HDU 5054 Alice and Bob（数学）

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=5054

Problem Description

Bob and Alice got separated in the Square, they agreed that if they get separated, they'll meet back at the coordinate point (x, y). Unfortunately they forgot to define the origin of coordinates and the coordinate axis direction. Now, Bob in the lower left
corner of the Square, Alice in the upper right corner of the the Square. Bob regards the lower left corner as the origin of coordinates, rightward for positive direction of axis X, upward for positive direction of axis Y. Alice regards the upper right corner
as the origin of coordinates, leftward for positive direction of axis X, downward for positive direction of axis Y. Assuming that Square is a rectangular, length and width size is N * M. As shown in the figure:




Bob and Alice with their own definition of the coordinate system respectively, went to the coordinate point (x, y). Can they meet with each other ?

Note: Bob and Alice before reaching its destination, can not see each other because of some factors (such as buildings, time poor).

 

Input

There are multiple test cases. Please process till EOF. Each test case only contains four integers : N, M and x, y. The Square size is N * M, and meet in coordinate point (x, y). ( 0 < x < N <= 1000 , 0 < y < M <= 1000 ).

 

Output

If they can meet with each other, please output "YES". Otherwise, please output "NO".

 

Sample Input

10 10 5 5
10 10 6 6

 

Sample Output

YES
NO

 

Source

field=problem&key=BestCoder+Round+%2311+%28Div.+2%29&source=1&searchmode=source" style="color:rgb(26,92,200); text-decoration:none">BestCoder Round #11 (Div. 2)

官方题解：

代码例如以下：

#include <cstdio>
int main()
{
    int n, m;
    int x, y;
    while(~scanf("%d%d%d%d",&n,&m,&x,&y))
    {
        if(x*2==n && y*2==m)
            printf("YES\n");
        else
            printf("NO\n");
    }
    return 0;
}