Problem

Figure 2. The probability of any outcome (leaf) in a probability tree diagram is given by the product of probabilities from the start of the tree to the outcome. For example, the probability that X is blue and Y is blue is equal to (2/5)(1/4), or 1/10.

Probability is the mathematical study of randomly occurring phenomena. We will model such a phenomenon with a random variable, which is simply a variable that can take a number of different distinct outcomes depending on the result of an underlying random process.

For example, say that we have a bag containing 3 red balls and 2 blue balls. If we let XX represent the random variable corresponding to the color of a drawn ball, then the probability of each of the two outcomes is given by Pr(X=red)=35Pr(X=red)=35 and Pr(X=blue)=25Pr(X=blue)=25.

Random variables can be combined to yield new random variables. Returning to the ball example, let YY model the color of a second ball drawn from the bag (without replacing the first ball). The probability of YY being red depends on whether the first ball was red or blue. To represent all outcomes of XX and YY, we therefore use a probability tree diagram. This branching diagram represents all possible individual probabilities for XX and YY, with outcomes at the endpoints ("leaves") of the tree. The probability of any outcome is given by the product of probabilities along the path from the beginning of the tree; see Figure 2 for an illustrative example.

An event is simply a collection of outcomes. Because outcomes are distinct, the probability of an event can be written as the sum of the probabilities of its constituent outcomes. For our colored ball example, let AA be the event "YY is blue." Pr(A)Pr(A) is equal to the sum of the probabilities of two different outcomes: Pr(X=blue and Y=blue)+Pr(X=red and Y=blue)Pr(X=blue and Y=blue)+Pr(X=red and Y=blue), or 310+110=25310+110=25 (see Figure 2 above).

Given: Three positive integers kk, mm, and nn, representing a population containing k+m+nk+m+n organisms: kk individuals are homozygous dominant for a factor, mm are heterozygous, and nn are homozygous recessive.

Return: The probability that two randomly selected mating organisms will produce an individual possessing a dominant allele (and thus displaying the dominant phenotype). Assume that any two organisms can mate.

Sample Dataset

2 2 2

Sample Output

0.78333

计算公式:

方法一:
def f(x, y, z):
s = x + y + z # the sum of population
c = s * (s - 1) / 2.0 # comb(2,s)
p = 1 - (z * (z - 1) / 2 + 0.25 * y * (y - 1) / 2 + y * z * 0.5) / c
return p print f(2, 2, 2)

方法二:

# -*- coding: utf-8 -*-
### 7. Mendel's First Law ###
from scipy.misc import comb individuals = input('Number of individuals(k,m,n):')
[k, m, n] = map(int, individuals.split(','))
t = k + m + n rr = comb(n, 2) / comb(t, 2)
hh = comb(m, 2) / comb(t, 2)
hr = comb(n, 1) * comb(m, 1) / comb(t, 2) prob = 1 - (rr + hh * 1 / 4 + hr * 1 / 2) print (prob)

  


07Mendel's First Law的更多相关文章

  1. 齐夫定律, Zipf's law,Zipfian distribution

    齐夫定律(英语:Zipf's law,IPA英语发音:/ˈzɪf/)是由哈佛大学的语言学家乔治·金斯利·齐夫(George Kingsley Zipf)于1949年发表的实验定律. 它可以表述为: 在 ...

  2. Conway's law(康威定律)

    Mel Conway  康威在加利福尼亚理工学院获得物理学硕士学位,在凯斯西储大学获得数学博士学位.毕业之后,他参与了很多知名的软件项目,如 Pascal 编辑器.在他的职业生涯中,康威观察到一个现象 ...

  3. 加州大学伯克利分校Stat2.2x Probability 概率初步学习笔记: Section 3 The law of averages, and expected values

    Stat2.2x Probability(概率)课程由加州大学伯克利分校(University of California, Berkeley)于2014年在edX平台讲授. PDF笔记下载(Acad ...

  4. 墨菲定律-Murphy's Law (转载)

    墨菲定律 “墨菲定律”(Murphy's Law)亦称莫非定律.莫非定理.或摩菲定理,是西方世界常用的俚语. “墨菲定律”:事情往往会向你所想到的不好的方向发展,只要有这个可能性.比如你衣袋里有两把钥 ...

