Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output NONE instead.

Sample Input 1:

4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100

Sample Output 1:

Mike CS991301
Mary EE990830
Joe Math990112

Sample Input 2:

2
Jean AA980920 60
Ann CS01 80
90 95

Sample Output 2:

NONE
 #include <iostream>
#include <string>
#include <algorithm>
using namespace std;
struct Node
{
string name, id;
int grade;
};
int main()
{
int N, grade1, grade2;
cin >> N;
Node* data = new Node[N];
for (int i = ; i < N; ++i)
cin >> data[i].name >> data[i].id >> data[i].grade;
cin >> grade1 >> grade2;
sort(data, data + N, [](Node a, Node b) {return a.grade > b.grade; });
int flag = ;
for (int i = ; i < N; ++i)
{
if (data[i].grade < grade1)
break;
if (data[i].grade >= grade1 && data[i].grade <= grade2)
{
cout << data[i].name << " " << data[i].id << endl;
flag = ;
}
}
if (flag == )
cout << "NONE" << endl;
delete[]data;
return ;
}

PAT甲级——A1083 List Grades的更多相关文章

  1. PAT 甲级 1083 List Grades (25 分)

    1083 List Grades (25 分) Given a list of N student records with name, ID and grade. You are supposed ...

  2. PAT 甲级 1083 List Grades

    https://pintia.cn/problem-sets/994805342720868352/problems/994805383929905152 Given a list of N stud ...

  3. PAT甲级题解(慢慢刷中)

    博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6102219.html特别不喜欢那些随便转载别人的原创文章又不给 ...

  4. 【转载】【PAT】PAT甲级题型分类整理

    最短路径 Emergency (25)-PAT甲级真题(Dijkstra算法) Public Bike Management (30)-PAT甲级真题(Dijkstra + DFS) Travel P ...

  5. PAT甲级题分类汇编——排序

    本文为PAT甲级分类汇编系列文章. 排序题,就是以排序算法为主的题.纯排序,用 std::sort 就能解决的那种,20分都算不上,只能放在乙级,甲级的排序题要么是排序的规则复杂,要么是排完序还要做点 ...

  6. PAT甲级题分类汇编——序言

    今天开个坑,分类整理PAT甲级题目(https://pintia.cn/problem-sets/994805342720868352/problems/type/7)中1051~1100部分.语言是 ...

  7. PAT甲级题解分类byZlc

    专题一  字符串处理 A1001 Format(20) #include<cstdio> int main () { ]; int a,b,sum; scanf ("%d %d& ...

  8. 1080 Graduate Admission——PAT甲级真题

    1080 Graduate Admission--PAT甲级练习题 It is said that in 2013, there were about 100 graduate schools rea ...

  9. PAT甲级:1036 Boys vs Girls (25分)

    PAT甲级:1036 Boys vs Girls (25分) 题干 This time you are asked to tell the difference between the lowest ...

随机推荐

  1. Spring REST(4)

    REST风格 /user/1    get请求  获取用户 /user/1 post请求   新增用户 /user/1 put请求     更新用户 /user/1 delete请求 删除用户 在Sp ...

  2. flask-Local源码流程解析

    flask中Local源码数据类型首先明确:源码中要构造的数据类型数是这样的: __storage__ = { 用线程或者协程的唯一标识为键: {stack:[ctx(session/request) ...

  3. Tomcat相关知识总结

    有关Tomcat的杂货店 一.修改端口号,并以IP访问 1.确保80端口没有程序占用.例如nginx等. 2.vi /tomcat/conf/server.xml 3.找到<Connector ...

  4. C#让两个长度相同的数组一一对应

    比如: string a[]={"x","y","z"} "} 用字典使其一一对应 Dictionary<string, s ...

  5. MAMP 安装 php 扩展

    1.官网下载所对应的php 版本http://php.net/get/php-5.3.29.tar.gz/from/a/mirror 2.解压 找到需要的扩展目录 例如我要的是shmopcd ~/Do ...

  6. Binary XML file line #23: Error inflating class android.widget.TextView

    分析一波,报错23行TextView的问题,但是检查了xml没有发现23行又TextView相关代码,就不应该继续纠结xml了,代码是通过R文件拿到xml资源的,你就应该怀疑是R文件的问题,R文件编译 ...

  7. Python 字符串_python 字符串截取_python 字符串替换_python 字符串连接

    Python 字符串_python 字符串截取_python 字符串替换_python 字符串连接 字符串是Python中最常用的数据类型.我们可以使用引号('或")来创建字符串. 创建字符 ...

  8. 关于python3字符串中引号格式的看法,‘’,“”

    关于字符串中引号格式的看法 在python3中,字符串统一使用: ' ' 或  " "     来表示,两者没有什么区别. 但是在使用的过程中,可以注意一下使用的方式,可以提高编程 ...

  9. range()函数在python3与python2中的区别

    range()函数在python3与python2中的区别 - CSDN博客 https://blog.csdn.net/weixin_37579123/article/details/8098038 ...

  10. C#winfrom listview 设置显示图片

    ListView控件有5种显示图片方式:LargeIcon(大图标),Detail(详细),SmallIcon(小图标),List(列表),Tile,常用前4种.  这里说一下设置方式:LargeIc ...