You are assigned to design network connections between certain points in a wide area. You are given a set of points in the area, and a set of possible routes for the cables that may connect pairs of points. For each possible route between two points, you are given the length of the cable that is needed to connect the points over that route. Note that there may exist many possible routes between two given points. It is assumed that the given possible routes connect (directly or indirectly) each two points in the area. Your task is to design the network for the area, so that there is a connection (direct or indirect) between every two points (i.e., all the points are interconnected, but not necessarily by a direct cable), and that the total length of the used cable is minimal. Input The input file consists of a number of data sets. Each data set defines one required network. The first line of the set contains two integers: the first defines the number P of the given points, and the second thenumber R ofgivenroutesbetweenthepoints. Thefollowing R linesdefinethegivenroutesbetween the points, each giving three integer numbers: the first two numbers identify the points, and the third gives the length of the route. The numbers are separated with white spaces. A data set giving only one number P = 0 denotes the end of the input. The data sets are separated with an empty line. The maximal number of points is 50. The maximal length of a given route is 100. The number of possible routes is unlimited. The nodes are identified with integers between 1 and P (inclusive). The routes between two points i and j may be given as ‘i j’ or as ‘j i’. Output For each data set, print one number on a separate line that gives the total length of the cable used for the entire designed network. Sample Input 1 0
2 3 1 2 37 2 1 17 1 2 68
3 7 1 2 19 2 3 11 3 1 7 1 3 5 2 3 89 3 1 91 1 2 32
5 7 1 2 5 2 3 7 2 4 8 4 5 11 3 5 10 1 5 6 4 2 12
0 Sample Output 0 17 16 26

分析:

最小生成树模板题

克鲁斯卡尔算法

code:

/*#include <iostream>
#include <cstdio>*/
#include<stdio.h>
#include<algorithm>
/*#include<cstring>
#include<math.h>
#include<memory>*/
using namespace std;
typedef long long LL;
#define max_v 55
struct edge
{
int x,y;
int w;
};
edge e[];
int rk[max_v];
int pa[max_v];
int sum;
bool cmp(edge a,edge b)
{
return a.w<b.w;
}
void make_set(int x)
{
pa[x]=x;
rk[x]=;
}
int find_set(int x)
{
if(x!=pa[x])
pa[x]=find_set(pa[x]);
return pa[x];
}
void union_set(int x,int y,int w)
{
x=find_set(x);
y=find_set(y);
if(x==y)
return ;
if(rk[x]>rk[y])
pa[y]=x;
else
{
if(rk[x]==rk[y])
rk[y]++;
pa[x]=y;
}
sum+=w;
}
int main()
{
int n,m;
while(~scanf("%d",&n))
{
if(n==)
break;
scanf("%d",&m);
sum=;
for(int i=;i<=n;i++)
make_set(i);
for(int i=;i<m;i++)
{
scanf("%d %d %d",&e[i].x,&e[i].y,&e[i].w);
}
sort(e,e+m,cmp);
for(int i=;i<m;i++)
{
union_set(e[i].x,e[i].y,e[i].w);
}
printf("%d\n",sum);
}
return ;
}

UVALive - 2515 (最小生成树 kruskal)的更多相关文章

  1. 模板——最小生成树kruskal算法+并查集数据结构

    并查集:找祖先并更新,注意路径压缩,不然会时间复杂度巨大导致出错/超时 合并:(我的祖先是的你的祖先的父亲) 找父亲:(初始化祖先是自己的,自己就是祖先) 查询:(我们是不是同一祖先) 路径压缩:(每 ...

  2. 最小生成树——Kruskal与Prim算法

    最小生成树——Kruskal与Prim算法 序: 首先: 啥是最小生成树??? 咳咳... 如图: 在一个有n个点的无向连通图中,选取n-1条边使得这个图变成一棵树.这就叫“生成树”.(如下图) 每个 ...

  3. 【转】最小生成树——Kruskal算法

    [转]最小生成树--Kruskal算法 标签(空格分隔): 算法 本文是转载,原文在最小生成树-Prim算法和Kruskal算法,因为复试的时候只用到Kruskal算法即可,故这里不再涉及Prim算法 ...

