Description

The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order. It costs 6 seconds to move the elevator up one floor, and 4 seconds to move down one floor. The elevator will stay for 5 seconds at each stop.

For a given request list, you are to compute the total time spent to fulfill the requests on the list. The elevator is on the 0th floor at the beginning and does not have to return to the ground floor when the requests are fulfilled.

 

Input

There are multiple test cases. Each case contains a positive integer N, followed by N positive numbers. All the numbers in the input are less than 100. A test case with N = 0 denotes the end of input. This test case is not to be processed. 
 

Output

Print the total time on a single line for each test case. 
 

Sample Input

1 2
3 2 3 1
0
 

Sample Output

17
41
 
 
 
 #include<iostream>
#include<cstring>
#include<cstdio>
using namespace std;
int main()
{
int n,N,m;
long long num;
while((scanf("%d",&N))&&N!=)
{
m=num=;
while(N--)
{
scanf("%d",&n);
if(m<n)
{
num+=*(n-m);
}
else
{
num+=*(m-n);
}
num+=;
m=n; }
printf("%lld\n",num);
}
}

CDZSC_2015寒假新人(1)——基础 b的更多相关文章

  1. CDZSC_2015寒假新人(1)——基础 i

    Description “Point, point, life of student!” This is a ballad(歌谣)well known in colleges, and you mus ...

  2. CDZSC_2015寒假新人(1)——基础 h

    Description Ignatius was born in a leap year, so he want to know when he could hold his birthday par ...

  3. CDZSC_2015寒假新人(1)——基础 g

    Description Ignatius likes to write words in reverse way. Given a single line of text which is writt ...

  4. CDZSC_2015寒假新人(1)——基础 f

    Description An inch worm is at the bottom of a well n inches deep. It has enough energy to climb u i ...

  5. CDZSC_2015寒假新人(1)——基础 e

    Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever ...

  6. CDZSC_2015寒假新人(1)——基础 d

    Description These days, I am thinking about a question, how can I get a problem as easy as A+B? It i ...

  7. CDZSC_2015寒假新人(1)——基础 c

    Description FatMouse prepared M pounds of cat food, ready to trade with the cats guarding the wareho ...

  8. CDZSC_2015寒假新人(1)——基础 a

    Description Contest time again! How excited it is to see balloons floating around. But to tell you a ...

  9. CDZSC_2015寒假新人(2)——数学 P

    P - P Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status ...

随机推荐

  1. (原)ubuntu上安装dlib

    转载请注明出处: http://www.cnblogs.com/darkknightzh/p/5652791.html 参考网址: http://stackoverflow.com/questions ...

  2. (原+转)error C2872: “ACCESS_MASK”: 不明确的符号 C:\Program Files (x86)\Windows Kits\8.1\Include\um\ktmw32.h 125

    转载请注明出处: http://www.cnblogs.com/darkknightzh/p/5500795.html 参考网址: http://www.lxway.com/88515256.htm ...

  3. MySQL 常用字段类型,介绍及其建表使用方法经验分享

    由于工作的公司没有专业的DBA又经常需要建立各种各种的表来满足自己的业务逻辑,所以经常查看MySQL 手册或者谷歌查看相关资料,所以本人就根据我的工作经验和相关资料来介绍一下MySQL各种字段类型及其 ...

  4. JavaScript 全局变量命名空间生成函数

    <script type="text/javascript"> var GLOBAL = {}; GLOBAL.namespace = function(str){ v ...

  5. XMLHttpRequest基础知识

    XMLHttpRequest 发送请求的两个重要方法:open(method,url,async)——参数:请求方式.请求地址.请求同步/异步:send(string)——参数:使用POST方式时,填 ...

  6. css让图片居中显示在手机屏幕上

    直接上代码了 <div class="showpic"> <span></span> <img src="" alt= ...

  7. MAC下用OPENSSL生成公钥和私钥

    MAC OS自带了OpenSSL,所以不用去编译那一坨跟SHIT一样的源码.直接在命令行里使用OPENSSL就可以. 打开命令行工具,然后输入 openssl打开openssl,接着只要三句命令就可以 ...

  8. [转]MySQL 5.6 全局事务 ID(GTID)实现原理(一)

    原文作者:淘长源 原文连接:http://qing.blog.sina.com.cn/1757661907/68c3cad333002qhe.html 转载注明以上信息   MySQL 5.6 的新特 ...

  9. haproxy之负载均衡算法

    backend     blance 算法 动态hash的特点     服务器运行时就可进行权重调整,即只需要重新载入配置文件即可,不需要重新启动haproxy     支持慢速启动,即重新恢复的后端 ...

  10. python笔记之ZipFile模块

    python笔记之ZipFile模块 zipfile模块用来做zip格式编码的压缩和解压缩的,zipfile里有两个非常重要的class, 分别是ZipFile和ZipInfo, 在绝大多数的情况下, ...