You are climbing a stair case. It takes n steps to reach to the top.

Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

代码如下(方法一:超时):

 public class Solution {
public int climbStairs(int n) {
if(n==1||n==2||n==3)
return n; return climbStairs(n-1)+climbStairs(n-2);
}
}

方法二:AC

 public class Solution {
public int climbStairs(int n) {
if(n==1||n==2)
return n; int num1=1,num2=2,sum=0;
for(int i=3;i<=n;i++)
{ sum=num1+num2;
num1=num2;
num2=sum;
}
return sum;
}
}

70. Climbing Stairs的更多相关文章

  1. 42. leetcode 70. Climbing Stairs

    70. Climbing Stairs You are climbing a stair case. It takes n steps to reach to the top. Each time y ...

  2. Leetcode#70. Climbing Stairs(爬楼梯)

    题目描述 假设你正在爬楼梯.需要 n 阶你才能到达楼顶. 每次你可以爬 1 或 2 个台阶.你有多少种不同的方法可以爬到楼顶呢? 注意:给定 n 是一个正整数. 示例 1: 输入: 2 输出: 2 解 ...

  3. 377. Combination Sum IV 70. Climbing Stairs

    back function (return number) remember the structure class Solution { int res = 0; //List<List< ...

  4. LN : leetcode 70 Climbing Stairs

    lc 70 Climbing Stairs 70 Climbing Stairs You are climbing a stair case. It takes n steps to reach to ...

  5. Leetcode之70. Climbing Stairs Easy

    Leetcode 70 Climbing Stairs Easy https://leetcode.com/problems/climbing-stairs/ You are climbing a s ...

  6. 刷题70. Climbing Stairs

    一.题目说明 题目70. Climbing Stairs,爬台阶(楼梯),一次可以爬1.2个台阶,n层的台阶有几种爬法.难度是Easy! 二.我的解答 类似的题目做过,问题就变得非常简单.首先用递归方 ...

  7. LeetCode练题——70. Climbing Stairs

    1.题目 70. Climbing Stairs——Easy You are climbing a stair case. It takes n steps to reach to the top. ...

  8. [LeetCode] 70. Climbing Stairs 爬楼梯问题

    You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb ...

  9. leetCode 70.Climbing Stairs (爬楼梯) 解题思路和方法

    Climbing Stairs  You are climbing a stair case. It takes n steps to reach to the top. Each time you ...

  10. [LeetCode] 70. Climbing Stairs 爬楼梯

    You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb ...

随机推荐

  1. select2去除搜索框

    $("#type_select").select2({ minimumResultsForSearch: -1 });

  2. javascript photo http://www.cnblogs.com/5ishare/tag/javascript/

  3. 开通了cnblogs

    受够了百度空间,换个地方,或许会更好. 以后有机会会将百度空间你的文章搬过来的.

  4. 神奇的NOIP模拟赛 T2 LGTB 学分块

    LGTB 学分块 LGTB 最近在学分块,但是他太菜了,分的块数量太多他就混乱了,所以只能分成3 块今天他得到了一个数组,他突然也想把它分块,他想知道,把这个数组分成3 块,块可以为空.假设3 块各自 ...

  5. TStringList 的Sorted属性

    1 .设置 sorted := true; 2.添加数据 add('3');add('4');add('1'); showmessage(commatext);// 1,3,4 3.再修改Sorted ...

  6. bzoj 2820 YY的GCD 莫比乌斯反演

    题目大意: 给定N, M,求1<=x<=N, 1<=y<=M且gcd(x, y)为质数的(x, y)有多少对 这里就抄一下别人的推断过程了 后面这个g(x) 算的方法就是在线性 ...

  7. io函数

    io函数一般分为两大类: 系统(不带缓存)调用: 如read.write.open 标准(带缓存)调用: fread.fwrite.fopen 上面说的带缓存/不带缓存是针对用户态的,内核态本身都是带 ...

  8. Program C--二分

    My birthday is coming up and traditionally I’m serving pie. Not just one pie, no, I have a number N ...

  9. 使用siege进行Web压力测试

    因为最近公司线上node项目出一些不稳定的情况,考虑在这方面能不能做进一步的优化,既然要做优化首先要知道问题出在哪里? 因为暂无法定位是node层问题还是api层出现问题,由于在开发环境小并发量程序运 ...

  10. 使用plsql连接别人的oracle(转)

    文章来源:http://www.linuxidc.com/Linux/2013-04/82738.htm oracle服务有时候我们觉得太大,所以我们只需要在本机上装一个oracle客户端和plsql ...