LeetCode(36)- Implement Stack using Queues
题目:
Implement the following operations of a stack using queues.
push(x) -- Push element x onto stack.
pop() -- Removes the element on top of the stack.
top() -- Get the top element.
empty() -- Return whether the stack is empty.
Notes:
You must use only standard operations of a queue -- which means only push to back, peek/pop from front, size, and is empty operations are valid.
Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
Update (2015-06-11):
The class name of the Java function had been updated to MyStack instead of Stack.
思路:
- 题意是用队列数据结构来实现栈,要求只能使用Queue的基本函数,包括poll,isEmprty等
- 用两个队列pre和next来实现,pop()操作是把一个非空队列复制到另一个空队列,最后一个不复制,每次判断哪个非空
- push(int x)的实现:先判断哪个队列非空,然后添加x,isEmpty()是两个队列都为空的时候
-
代码:
import java.util.LinkedList;
import java.util.Queue;
class MyStack {
Queue<Integer> pre = new LinkedList<Integer>();
Queue<Integer> next = new LinkedList<Integer>();
// Push element x onto stack.
public void push(int x) {
if(next != null){
next.add(x);
}else{
pre.add(x);
}
}
// Removes the element on top of the stack.
public void pop() {
if(!next.isEmpty()){
while(!next.isEmpty()){
int a = next.poll();
if(!next.isEmpty()){
pre.add(a);
}
}
}else{
while(!pre.isEmpty()){
int b = pre.poll();
if(!pre.isEmpty()){
next.add(b);
}
}
}
}
// Get the top element.
public int top() {
if(!next.isEmpty()){
while(!next.isEmpty()){
int c = next.poll();
pre.add(c);
if(next.isEmpty()){
return c;
}
}
}else{
while(!pre.isEmpty()){
int d = pre.poll();
next.add(d);
if(pre.isEmpty()){
return d;
}
}
}
return 0;
}
public boolean empty() {
if(next.isEmpty() && pre.isEmpty()){
return true;
}else{
return false;
}
}
}
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