[LintCode] Trapping rain water II
Given n x m non-negative integers representing an elevation map 2d where the area of each cell is 1 x 1, compute how much water it is able to trap after raining.

Given 5*4 matrix
[12,13,0,12]
[13,4,13,12]
[13,8,10,12]
[12,13,12,12]
[13,13,13,13]
return 14.
struct MyPoint{
int x, y, h;
MyPoint(int xx, int yy, int hh):x(xx), y(yy), h(hh){}
};
struct Cmp{
bool operator()(const MyPoint &p1, const MyPoint &p2){
return p1.h > p2.h;
}
};
class Solution {
public:
/**
* @param heights: a matrix of integers
* @return: an integer
*/
int trapRainWater(vector<vector<int> > &heights) {
int m = heights.size();
if(m < ) return ;
int n = heights[].size();
if(n < ) return ;
int waterNum = ;
vector<vector<bool> > visit(m, vector<bool>(n, false));
priority_queue<MyPoint, vector<MyPoint>, Cmp> MyPointQue;
for(int i = ;i < n;++i){
MyPointQue.push(MyPoint(, i, heights[][i]));
MyPointQue.push(MyPoint(m - , i, heights[m - ][i]));
visit[][i] = true;
visit[m - ][i] = true;
}
for(int j = ;j < m - ;++j){
MyPointQue.push(MyPoint(j, , heights[j][]));
MyPointQue.push(MyPoint(j, n - , heights[j][n - ]));
visit[j][] = true;
visit[j][n - ] = true;
}
const int detX[] = {, , , -}, detY[] = {, -, , };
while(MyPointQue.size() > ){
MyPoint p = MyPointQue.top();
MyPointQue.pop();
for(int i = ;i < ;++i){
int xx = p.x + detX[i], yy = p.y + detY[i];
if(xx < || xx >= m || yy < || yy >= n) continue;
if(visit[xx][yy]) continue;
else{
int h = heights[xx][yy];
if(heights[xx][yy] < p.h){
h = p.h;
waterNum += p.h - heights[xx][yy];
}
MyPointQue.push(MyPoint(xx, yy, h));
visit[xx][yy] = true;
}
}
}
return waterNum;
}
};
[LintCode] Trapping rain water II的更多相关文章
- leetcode 11. Container With Most Water 、42. Trapping Rain Water 、238. Product of Array Except Self 、407. Trapping Rain Water II
11. Container With Most Water https://www.cnblogs.com/grandyang/p/4455109.html 用双指针向中间滑动,较小的高度就作为当前情 ...
- [LeetCode] Trapping Rain Water II 收集雨水之二
Given an m x n matrix of positive integers representing the height of each unit cell in a 2D elevati ...
- [LintCode] Trapping Rain Water 收集雨水
Given n non-negative integers representing an elevation map where the width of each bar is 1, comput ...
- [LeetCode] 407. Trapping Rain Water II 收集雨水之二
Given an m x n matrix of positive integers representing the height of each unit cell in a 2D elevati ...
- [LeetCode] 407. Trapping Rain Water II 收集雨水 II
Given an m x n matrix of positive integers representing the height of each unit cell in a 2D elevati ...
- Leetcode: Trapping Rain Water II
Given an m x n matrix of positive integers representing the height of each unit cell in a 2D elevati ...
- [Swift]LeetCode407. 接雨水 II | Trapping Rain Water II
Given an m x n matrix of positive integers representing the height of each unit cell in a 2D elevati ...
- 407. Trapping Rain Water II
Given an m x n matrix of positive integers representing the height of each unit cell in a 2D elevati ...
- 【Lintcode】364.Trapping Rain Water II
题目: Given n x m non-negative integers representing an elevation map 2d where the area of each cell i ...
随机推荐
- 机器学习公开课笔记(4):神经网络(Neural Network)——表示
动机(Motivation) 对于非线性分类问题,如果用多元线性回归进行分类,需要构造许多高次项,导致特征特多学习参数过多,从而复杂度太高. 神经网络(Neural Network) 一个简单的神经网 ...
- 高流量站点NGINX与PHP-fpm配置优化
导读 使用Nginx搭配PHP已有7年的经历,这份经历让我们学会如何为高流量站点优化NGINX和PHP-fpm配置. 以下正是这方面的一些提示和建议: 1. 将TCP切换为UNIX域套接字 1. 将T ...
- each-Select
While Ruby’s each method is useful, it also comes with an awesome extended family of methods that ar ...
- CUDA中的Toolkit
CUDA Toolkit是什么? 对于使用 C 语言和 C++ 来开发 GPU 加速应用程序的开发者来说,NVIDIA CUDA Toolkit 可提供一个综合的开发环境.CUDA Toolkit 包 ...
- Android控件之圆形Button
bg_circle.xml <?xml version="1.0" encoding="utf-8"?> <layer-list xmlns: ...
- Coursera台大机器学习课程笔记11 -- Nonlinear Transformation
这一节讲的是如何将线性不可分的情况转为非线性可分以及转换的代价.特征转换是机器学习的重点. 最后得出重要的结论是,在做转换时,先从简单模型,再到复杂模型. 参考:http://www.cnblogs. ...
- [ruby on rails] 跟我学之(6)显示指定数据
根据<[ruby on rails] 跟我学之路由映射>,我们知道,可以访问 GET /posts/:id(.:format) 来显示具体的对象. 1. 修改action 修改 ap ...
- ios图标和默认图像
Icon.png和Default.png是两个重要的图像文件.Icon.png充当应用程序的图标,这些图标用于在SpringBoard主屏幕上表示应用程序.Default.png(也称"启动 ...
- jQuery获取Select选择的Text和 Value(转)
radio: radio: var item = $('input[name=items][checked]').val(); var item = $('input[name=items]:chec ...
- 【转】maven仓库快速镜像
本文转自:http://blog.csdn.net/zuoluoboy/article/details/20007819 国内连接maven官方的仓库更新依赖库,网速一般很慢,收集一些国内快速的mav ...