Given a sequence of positive numbers, a segment is defined to be a consecutive subsequence. For example, given the sequence { 0.1, 0.2, 0.3, 0.4 }, we have 10 segments: (0.1) (0.1, 0.2) (0.1, 0.2, 0.3) (0.1, 0.2, 0.3, 0.4) (0.2) (0.2, 0.3) (0.2, 0.3, 0.4) (0.3) (0.3, 0.4) and (0.4).

Now given a sequence, you are supposed to find the sum of all the numbers in all the segments. For the previous example, the sum of all the 10 segments is 0.1 + 0.3 + 0.6 + 1.0 + 0.2 + 0.5 + 0.9 + 0.3 + 0.7 + 0.4 = 5.0.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N, the size of the sequence which is no more than 1. The next line contains N positive numbers in the sequence, each no more than 1.0, separated by a space.

Output Specification:

For each test case, print in one line the sum of all the numbers in all the segments, accurate up to 2 decimal places.

Sample Input:

4
0.1 0.2 0.3 0.4

Sample Output:

5.00
#include<cstdio>
int main(){
int n;
scanf("%d",&n);
double v,ans = ;
for(int i = ; i <= n; i++){
scanf("%lf",&v);
ans += v * i * (n + - i);
}
printf("%.2f",ans);
return ;
}

1104 Sum of Number Segments(20 分)的更多相关文章

  1. 【PAT甲级】1104 Sum of Number Segments (20 分)

    题意:输入一个正整数N(<=1e5),接着输入N个小于等于1.0的正数,输出N个数中所有序列的和. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC ...

  2. PAT 甲级 1104. Sum of Number Segments (20) 【数学】

    题目链接 https://www.patest.cn/contests/pat-a-practise/1104 思路 最容易想到的一个思路就是 遍历一下所有组合 加一遍 但 时间复杂度 太大 会超时 ...

  3. PAT (Advanced Level) 1104. Sum of Number Segments (20)

    简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #in ...

  4. PAT甲题题解-1104. Sum of Number Segments (20)-(水题)

    #include <iostream> #include <cstdio> #include <algorithm> #include <string.h&g ...

  5. PAT甲级——1104 Sum of Number Segments (数学规律、自动转型)

    本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/90486252 1104 Sum of Number Segmen ...

  6. PAT 甲级 1104 sum of Number Segments

    1104. Sum of Number Segments (20) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CAO, Pen ...

  7. PAT 1104 Sum of Number Segments

    Given a sequence of positive numbers, a segment is defined to be a consecutive subsequence. For exam ...

  8. PAT Advanced A1104 Sum of Number Segments (20) [数学问题]

    题目 Given a sequence of positive numbers, a segment is defined to be a consecutive subsequence. For e ...

  9. 1104 Sum of Number Segments

    题意: 给出n个不大于1.0的小数序列,如{ 0.1, 0.2, 0.3, 0.4 },则共有10个分片(0.1) (0.1, 0.2) (0.1, 0.2, 0.3) (0.1, 0.2, 0.3, ...

随机推荐

  1. eclipse IDE注释模板设置

    1.windows->preference—>java->code style->code template,弹出下图所示的界面.

  2. ACM学习历程—HDU 3915 Game(Nim博弈 && xor高斯消元)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3915 题目大意是给了n个堆,然后去掉一些堆,使得先手变成必败局势. 首先这是个Nim博弈,必败局势是所 ...

  3. Poj 1316 Self Numbers(水题)

    一.Description In 1949 the Indian mathematician D.R. Kaprekar discovered a class of numbers called se ...

  4. boost asio中io_service类的几种使用

    io_service类 你应该已经发现大部分使用Boost.Asio编写的代码都会使用几个io_service的实例.io_service是这个库里面最重要的类:它负责和操作系统打交道,等待所有异步操 ...

  5. unittest单元测试生成HTML测试报告

    前言: HTMLTestRunner 是 Python 标准库的 unittest 模块的一个扩展,它可以生成 HTML的 测试报告. 一.下载HTMLTestRunnerNew.py文件: 下载链接 ...

  6. VisualGDB系列9:配置VS直接通过SSH方式访问Linux项目

    根据VisualGDB官网(https://visualgdb.com)的帮助文档大致翻译而成.主要是作为个人学习记录.有错误的地方,Robin欢迎大家指正. 本文介绍如何使用VS和VisualGDB ...

  7. js检测对象属性

    In:(检测自身及原型属性) var o={x:1}; "x" in o; //true,自有属性存在 "y" in o; //false "toSt ...

  8. oracle sql 语句 示例

    --oracle 用户对象的导入导出 exp devimage/oracle@172.xx.x.xx/TESTDB owner='devimage' file=d:/devimage.dmp log= ...

  9. 【转】GitHub使用

    1.设置Git全局用户配置 git config --global user.name "xxx" git config --global user.email xxx@gmail ...

  10. 使用mahout fpgrowth算法求关联规则

    使用mahout fpgrowth 首先,这篇文章的内容大部分取自国外一篇博客Finding association rules with Mahout Frequent Pattern Mining ...