false;
}
};

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