php 如何获取一个json文件

    function showupversion(){
        #获取平台类型
        $type='android';
        #读取文件的路径
        $url="D:/WWW/gm_lequ/gm_lequ";
        $file_name="update.ini";
        $path=$url.'/'.$type.'/'.$file_name;
        #判断文件的路径是否存在 判断目录是否存在我们用is_dir就OK了。
        if(file_exists($path)){
            #读取php.ini json格式的文件
            $content=json_decode(file_get_contents($path),true);
            #获取所有的文件
            $file_name_array=$this->showGetFileName($type,$url);
            $this->Tmpl['option']="";
            foreach ($file_name_array as $v){
                if($content['upVer']==$v){
                    $this->Tmpl['option'].="<option  selected='selected'>{$v}</option>";
                }else{
                    $this->Tmpl['option'].="<option >{$v}</option>";
                }

            }
            $this->Tmpl['mainVer']=$content['mainVer'];
            $this->Tmpl['upVer']=$content['upVer'];
            $this->Tmpl['upTips']=$content['upTips'];
            $this->Tmpl['assetPath']=$content['assetPath'];
            $this->Tmpl['newUpiniPath']=$content['newUpiniPath'];
            $this->Tmpl['appStore']=$content['appStore'];
            $this->Tmpl['forceUpdateVersion']=$content['forceUpdateVersion'];
        }else{
            $this->PromptMsg = "文件不存在！";
        }
        $this->display();
    }