【leetcode_easy】598. Range Addition II
problem
题意:
第一感觉就是最小的行和列的乘积即是最后结果。
class Solution {
public:
int maxCount(int m, int n, vector<vector<int>>& ops) {
for(auto op : ops)
{
m = min(m, op[]);
n = min(n, op[]);
}
return m*n;
}
};
参考
1. Leetcode_easy_598. Range Addition II;
2. Grandyang;
完
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