Count On Me

歌手:Bruno Mars

所属专辑:It´s Better If You Don´t Understand

If you ever find yourself stuck in the middle of the sea

如果你深陷汪洋之中迷失了自己

I'll sail the world to find you

我就航遍世界直到找到你的足迹

If you ever find yourself lost in the dark and you can't see

如果你迷失在黑暗之中孤苦无依

I'll be the light to guide you

那我就变成光芒给你温暖指引

Find out what we're made of

要知道你是怎样一个自己

When we are called to help our friends in need

知道何时能帮到朋友 当他处在水深火热里

You can count on me like 1 2 3

你数1 2 3 我就能让你依靠

I'll be there

在你身边给你怀抱

And I know when I need it I can count on you like 4 3 2

而我数4 3 2 我知道当我需要

And you'll be there

你也会在我身边给我微笑

Cause that's what friends are supposed to do oh yeah

这就是朋友之间所能做到的刚刚好

Wooooh Wooooh

Wooooh Wooooh

yeah Yeah

Yeah Yeah

If you toss and you turn and you just can't fall asleep

如果你辗转反侧不能入睡

I'll sing a song

我就用歌声作陪

beside you

哄你入睡

And if you ever forget how much you really mean to me

要是你对你在我心中的重要性有所遗忘或怀疑

Everyday I will

我会每天向你证明

remind you

让你记起

Ohh

Find out what we're made of

要知道你是一个怎样的自己

When we are called to help our friends in need

知道何时能帮到朋友 当他处在水深火热里

You can count on me like 1 2 3

你数1 2 3 我的肩膀给你

I'll be there

无论如何我陪着你

And I know when I need it I can count on you like 4 3 2

而我数4 3 2 我知道当我需要

And you'll be there

你也会在我身边给我微笑

Cause that's what friends are supposed to do oh yeah

这就是朋友之间所能做到的刚刚好

Wooooh Wooooh

Wooooh Wooooh

Yeah Yeah

Yeah Yeah

You'll always have my shoulder when you cry

当你脆弱哭泣 我的肩膀永远等待着你

I'll never let go

不离不弃

Never say goodbye

不会离去

You can count on me like 1 2 3

你数1 2 3 我的肩膀给你

I'll be there

无论如何我陪着你

And I know when I need it I can count on you like 4 3 2

而我数4 3 2 我知道当我需要

And you'll be there

你也会在我身边给我微笑

Cause that's what friends are supposed to do oh yeah

这就是朋友之间所能做到的刚刚好

Wooooh Wooooh

Wooooh Wooooh

you can count on me cos' I can count on you

你依靠着我 我依靠着你

English Voice of << Count on me >>的更多相关文章

  1. English Voice of <<Something just like this>>

    歌名:something just like this演唱:Chris Martin 词:Andrew Taggart,Chris Martin 曲:Andrew Taggart,Chris Mart ...

  2. English Voice of <<Way Back Into Love>>

    I have been living with a shadow overhead我一直生活在阴影中I have been sleeping with a cloud above my bed睡梦中床 ...

  3. English Voice of <<City of stars>>

    City of stars 星光之城啊 Are you shining just for me? 你是否只愿为我闪耀 City of stars 星光之城啊 There's so much that ...

  4. English Voice of <<Just Give Me A Reason>>

    Right from the start, you were a thief,打从一开始,你就是个偷心贼You stole my heart and你偷走了我的心I your willing vict ...

  5. English Voice of <<Bye Bye Bye>>

    Bye Bye Bye - Lovestoned When i see you, looking back at me 当我看到你回首看我时 Watching this eye still 彼此凝视 ...

  6. English Voice of <<Beautiful now>>

    Beautiful Now  -Zedd & Jon Bellion I see what you're wearing, there's nothing beneath it 我看见了你身着 ...

  7. English Voice of <<Dream it passible>>

    Dream It Possible(梦想成为可能) - DelaceyI will run I will climb I will soar.我奔跑,我攀爬 我要飞翔.I'm undefeated我所 ...

  8. English Voice of << Last Christmas >>

    Last Christmas填 词:乔治·迈克尔谱 曲:乔治·迈克尔编 曲:乔治·迈克尔歌词:Last Christmas I gave you my heart去年的圣诞节,我把心给了你But th ...

  9. English Voice of <<if were a boy >>

    <if i were a boy>中英文歌词: If I were a boy 如果我是个男孩 Even just for a day 就算只是一天 I' roll out of bed ...

随机推荐

  1. Python中的对象行为与特殊方法(二)类型检查与抽象基类

    类型检查 创建类的实例时,该实例的类型为类本身: class Foo(object): pass f = Foo() 要测试实例是否属于某个类,可以使用type()内置函数: >>> ...

  2. topcoder srm 702 div1 -3

    1.给定一个$n*m$的矩阵,里面的数字是1到$n*m$的一个排列.一个$n*m$矩阵$A$对应一个$n*m$ 的01字符串,字符串的位置$i*m+j$为1当且仅当$A_{i,j}=i*m+j+1$. ...

  3. Linux使用——Linux命令——CentOS7防火墙使用

    注意:设置防火墙需要使用具有root权限的用户进入: CentOS 7.0默认使用的是firewall作为防火墙: CentOS 7.0使用systemctl来管理服务和程序,包括了service和c ...

  4. uniGUI试用笔记(二)

    前几天做的demo今天启动后,浏览器打开页面后死活不显示窗体,找了半天原因才发现是360浏览器启动了兼容模式,改成极速模式后就正常了.有点晕.... 今天简单测试了TUniGUIServerModul ...

  5. selinux权限问题【转】

    本文转载自:https://blog.csdn.net/u011386173/article/details/83339770 版权声明:本文为博主原创文章,未经博主允许不得转载. https://b ...

  6. Git 命令收集

    目录 1.清理恢复 2.回滚,reset与revert的区别 3.merge,rebase,cherry-pick区别 4.删除不存在对应远程分支的本地分支 5.git pull,git push 报 ...

  7. Python, pandas: how to sort dataframe by index// Merge two dataframes by index

    pd.concat([df1, df2], axis=1) df.sort_index(inplace=True) https://stackoverflow.com/questions/404680 ...

  8. java 之 音乐播放代码

    //需求:通过代码播放音乐 //1.读取文件 //2.将音乐文件放到播放代码中 //3.播放 public static void main(String[] args) throws Malform ...

  9. 题解——洛谷P2734 游戏A Game 题解(区间DP)

    题面 题目背景 有如下一个双人游戏:N(2 <= N <= 100)个正整数的序列放在一个游戏平台上,游戏由玩家1开始,两人轮流从序列的任意一端取一个数,取数后该数字被去掉并累加到本玩家的 ...

  10. 强化学习策略梯度方法之: REINFORCE 算法(从原理到代码实现)

    强化学习策略梯度方法之: REINFORCE 算法 (从原理到代码实现) 2018-04-01  15:15:42   最近在看policy gradient algorithm, 其中一种比较经典的 ...