Recommendation system predicts the preference that a user would give to an item. Now you are asked to program a very simple recommendation system that rates the user's preference by the number of times that an item has been accessed by this user.

Input Specification:

Each input file contains one test case. For each test case, the first line contains two positive integers: N (≤ 50,000), the total number of queries, and K (≤ 10), the maximum number of recommendations the system must show to the user. Then given in the second line are the indices of items that the user is accessing -- for the sake of simplicity, all the items are indexed from 1 to N. All the numbers in a line are separated by a space.

Output Specification:

For each case, process the queries one by one. Output the recommendations for each query in a line in the format:

query: rec[1] rec[2] ... rec[K]

where query is the item that the user is accessing, and rec[i] (i=1, ... K) is the i-th item that the system recommends to the user. The first K items that have been accessed most frequently are supposed to be recommended in non-increasing order of their frequencies. If there is a tie, the items will be ordered by their indices in increasing order.

Note: there is no output for the first item since it is impossible to give any recommendation at the time. It is guaranteed to have the output for at least one query.

Sample Input:

12 3
3 5 7 5 5 3 2 1 8 3 8 12

Sample Output:

5: 3
7: 3 5
5: 3 5 7
5: 5 3 7
3: 5 3 7
2: 5 3 7
1: 5 3 2
8: 5 3 1
3: 5 3 1
8: 3 5 1
12: 3 5 8
#include<iostream>
#include<set>
using namespace std;
struct node{
int value,cnt;
bool operator< (const node &a) const{
return (cnt != a.cnt) ? cnt > a.cnt : value < a.value;
}
};
int book[]; int main(){
int n,m,num;
scanf("%d%d",&n,&m);
set<node> s;
for(int i = ; i < n; i++){
scanf("%d",&num);
if(i != ){
printf("%d:",num);
int tempCnt = ;
for(auto it = s.begin(); tempCnt < m && it != s.end();it++){
printf(" %d",it->value);
tempCnt++;
}
printf("\n");
}
auto it = s.find(node{num,book[num]});
if(it != s.end()) s.erase(it);
book[num]++;
s.insert(node{num,book[num]});
}
return ;
}

1129 Recommendation System (25 分)的更多相关文章

  1. PAT甲级 1129. Recommendation System (25)

    1129. Recommendation System (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue ...

  2. 1129. Recommendation System (25)

    Recommendation system predicts the preference that a user would give to an item. Now you are asked t ...

  3. PAT甲题题解-1129. Recommendation System (25)-排序

    博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6789819.html特别不喜欢那些随便转载别人的原创文章又不给 ...

  4. 1129 Recommendation System

    1129 Recommendation System (25 分) Recommendation system predicts the preference that a user would gi ...

  5. PAT 1129 Recommendation System[比较]

    1129 Recommendation System(25 分) Recommendation system predicts the preference that a user would giv ...

  6. PAT 甲级 1129 Recommendation System

    https://pintia.cn/problem-sets/994805342720868352/problems/994805348471259136 Recommendation system ...

  7. PAT 1129 Recommendation System

    Recommendation system predicts the preference that a user would give to an item. Now you are asked t ...

  8. PAT1129:Recommendation System

    1129. Recommendation System (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue ...

  9. PAT_A1129#Recommendation System

    Source: PAT A1129 Recommendation System (25 分) Description: Recommendation system predicts the prefe ...

随机推荐

  1. oralce错误总结

    1>System.Data.OracleClient 需要 Oracle 客户端软件 8.1.7 或更高版本. 给oracle客户端的bin目录添加““Authenticated Users”权 ...

  2. C++ 输出精度和输出小数点位数

    有时候需要调节小数点的精度或者位数 #include<iostream> #include<iomanip> using namespace std; //设置数据精度 set ...

  3. 如何安全退出已调用多个Activity的应用

    对于单一Activity的应用来说,退出很简单,直接finish()即可.当然,也可以用killProcess()和System.exit()这样的方法. 但是,对于多Activity的应用来说,在打 ...

  4. 1.scala基础语法总结

    Scala基础语法总结:Scala 与 Java 的最大区别是:Scala 语句末尾的分号 ; 是可选的.如果一行里写多个语句那么分号是需要的 val s = "菜鸟教程"; pr ...

  5. 36.LEN() 函数

    LEN() 函数 LEN 函数返回文本字段中值的长度. SQL LEN() 语法 SELECT LEN(column_name) FROM table_name SQL LEN() 实例 我们拥有下面 ...

  6. 30.MIN() 函数

    MIN() 函数 MIN 函数返回一列中的最小值.NULL 值不包括在计算中. SQL MIN() 语法 SELECT MIN(column_name) FROM table_name 注释:MIN ...

  7. HTML中meta标签的作用与使用

    META标签用来描述一个HTML网页文档的属性 META标签可分为两大部分:HTTP-EQUIV和NAME变量. HTTP实例 HTML代码实例中有一项内容是 <meta http-equiv= ...

  8. canvas时钟demo

    显示效果如下 源码如下: <!DOCTYPE html> <html lang="en"> <head> <meta charset=&q ...

  9. ASP.NET多页面传递数据,附框架源码

    很多时候我们需要把数据传递到多个页面,比如表单提交可以指定提交数据到某个页面,那么关闭某个页面怎么把数据传递到上一个页面或者它的父页面. 在这里我附一段源码用于当前页面关闭指定某个页面刷新. 子页面方 ...

  10. 编写高质量代码改善C#程序的157个建议——建议28:理解延迟求值和主动求值之间的区别

    建议28:理解延迟求值和主动求值之间的区别 要理解延迟求值(lazy evaluation)和主动求值(eager evaluation),先看个例子: List<, , , , , , , , ...