What I would like to do is to display a single form that lets the user:

  • Enter a document title (from Document model)
  • Select one of their user_defined_code choices from a drop down list (populated by the UserDefinedCode model)
  • Type in a unique_code (stored in the Code model)

I'm not sure how to go about displaying the fields for the foreign key relationships in a form. I know in a view you can use document.code_set (for example) to access the related objects for the current document object, but I'm not sure how to apply this to a ModelForm.

My model:

class UserDefinedCode(models.Model):
name = models.CharField(max_length=8)
owner = models.ForeignKey(User) class Code(models.Model):
user_defined_code = models.ForeignKey(UserDefinedCode)
unique_code = models.CharField(max_length=15) class Document(models.Model):
title = models.CharField(blank=True, null=True, max_length=200)
code = models.ForeignKey(Code)
active = models.BooleanField(default=True)

My ModelForm

class DocumentForm(ModelForm):
class Meta:
model = Document
asked Apr 18 '11 at 20:42
Ben S

5891720

In regards to displaying a foreign key field in a form you can use the forms.ModelChoiceField and pass it a queryset.

so, forms.py:

class DocumentForm(forms.ModelForm):
class Meta:
model = Document def __init__(self, *args, **kwargs):
user = kwargs.pop('user','')
super(DocumentForm, self).__init__(*args, **kwargs)
self.fields['user_defined_code']=forms.ModelChoiceField(queryset=UserDefinedCode.objects.filter(owner=user))

views.py:

def someview(request):
if request.method=='post':
form=DocumentForm(request.POST, user=request.user)
if form.is_valid():
selected_user_defined_code = form.cleaned_data.get('user_defined_code')
#do stuff here
else:
form=DocumentForm(user=request.user) context = { 'form':form, } return render_to_response('sometemplate.html', context,
context_instance=RequestContext(request))

from your question:

I know in a view you can use document.code_set (for example) to access the related objects for the current document object, but I'm not sure how to apply this to a ModelForm.

Actually, your Document objects wouldn't have a .code_set since the FK relationship is defined in your documents model. It is defining a many to one relationship to Code, which means there can be many Document objects per Code object, not the other way around. Your Code objects would have a .document_set. What you can do from the document object is access which Code it is related to using document.code.

edit: I think this will do what you are looking for. (untested)

forms.py:

class DocumentForm(forms.ModelForm):
class Meta:
model = Document
exclude = ('code',) def __init__(self, *args, **kwargs):
user = kwargs.pop('user','')
super(DocumentForm, self).__init__(*args, **kwargs)
self.fields['user_defined_code']=forms.ModelChoiceField(queryset=UserDefinedCode.objects.filter(owner=user))
self.fields['unique_code']=forms.CharField(max_length=15)

views.py:

def someview(request):
if request.method=='post':
form=DocumentForm(request.POST, user=request.user)
if form.is_valid():
uniquecode = form.cleaned_data.get('unique_code')
user_defined_code = form.cleaned_data.get('user_defined_code')
doc_code = Code(user_defined_code=user_defined_code, code=uniquecode)
doc_code.save()
doc = form.save(commit=False)
doc.code = doc_code
doc.save()
return HttpResponse('success')
else:
form=DocumentForm(user=request.user) context = { 'form':form, } return render_to_response('sometemplate.html', context,
context_instance=RequestContext(request))

actually you probably want to use get_or_create when creating your Code object instead of this.

doc_code = Code(user_defined_code=user_defined_code, code=uniquecode)

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