leetcode之Ransom Note
题目描述:
Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false. Each letter in the magazine string can only be used once in your ransom note. Note:
You may assume that both strings contain only lowercase letters. canConstruct("a", "b") -> false
canConstruct("aa", "ab") -> false
canConstruct("aa", "aab") -> true
class Solution {
public:
bool canConstruct(string ransomNote, string magazine) {
/*第一种方法
if(ransomNote.size() > magazine.size()){
return false;
}
for(int i = 0; i<ransomNote.size() ;){
char ch = ransomNote[i];
std::size_t found = magazine.find(ch);
if(found != std::string::npos){
ransomNote.erase(i,1);
magazine.erase(found,1);
continue;
}
i++;
}
if(ransomNote.length() == 0)
return true;
else
return false;
}*//*第二种检测方法*/
int* arr = new int[];
for(int i=;i<;i++){
arr[i] = ;
}
for(int i=;i<magazine.length();i++)
{
char c = magazine[i];
arr[c-'a']++;
}
for(int i=;i<ransomNote.length();i++)
{
char c = ransomNote[i];
arr[c-'a']--;
if(arr[c-'a']<)
return false;
}
return true;
}
};
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