LeetCode 225 Implement Stack using Queues 用队列实现栈
1、两个队列实现,始终保持一个队列为空即可
class MyStack {
public:
/** Initialize your data structure here. */
MyStack() {
}
/** Push element x onto stack. */
void push(int x) {
if(que1.empty())
{
que1.push(x);
while(!que2.empty())
{
int val=que2.front();
que2.pop();
que1.push(val);
}
}
else
{
que2.push(x);
while(!que1.empty())
{
int val=que1.front();
que1.pop();
que2.push(val);
}
}
}
/** Removes the element on top of the stack and returns that element. */
int pop() {
if(que1.empty())
{
int val=que2.front();
que2.pop();
return val;
}
if(que2.empty())
{
int val=que1.front();
que1.pop();
return val;
}
}
/** Get the top element. */
int top() {
if(que1.empty())
return que2.front();
if(que2.empty())
return que1.front();
}
/** Returns whether the stack is empty. */
bool empty() {
return que1.empty()&&que2.empty();
}
private:
queue<int> que1;
queue<int> que2;
};
/**
* Your MyStack object will be instantiated and called as such:
* MyStack obj = new MyStack();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.top();
* bool param_4 = obj.empty();
*/
2、一个队列实现栈
class MyStack {
public:
/** Initialize your data structure here. */
MyStack() {
}
/** Push element x onto stack. */
void push(int x) {
que.push(x);
for(int i=;i<que.size()-;++i)
{
que.push(que.front());
que.pop();
}
}
/** Removes the element on top of the stack and returns that element. */
int pop() {
int val=que.front();
que.pop();
return val;
}
/** Get the top element. */
int top() {
return que.front();
}
/** Returns whether the stack is empty. */
bool empty() {
return que.empty();
}
private:
queue<int> que;
};
/**
* Your MyStack object will be instantiated and called as such:
* MyStack obj = new MyStack();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.top();
* bool param_4 = obj.empty();
*/
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