https://nanti.jisuanke.com/t/31461

题意

一个hash规则,每个字母映射成一个两位数,求给的字符串最后的编码位数,要求去除最终结果的前导零

分析

按题意模拟就是了

#include <iostream>
#include <stdlib.h>
#include <string>
#include <vector>
using namespace std;
int main(){
int t,n,i,j,p,q,num;
char z;
string s;
cin>>t;
vector<int> v;
for(i=;i<t;i++){
cin>>n>>z>>s;
num=;
for(j=;j<n;j++){
p=abs((int)z-s[j]);
if(p>=){
q=p/;
v.push_back(q);
num++;
q=p%;
v.push_back(q);
num++;
}
else{
v.push_back();
num++;
v.push_back(p);
num++;
}
}
vector<int>::iterator it=v.begin();
while(*it==){
num--;
it++;
if(it==v.end()){
num=;
break;
}
}
cout<<num<<endl;
v.clear();
}
return ;
}

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