Given n pieces of wood with length L[i] (integer array). Cut them into small pieces to guarantee you could have equal or more than k pieces with the same length. What is the longest length you can get from the n pieces of wood? Given L & k, return the maximum length of the small pieces.

You couldn't cut wood into float length.

Example

For L=[232, 124, 456]k=7, return 114.

Analysis:

From 1 to Max(L), use binary search to find the maximum length;

 public class Solution {
/**
*@param L: Given n pieces of wood with length L[i]
*@param k: An integer
*return: The maximum length of the small pieces.
*/
public int woodCut(int[] L, int k) {
if (L == null || L.length == ) return ;
int startLength = ;
int endLength = maxLength(L); while (startLength <= endLength) {
int mid = startLength + (endLength - startLength) / ;
if (count(L, mid) >= k) {
startLength = mid + ;
} else {
endLength = mid - ;
}
}
return startLength - ; // using startLength will make count(L, startLength) < k
} public int count(int[] L, int length) {
int total = ;
for (int i = ; i < L.length; i++) {
total += L[i] / length;
}
return total;
} public int maxLength(int[] L) {
int max = L[];
for (int i = ; i < L.length; i++) {
max = Math.max(L[i], max);
}
return max;
}
}

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