使用union all 遇到的问题（俩条sql语句行数的和 不等于union all 后的 行数的和 ！）；遗留问题 怎么找到 相差的呐俩条数据 ？

 create table buyer as
 SELECT b.id AS bankid
   FROM v_product_deal_main m, base_member b
  WHERE b.id = m.BUYERID
    AND m.DEALDATE <= to_date('', 'yyyymmdd')
    AND m.STATE = 9
    AND b.state = 0;
 ---441947
 --seller方
  create table seller as SELECT * FROM seller ;
 create table seller as
 SELECT b.id AS bankid
   FROM v_product_deal_main m, base_member b
  WHERE b.id = m.sellerid
    AND m.DEALDATE <= to_date('', 'yyyymmdd')
    AND m.STATE = 9
    AND b.state = 0;

 create TABLE ttt as
 SELECT aa,bankid
 FROM (SELECT 1 aa,
         m.BUYERID AS bankid
 FROM v_product_deal_main m, base_member b
 WHERE b.id = m.BUYERID
 AND m.DEALDATE <= to_date('', 'yyyymmdd')
 AND m.STATE = 9
 AND b.state = 0
 UNION ALL
 SELECT 2 AS aa,
         m.sellerID AS bankid
 FROM v_product_deal_main m, base_member b
 WHERE b.id = m.sellerid
 AND m.DEALDATE <= to_date('', 'yyyymmdd')
 AND m.STATE = 9
 AND b.state = 0);
 --从下面可以看到 seller 表中的行数+ buyer 表中的行数  < ttt表中的行数 ；
 SELECT COUNT(1)  FROM seller ;  --
 SELECT COUNT(1)  FROM buyer ;   --
 SELECT COUNT(1)   FROM ttt ;   ---883894
 -- bankid=1 在buyer表中出现的次数 15191 + （seller表中出现的次数）11457= （ttt 表中出现的次数）30382 ;（seller + buyer）= 26648
 --4378 +5859  =8756 10237 --bankid =2 出现的次数
 SELECT 4378 +5859 FROM dual ;
 SELECT  b.bankid ,COUNT(b.bankid)  FROM buyer b GROUP BY b.bankid  ORDER BY b.bankid ;
 SELECT  s.bankid ,COUNT(s.bankid)  FROM seller s GROUP BY s.bankid ORDER BY s.bankid ;
 SELECT t.bankid ,COUNT(t.bankid)  FROM ttt t  GROUP BY t.bankid  ORDER BY t.bankid  

 SELECT SUM(DECODE(t.aa ,1 ,bankid,0 )) buyer ,
       SUM( DECODE(t.aa ,2 ,bankid,0 )) seller
  FROM ttt t ;

 SELECT SUM(DECODE(t.aa ,1 ,1,0 )) buyer ,
       SUM( DECODE(t.aa ,2 ,1,0 )) seller
  FROM ttt t ;

 --
 SELECT bankid, count(1) from ttt
 where aa=2
 MINUS
 --
 Select bankid ,Count(1) From seller ;

 SELECT bankid from ttt
 where aa=2
 MINUS
 --
 Select bankid  From seller ;
 SELECT COUNT(1) from ttt

 -------------------------------
 --1765  --441947
 select bankid,count(1) from ttt
 where aa=2
 group by bankid
 order by bankid ;

 --1465  --441945
 Select bankid,Count(1) From seller
 group by bankid
 order by bankid
 ;

  SELECT t.bankid FROM ttt t WHERE t.aa =1  

  SELECT t.bankid FROM ttt t WHERE t.aa =2  

 SELECT SUM(NVL(BUYERID, 0) + NVL(SELLERID, 0))
   FROM (SELECT (SELECT 1
                   FROM BASE_MEMBER B
                  WHERE B.ID = M.BUYERID
                    AND B.STATE = 0) AS BUYERID,
                (SELECT 1
                   FROM BASE_MEMBER B
                  WHERE B.ID = M.SELLERID
                    AND B.STATE = 0) AS SELLERID
           FROM V_PRODUCT_DEAL_MAIN M
          WHERE M.DEALDATE <= TO_DATE('', 'yyyymmdd')
            AND M.STATE = 9)

1.遗留问题 怎么找到 相差的呐俩条数据  ？

2. 问题到底出在哪里 ？