Given a sequence of positive numbers, a segment is defined to be a consecutive subsequence. For example, given the sequence {0.1, 0.2, 0.3, 0.4}, we have 10 segments: (0.1) (0.1, 0.2) (0.1, 0.2, 0.3) (0.1, 0.2, 0.3, 0.4) (0.2) (0.2, 0.3) (0.2, 0.3, 0.4) (0.3) (0.3, 0.4) (0.4).

Now given a sequence, you are supposed to find the sum of all the numbers in all the segments. For the previous example, the sum of all the 10 segments is 0.1 + 0.3 + 0.6 + 1.0 + 0.2 + 0.5 + 0.9 + 0.3 + 0.7 + 0.4 = 5.0.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N, the size of the sequence which is no more than 105. The next line contains N positive numbers in the sequence, each no more than 1.0, separated by a space.

Output Specification:

For each test case, print in one line the sum of all the numbers in all the segments, accurate up to 2 decimal places.

Sample Input:

4

0.1 0.2 0.3 0.4

Sample Output:

5.00

分析

这道题比较简单

#include<iostream>
#include<vector>
#include<iomanip>
using namespace std;
int main(){
int N;
cin>>N;
double sum=0.00;
vector<double> vi(N,0);
for(int i=0; i<N; i++)
cin>>vi[i];
for(int i=1; i<=vi.size(); i++)
sum+=vi[i-1]*(i)*(N-i+1);
cout<<setiosflags(ios::fixed)<<setprecision(2)<<sum<<endl;
return 0;
}

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