hdoj 5387（Clock）

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=5387

比较水的一道题目，也是自己单翘的第一道题目吧，题意就是找到给定时间时钟三个指针之间的夹角，

需要注意的问题分数的表示方法，辗转相除求最大公因子，同时除去，

此外还应注意夹角为锐角。

 #include<stdio.h>
 #include<cmath>
 #include<algorithm>
 using namespace std;
 int gcd(int a,int b)
 {
     int r;
     if(a<b) {r=a;a=b;b=r;}
     while(b)
     {
         r=a%b;
         a=b;
         b=r;
     }
     return a;
 }
 void per( int &a, int &b){
     int tmp = gcd(a,b);
     a = a / tmp;
     b = b / tmp;
 }
 void show( int a, int b, int c, int d){
      )
         a = a % (  * b);
      )
         c = c % (  * d);
     *abs(a*d-b*c);
     int mot = b*d;
     son = son %( b*d*);
      )
         son = b*d* - son;
     per(son,mot);
      )
         printf("%d/%d ",son,mot);
     else
         printf("%d ",son);
 }
 int main(){
 //    freopen("test.out","r",stdin);
     int T;
     ];
     int hh, mm, ss;
     int total;
     int total2;
     int total3;
     int hour ;
     int minu ;
     int sec ;
     scanf("%d",&T);
     while(T--){
         hour = ;
         minu = ;
         sec = ;
         scanf("%s", in);
         hh = (]-+(]-');
         mm = (]-+(]-');
         ss = (]-+(]-');
         total = ( ss + mm *  + hh *  ) % (  *  );
         total2 = total;
         total3 = total;
         per(total,hour);
         per(total2,minu);
         per(total3,sec);
         show(total,hour,total2,minu);
         show(total,hour,total3,sec);
         show(total3,sec,total2,minu);
         printf("\n");
     }
 }