109. Convert Sorted List to Binary Search Tree (List; Divide-and-Conquer, dfs)
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode *sortedListToBST(ListNode *head) {
if(!head) return NULL;
int size = ;
ListNode * listNode = head->next;
while(listNode)
{
size++;
listNode = listNode->next;
}
TreeNode* root = new TreeNode();
binarySearch(head,size,root);
return root;
}
void binarySearch(ListNode *head,int size, TreeNode* treeNode) //二分法,对于Array,需要一头一尾两个指针;对于List需要头指针及size
{
if(size == )
{
treeNode->val = head->val;
return;
}
ListNode * listNode = head;
int mid = size>>;
int i;
for(i = ; i<mid;i++)
{
listNode = listNode ->next;
}
treeNode->val = listNode->next->val;
treeNode->left = new TreeNode(); //先申请好空间,再传递。否则在被调用函数中指针本身值的变化并不会影响调用者
binarySearch(head,mid,treeNode->left);
if(size>)
{
treeNode->right = new TreeNode();
binarySearch(listNode->next->next,size-mid-,treeNode->right);
}
}
};
也可以通过引用传递,这样就不需要先初始化。
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode *sortedListToBST(ListNode *head) {
if(!head) return NULL;
int size = ;
ListNode * listNode = head->next;
while(listNode)
{
size++;
listNode = listNode->next;
}
TreeNode* root = new TreeNode();
binarySearch(head,size,root);
return root;
}
void binarySearch(ListNode *head,int size, TreeNode* &treeNode) //按引用传递参数
{
if(size == )
{
treeNode=new TreeNode(head->val);
return;
}
ListNode * listNode = head;
int mid = size>>;
for(int i = ; i<mid;i++)
{
listNode = listNode ->next;
}
treeNode = new TreeNode (listNode->next->val); //在被调用处申请空间
binarySearch(head,mid,treeNode->left); //引用的是0x0000的地址
if(size>)
{
binarySearch(listNode->next->next,size-mid-,treeNode->right);
}
}
};
注意,NULL是一个宏定义
#define NULL 0
即NULL = (void*) 0
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