3. Longest Substring Without Repeating Characters

Given a string, find the length of the longest substring without repeating characters.

Examples:

Given "abcabcbb", the answer is "abc", which the length is .

Given "bbbbb", the answer is "b", with the length of .

Given "pwwkew", the answer is "wke", with the length of . Note that the answer must be a substring, "pwke" is a subsequence and not a substring

ANSWER:

 class Solution:
def lengthOfLongestSubstring(self, s):
"""
:type s: str
:rtype: int
"""
if s:
i=
max_sub =s[]
len_s=len(s)
while i<len(s):
j=i+
for index in range(j,len_s):
if s[index] not in s[i:index]:
if len(s[i:index+])>len(max_sub):
max_sub=s[i:index+]
else:
break
i+=
return len(max_sub)
else:
return

code

 def main(s):
if s:
i=
max_sub =s[]
len_s=len(s)
while i<len(s):
j=i+
for index in range(j,len_s):
if s[index] not in s[i:index]:
if len(s[i:index+])>len(max_sub):
max_sub=s[i:index+]
else:
break
i+=
return len(max_sub)
else:
return
if __name__ == '__main__':
s='pwwke'
print(main(s))

调试代码

(python)leetcode刷题笔记03 Longest Substring Without Repeating Characters的更多相关文章

  1. 【leetcode刷题笔记】Longest Substring Without Repeating Characters

    Given a string, find the length of the longest substring without repeating characters. For example, ...

  2. (python)leetcode刷题笔记05 Longest Palindromic Substring

    5. Longest Palindromic Substring Given a string s, find the longest palindromic substring in s. You ...

  3. LeetCode(2) || Add Two Numbers && Longest Substring Without Repeating Characters

    LeetCode(2) || Add Two Numbers && Longest Substring Without Repeating Characters 题记 刷LeetCod ...

  4. LeetCode解题笔记 - 3. Longest Substring Without Repeating Characters

    Given a string, find the length of the longest substring without repeating characters. Examples: Giv ...

  5. LeetCode第[3]题(Java):Longest Substring Without Repeating Characters 标签:Linked List

    题目中文:没有重复字符的最长子串 题目难度:Medium 题目内容: Given a string, find the length of the longest substring without ...

  6. leetcode笔记:Longest Substring Without Repeating Characters

    一. 题目描写叙述 Given a string, find the length of the longest substring without repeating characters. For ...

  7. leetcode-【中等题】3. Longest Substring Without Repeating Characters

    题目: Given a string, find the length of the longest substring without repeating characters. Examples: ...

  8. 【Leetcode】【Medium】Longest Substring Without Repeating Characters

    Given a string, find the length of the longest substring without repeating characters. For example, ...

  9. 【leetcode刷题笔记】Longest Valid Parentheses

    Given a string containing just the characters '(' and ')', find the length of the longest valid (wel ...

随机推荐

  1. 微信公众平台创建自定义菜单的PHP代码

    授人以鱼不如授人以渔.在方倍工作室上问了一下,创建自定义菜单的代码多少钱,一张口就一百,好吧,那我就给你们一人省一百块钱吧,你们说该如何谢谢我?事先说明一下啊,你的PHP版本要高于4.0.2才支持cU ...

  2. Openssl 生成证书server.key and server.crt

    1.key的生成 openssl genrsa -des3 -out server.key 2048 这样是生成rsa私钥,des3算法,openssl格式,2048位强度.server.key是密钥 ...

  3. TensorFlow MNIST(手写识别 softmax)实例运行

    TensorFlow MNIST(手写识别 softmax)实例运行 首先要有编译环境,并且已经正确的编译安装,关于环境配置参考:http://www.cnblogs.com/dyufei/p/802 ...

  4. JavaScript学习笔记(十六)——面向对象编程

    在学习廖雪峰前辈的JavaScript教程中,遇到了一些需要注意的点,因此作为学习笔记列出来,提醒自己注意! 如果大家有需要,欢迎访问前辈的博客https://www.liaoxuefeng.com/ ...

  5. Android Toolbar 标题居中及字体样式自定义

    首先找到 toolbar 所在xml布局文件,将toolbar控件放置在一个相对布局(RelativeLayout)中,然后设置toolbar的title为空(随便打几个空格即可): 然后在 tool ...

  6. Solr7.1---数据库导入并建立中文分词器

     这里只是告诉你如何导入,生产环境不要这样部署你的solr服务. 首先修改solrConfig.xml文件 备份_default文件夹 修改solrconfig.xml 加入如下内容 官方示例:< ...

  7. 百度编辑器的内容改变事件监听bug

    先贴上我的初始化代码,可能是用法问题冤枉了百度编辑器,如果是我的用法有问题欢迎大侠们指正 <!DOCTYPE type> <html> <head> <met ...

  8. Android - shape圆形画法(oval)

    shape圆形画法(oval) 本文地址: http://blog.csdn.net/caroline_wendy 1. 创建一个目录drawable, 用于存放xml类型的图片资源; 2. 在dra ...

  9. Hadoop之SequenceFile

    Hadoop序列化文件SequenceFile能够用于解决大量小文件(所谓小文件:泛指小于black大小的文件)问题,SequenceFile是Hadoop API提供的一种二进制文件支持.这样的二进 ...

  10. java多线程编程核心技术——第五章总结

    定时器Timer的使用 1.1方法schedule(TimerTask task, Date time)的测试 1.2方法schedule(TimerTask task, Date firstTime ...