  5. BendFord's law's Chi square test

    http://www.siam.org/students/siuro/vol1issue1/S01009.pdf bendford'law e=log10(1+l/n) o=freq of first ...

  6. 帕金森定律(Parkinson's Law)

    帕金森定律(Parkinson's Law)是官僚主义或官僚主义现象的一种别称, 是由英国历史学家.政治学家西里尔·诺斯古德·帕金森(Cyril Northcote Parkinson)通过长期调查研 ...

  7. 默菲定律 [Murphy's Law]

    一.关于默菲定律(Murphy's Law)   “墨菲定律”.“帕金森定律”和“彼德原理”并称为二十世纪西方文化三大发现. “墨菲定律”的原话是这样说的:If there are two or mo ...

  8. 【分享】IT产业中的三大定理(一) —— 摩尔定理(Moore's Law)

    科技行业流传着很多关于比尔·盖茨的故事,其中一个是他和通用汽车公司老板之间的对话.盖茨说,如果汽车工业能够像计算机领域一样发展,那么今天,买一辆汽车只需要 25 美元,一升汽油能跑四百公里.通用汽车老 ...

  9. 【分享】IT产业中的三大定理(二) —— 安迪&比尔定理 (Andy and Bill's Law)

    摩尔定理给所有的计算机消费者带来一个希望,如果我今天嫌计算机太贵买不起,那么我等十八个月就可以用一半的价钱来买.要真是这样简单的话,计算机的销售量就上不去了.需要买计算机的人会多等几个月,已经有计算机 ...

随机推荐

  1. 51nod 算法马拉松4 D装盒子(网络流 / 二分图最优匹配)

    装盒子   基准时间限制:1 秒 空间限制:131072 KB 分值: 160 有n个长方形盒子,第i个长度为Li,宽度为Wi,我们需要把他们套放.注意一个盒子只可以套入长和宽分别不小于它的盒子,并且 ...

  2. [LeetCode系列] 变序词查找问题(Anagrams)

    给定一系列词, 找出其中所有的变序词组合. Note: 变序词 - 组成字符完全相同但次序不同的单词. 如dog和god, ate和eat. 算法描述: 使用map<string, vector ...

  3. bzoj2957楼房重建

    题目:https://www.lydsy.com/JudgeOnline/problem.php?id=2957 线段树.每个点记录斜率,要一个单增的序列长度(从1开始). 线段树每个点记录自己区间的 ...

  4. Python VIL Realse

    #!/usr/bin/python #-*- coding:utf-8 –*- import os import sys import re import shutil import xlrd imp ...

  5. 嵌入式linux开发:杂七杂八的话

    1. 编译器:常用的有Sourcery,linaro等.当然芯片厂家一般也会提供可用的编译器. 2. 将配置和编译时的输出O到其他位置:make O=some_dir 这样做的好处是保持源代码树的干净 ...

  6. C++ 类成员的构造和析构顺序

    我想对面向对象有了解的童鞋应该不会对类和对象感到陌生吧 ! 对象并不是突然建立起来的,创建对象必须时必须同时创建父类以及包含于其中的对象.C++遵循如下的创建顺序: (1)如果某个类具体基类,执行基类 ...

  7. migrating-vcenter-database-express-to-sql-2008-r2

    migrating-vcenter-database-express-to-sql-2008-r2 一.      准备环境. ESXi5.0主机      IP:192.168.1.158      ...

  8. delete删除属性

    /* 删除实例属性 */ function MyObject() { this.name = "我是实例的name"; } var obj = new MyObject(); al ...

  9. 5_python之路之员工管理系统

    python之路之员工管理系统 1.程序说明:Readme.cmd 1.程序文件:info_management.py user_info 2.程序文件说明:info_management.py-主程 ...

  10. 页面白屏并且报错PHP Parse error: syntax error, unexpected end of file in 试了很久总算解决了

    页面白屏并且报错PHP Parse error:  syntax error, unexpected end of file in 试了很久 啥短标记,打开,都试了 最简单的办法 是重新建立一个文件, ...