  4. 最小生成树 kruskal算法 codevs 1638 修复公路

    1638 修复公路  时间限制: 1 s  空间限制: 256000 KB  题目等级 : 钻石 Diamond 题解       题目描述 Description A地区在地震过后,连接所有村庄的公 ...

  5. 最小生成树——kruskal算法

    kruskal和prim都是解决最小生成树问题,都是选取最小边,但kruskal是通过对所有边按从小到大的顺序排过一次序之后,配合并查集实现的.我们取出一条边,判断如果它的始点和终点属于同一棵树,那么 ...

  6. 贪心算法-最小生成树Kruskal算法和Prim算法

    Kruskal算法: 不断地选择未被选中的边中权重最轻且不会形成环的一条. 简单的理解: 不停地循环,每一次都寻找两个顶点,这两个顶点不在同一个真子集里,且边上的权值最小. 把找到的这两个顶点联合起来 ...

  7. 最小生成树---Kruskal/Prime算法

    1.Kruskal算法 图的存贮采用边集数组或邻接矩阵,权值相等的边在数组中排列次序可任意,边较多的不很实用,浪费时间,适合稀疏图.      方法:将图中边按其权值由小到大的次序顺序选取,若选边后不 ...

  8. 【BZOJ-2177】曼哈顿最小生成树 Kruskal + 树状数组

    2177: 曼哈顿最小生成树 Time Limit: 10 Sec  Memory Limit: 259 MBSubmit: 190  Solved: 77[Submit][Status][Discu ...

  9. 最小生成树Kruskal算法(邻接矩阵和邻接表)

    最小生成树,克鲁斯卡尔算法. 算法简述: 将每个顶点看成一个图. 在所有图中找权值最小的边.将这条边的两个图连成一个图, 重复上一步.直到只剩一个图. 注:将abcdef每个顶点看成一个图.将最小权值 ...

随机推荐

  1. Java 并发:Executor

    异常捕获 以前使用executor的时候,为了记录任务线程的异常退出会使用ThreadFactory来设置线程的UncaughtExceptionHandler,但是按照书上的验证发现,采用execu ...

  2. POJ P2104 K-th Number

    You are working for Macrohard company in data structures department. After failing your previous tas ...

  3. MAVLink Onboard Integration Tutorial

    MAVLink Onboard Integration Tutorial MAVLink is a header-only library, which means that you don't ha ...

  4. Codeforces Round #417 C. Sagheer and Nubian Market

    C. Sagheer and Nubian Market time limit per test  2 seconds memory limit per test  256 megabytes   O ...

  5. 解决Spring框架下中文乱码的问题

    在使用了Spring框架下回发现很多表单交互的地方会发生乱码,而且写到数据库中也是乱码,这其实还是字符编码的问题,在我们还在用自己写的servlet的时候,直接在request和response加上字 ...

  6. 哪个HTML5内建对象用于在画布上绘制?()

    哪个HTML5内建对象用于在画布上绘制?() getContent getContext getGraphics getCanvas 我的理解: A.C.D不存在HTML5,,js方法中 HTML 5 ...

  7. net 4.0+EF6+Sqlite 使用,安装,打包

    开发 1.因为EF不支持Codefirst,开始可以使用SQL来进行开发. 部署安装 2.然后可以找到SQL转Sqlite工具(http://www.cnblogs.com/walkingp/arch ...

  8. mysql 的增删改查

    数据库的基本流程就是先看你的数据库中的库都是哪些:show databases; 然后再进入相应的库进行操作  :  use+进入的库/表 切换路径 查看这个库内的所有的表: show tabales ...

  9. aspnetcore 认证相关类简要说明三

    今天我们再来了解一个很重要的接口IAuthenticationService的实现类AuthenticationService: public class AuthenticationService ...

  10. MSDN版、OEM版、RTM版、VOL版等的区别

    我们常常听说操作系统的MSDN版.OEM版.RTM版.VOL版等等,它们到底是什么意思,有什么不同呢? (一)MSDN (Microsoft Developer Network)版MSDN软件是微软公 ...