CodeForces - 296A-Yaroslav and Permutations(思维)
Yaroslav has an array that consists of n integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would be distinct in a finite time.
Help Yaroslav.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of elements in the array. The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 1000) — the array elements.
Output
In the single line print "YES" (without the quotes) if Yaroslav can obtain the array he needs, and "NO" (without the quotes) otherwise.
Examples
Input
1
1
Output
YES
Input
3
1 1 2
Output
YES
Input
4
7 7 7 7
Output
NO
Note
In the first sample the initial array fits well.
In the second sample Yaroslav can get array: 1, 2, 1. He can swap the last and the second last elements to obtain it.
In the third sample Yarosav can't get the array he needs.
题解:去看是否出现次数最多的是否占n个数的一半以上
代码
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<iostream>
using namespace std;
int main()
{
int n;
cin>>n;
int a[105];
int vis[1005]={0};
memset(vis,0,sizeof(vis));
for(int t=0;t<n;t++)
{
scanf("%d",&a[t]);
vis[a[t]]++;
}
int maxn=0;
for(int t=1;t<=1000;t++)
{
if(vis[t]>=2)
{
if(vis[t]>maxn)
maxn=vis[t];
}
}
if(maxn<=(n+1)/2)
{
cout<<"YES"<<endl;
}
else
{
cout<<"NO"<<endl;
}
return 0;
}
CodeForces - 296A-Yaroslav and Permutations(思维)的更多相关文章
- Codeforce 296A - Yaroslav and Permutations
Yaroslav has an array that consists of n integers. In one second Yaroslav can swap two neighboring a ...
- CodeForces - 987E Petr and Permutations (思维+逆序对)
题意:初始有一个序列[1,2,...N],一次操作可以将任意两个位置的值互换,Petr做3*n次操作:Alxe做7*n+1次操作.给出最后生成的新序列,问是由谁操作得到的. 分析:一个序列的状态可以归 ...
- CodeForces - 427A (警察和罪犯 思维题)
Police Recruits Time Limit: 1000MS Memory Limit: 262144KB 64bit IO Format: %I64d & %I64u Sub ...
- Codeforces Round #337 Alphabet Permutations
E. Alphabet Permutations time limit per test: 1 second memory limit per test: 512 megabytes input: ...
- codeforces 341C Iahub and Permutations(组合数dp)
C. Iahub and Permutations time limit per test 1 second memory limit per test 256 megabytes input sta ...
- Codeforces 463D Gargari and Permutations
http://codeforces.com/problemset/problem/463/D 题意:给出k个排列,问这k个排列的最长公共子序列的长度. 思路:只考虑其中一个的dp:f[i]=max(f ...
- codeforces 340E Iahub and Permutations(错排or容斥)
转载请注明出处: http://www.cnblogs.com/fraud/ ——by fraud Iahub and Permutations Iahub is so happy ...
- codeforces 895B XK Segments 二分 思维
codeforces 895B XK Segments 题目大意: 寻找符合要求的\((i,j)\)对,有:\[a_i \le a_j \] 同时存在\(k\),且\(k\)能够被\(x\)整除,\( ...
- codeforces 893D Credit Card 贪心 思维
codeforces 893D Credit Card 题目大意: 有一张信用卡可以使用,每天白天都可以去给卡充钱.到了晚上,进入银行对卡的操作时间,操作有三种: 1.\(a_i>0\) 银行会 ...
- C. Nice Garland Codeforces Round #535 (Div. 3) 思维题
C. Nice Garland time limit per test 1 second memory limit per test 256 megabytes input standard inpu ...
随机推荐
- 城市旅游ppt模板
城市旅游ppt模板,城市,旅游,旅行,休闲. 下载:http://www.huiyi8.com/lvyoumuban/ppt/
- 延时加载 lazyload使用技巧
html <img class="lazy" src="images/src_unit.png" data-src="images/index/ ...
- 【boost】使用serialization库序列化子类
boost.serialization库是一个非常强大又易用的序列化库,用于对象的保存与持久化等. 使用base_object可以在序列化子类的同时也序列化父类,以此获得足够的信息来从文件或网络数据中 ...
- 国内镜像pip
建议非清华大学校内的使用这个镜像: http://e.pypi.python.org/simple(这也是一个http://pypi.v2ex.com/simple),清华校内的就使用这个:http: ...
- Codeforces 762C Two strings 字符串
Cpdeforces 762C 题目大意: 给定两个字符串a,b\((len \leq 10^5)\),让你去b中的一个连续的字段,使剩余的b串中的拼接起来的两个串是a穿的子序列.最大化这个字串的长度 ...
- POJ2182:Lost Cows
浅谈线段树和树状数组:https://www.cnblogs.com/AKMer/p/9946944.html 题目传送门:http://poj.org/problem?id=2182 线段树,倒着确 ...
- poco时间操作
Poco::DateTime Poco::Timespan Poco::Timestamp 时间操作 Poco::DateTime dt; //c++ 20才有 Calendar dt = dt + ...
- caffe template
http://www.cnblogs.com/ggjucheng/archive/2011/12/18/2292090.html
- [提高班] 2017 Summer Training Day1补题
题目地址:https://vjudge.net/contest/175939#overview A.数据范围是10^9,所以需要一个巧思路.对于一个数n,如何去判定比它的所有数是否是二进制形式.比n小 ...
- iframe父页面和子页面相互调用的方法
随着W3C一声令下,几年前使用非常频繁的frameset + frame已完成使命,光荣退伍.作为frameset的替代方案(姑且这么称吧),iframe的使用也多了起来.较frameset方案,if ...