A C

Problem Description

Are you excited when you see the title "AC" ? If the answer is YES , AC it ;

You must learn these two combination formulas in
the school . If you have forgotten it , see the picture.

Now I will give you n and m ,
and your task is to calculate the answer .

 

Input

In the first line , there is a integer T indicates the
number of test cases.
Then T cases follows in the T lines.
Each case
contains a character 'A' or 'C', two integers represent n and m.
(1<=n,m<=10)

 

Output

For each case , if the character is 'A' , calculate
A(m,n),and if the character is 'C' , calculate C(m,n).
And print the answer
in a single line.

 

Sample Input

2

A 10 10

C 4 2

 

Sample Output

3628800

6

 

 #include <stdio.h>

 int jieCheng(int number);

 int main(){
     int T;
     char c;
     int n;
     int m;
     int n_jieCheng;
     int m_jieCheng;
     int n_m_jieCheng;
     int result;

     scanf("%d",&T);

     while(T--){
         getchar();

         scanf("%c%d%d",&c,&n,&m);

         n_jieCheng=jieCheng(n);
         m_jieCheng=jieCheng(m);
         n_m_jieCheng=jieCheng(n-m);

         if(c=='A')
             result=n_jieCheng/n_m_jieCheng;

         else
             result=n_jieCheng/(m_jieCheng*n_m_jieCheng);

         printf("%d\n",result);
     }
     return ;
 }

 int jieCheng(int number){
     int result;
     int i;

     result=;

     for(i=;i<=number;i++)
         result*=i;

     return result;
 }