Complete the Word

ZS the Coder loves to read the dictionary. He thinks that a word is nice if there exists a substring (contiguous segment of letters) of it of length 26 where each letter of English alphabet appears exactly once. In particular, if the string has length strictly less than 26, no such substring exists and thus it is not nice.

Now, ZS the Coder tells you a word, where some of its letters are missing as he forgot them. He wants to determine if it is possible to fill in the missing letters so that the resulting word is nice. If it is possible, he needs you to find an example of such a word as well. Can you help him?

Input

The first and only line of the input contains a single string s (1 ≤ |s| ≤ 50 000), the word that ZS the Coder remembers. Each character of the string is the uppercase letter of English alphabet ('A'-'Z') or is a question mark ('?'), where the question marks denotes the letters that ZS the Coder can't remember.

Output

If there is no way to replace all the question marks with uppercase letters such that the resulting word is nice, then print  - 1 in the only line.

Otherwise, print a string which denotes a possible nice word that ZS the Coder learned. This string should match the string from the input, except for the question marks replaced with uppercase English letters.

If there are multiple solutions, you may print any of them.

Example

Input

ABC??FGHIJK???OPQR?TUVWXY?

Output

ABCDEFGHIJKLMNOPQRZTUVWXYS

Input

WELCOMETOCODEFORCESROUNDTHREEHUNDREDANDSEVENTYTWO

Output

-1

Input

??????????????????????????

Output

MNBVCXZLKJHGFDSAQPWOEIRUYT

Input

AABCDEFGHIJKLMNOPQRSTUVW??M

Output

-1

Note

In the first sample case, ABCDEFGHIJKLMNOPQRZTUVWXYS is a valid answer beacuse it contains a substring of length 26 (the whole string in this case) which contains all the letters of the English alphabet exactly once. Note that there are many possible solutions, such as ABCDEFGHIJKLMNOPQRSTUVWXYZ or ABCEDFGHIJKLMNOPQRZTUVWXYS.

In the second sample case, there are no missing letters. In addition, the given string does not have a substring of length 26 that contains all the letters of the alphabet, so the answer is  - 1.

In the third sample case, any string of length 26 that contains all letters of the English alphabet fits as an answer.

找出字符串的一个子串，所有字母只出现一遍，且26个字母齐全，或者补缺？位能得到26个字母排列的子串，则输出填补后的字符串，否则输出-1。用一个数组来标记，记录字母出现的位置，如果一个字母出现了两遍，那么就回到他出现第一次位置的下一位，所有的数据初始化，继续寻找，直到符合要求了跳出循环。

代码：

#include <iostream>
#include <map>
#include <algorithm>
#include <cstring>
using namespace std;
int main()
{
    string a;
    int t = ;
    int c = ;
    int check[] = {};
    cin>>a;
    int n = ;
    for(int i = ;i < a.size();i ++)
    {
        if(n + c >= )break;
        if(a[i] == '?')n ++;
        else if(a[i] >= 'A' && a[i] <= 'Z')
        {
            if(!check[a[i] - 'A'])
            {
                check[a[i] - 'A'] = i + ;
                c ++;
            }
            else
            {
                i = check[a[i] - 'A'] - ;
                t = i + ;
                n = c = ;
                memset(check,,sizeof(check));
            }
        }
    }
    if(n + c < )cout<<-<<endl;
    else
    {
        int j = ;
        for(int i = ;i < a.size();i ++)
        {
            if(a[i] != '?')cout<<a[i];
            else if(i >= t && i <= t + )
            {
                while(check[j])j++;
                cout<<(char)('A'+j);
                j ++;
            }
            else cout<<'A';//无关紧要的可以随意填补，只要保证满足要求的子串填补好了，其他的随便填补，子串一定要是连续的26个
        }
    }
}