贪心-Wooden Sticks
先将火柴按照长度(或重量)优先排序,在不断遍历数组,找出其中重量(长度)递增子序列,并标记
(a) The setup time for the first wooden stick is 1 minute.
(b)
Right after processing a stick of length l and weight w , the machine
will need no setup time for a stick of length l' and weight w' if
l<=l' and w<=w'. Otherwise, it will need 1 minute for setup.
You
are to find the minimum setup time to process a given pile of n wooden
sticks. For example, if you have five sticks whose pairs of length and
weight are (4,9), (5,2), (2,1), (3,5), and (1,4), then the minimum setup
time should be 2 minutes since there is a sequence of pairs (1,4),
(3,5), (4,9), (2,1), (5,2).
input consists of T test cases. The number of test cases (T) is given
in the first line of the input file. Each test case consists of two
lines: The first line has an integer n , 1<=n<=5000, that
represents the number of wooden sticks in the test case, and the second
line contains n 2 positive integers l1, w1, l2, w2, ..., ln, wn, each of
magnitude at most 10000 , where li and wi are the length and weight of
the i th wooden stick, respectively. The 2n integers are delimited by
one or more spaces.
5
4 9 5 2 2 1 3 5 1 4
3
2 2 1 1 2 2
3
1 3 2 2 3 1
1
3
#include<iostream>
#include<algorithm>
using namespace std;
struct wood{
int l;
int w;
int flag;
}W[];
bool cmp(wood w1, wood w2){
if(w1.l<w2.l )
return true;
else if(w1.l==w2.l && w1.w<=w2.w)
return true;
return false;
}
int main()
{
int t,n;
cin>>t;
while(t--){
cin>>n;
for(int i=;i<n;i++){
cin>>W[i].l>>W[i].w;
W[i].flag=;
}
sort(W,W+n,cmp);
//for(int i=0;i<n;i++)
//cout<<W[i].l<<" "<<W[i].w<<endl;
int tw;
int result=;
for(int i=;i<n;i++){
if(W[i].flag)
continue;
tw=W[i].w;
W[i].flag=;
for(int j=;j<n;j++){
if(W[j].flag)
continue;
if(W[j].w>=tw){
tw=W[j].w;
W[j].flag=;
}
}
result++;
}
cout<<result<<endl;
}
return ;
}
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