作者: 负雪明烛
id: fuxuemingzhu
个人博客: http://fuxuemingzhu.cn/


题目地址: https://leetcode.com/problems/repeated-dna-sequences/description/

题目描述:

All DNA is composed of a series of nucleotides abbreviated as A, C, G, and T, for example: “ACGAATTCCG”. When studying DNA, it is sometimes useful to identify repeated sequences within the DNA.

Write a function to find all the 10-letter-long sequences (substrings) that occur more than once in a DNA molecule.

Example:

Input: s = "AAAAACCCCCAAAAACCCCCCAAAAAGGGTTT"

Output: ["AAAAACCCCC", "CCCCCAAAAA"]

题目大意

在一个字符串中找出连续的十个字符,这十个字符不止在一个地方出现过。

解题方法

遍历+set。

做法简单了,需要一个长度是10的字符串切片,从头到尾把字符遍历一遍,然后不停的判断以这个位置开头的10个字符构成的字符串是否看到过,如果看到过就放到另外一个set里。为什么不直接放入list返回呢?因为一个字符串可能会重复多次,为了防止重复添加到结果里,必须set一下。

时间复杂度是O(N),空间复杂度是O(N)。

class Solution(object):
def findRepeatedDnaSequences(self, s):
"""
:type s: str
:rtype: List[str]
"""
seen = set()
repeated = set()
N = len(s)
for i in range(N):
cur = s[i : i+ 10]
if cur in seen:
repeated.add(cur)
else:
seen.add(cur)
return list(repeated)

参考资料:

https://leetcode.com/problems/repeated-dna-sequences/discuss/53855/7-lines-simple-Java-O(n)

日期

2018 年 10 月 11 日 —— 做Hard题真的很难

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