解析url中参数

兼容不带参数等情况

function getUrlParam(){
        var params = {};
        var search = location.search;
        search = /\?/.test(search) && search.split("?")[1];
        var searchs = /\&/.test(search) ? search.split("&") : [search];
        for(var i = 0 ; i < searchs.length ; i++){
            if(/\=/.test(searchs[i])){
                var item = searchs[i].split("=");
                params[item[0]] = item[1];
            };
        };
        return params;
    };