201. Segment Tree Build
最后更新
二刷
08-Jan-2017
一刷忘了什么时候做的,只是觉得这几个题挺好的,一步一步手动构建线段树,最终理解了这个数据结构,并且后面有利用的地方。
其实重要的3个东西题目已经提供了:
- left < right return null
- left == right return root
- (left, mid), (mid+1, right)
public class Solution {
public SegmentTreeNode build(int start, int end) {
if (start > end) return null;
SegmentTreeNode tempRoot = new SegmentTreeNode(start, end);
if (start == end) return tempRoot;
int mid = start + (end - start) / 2;
tempRoot.left = build(start, mid);
tempRoot.right = build(mid + 1, end);
return tempRoot;
}
}
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