PAT 1123 Is It a Complete AVL Tree
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child subtrees of any node differ by at most one; if at any time they differ by more than one, rebalancing is done to restore this property. Figures 1-4 illustrate the rotation rules.


Now given a sequence of insertions, you are supposed to output the level-order traversal sequence of the resulting AVL tree, and to tell if it is a complete binary tree.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive integer N (≤ 20). Then N distinct integer keys are given in the next line. All the numbers in a line are separated by a space.
Output Specification:
For each test case, insert the keys one by one into an initially empty AVL tree. Then first print in a line the level-order traversal sequence of the resulting AVL tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line. Then in the next line, print YES if the tree is complete, or NO if not.
Sample Input 1:
5
88 70 61 63 65
Sample Output 1:
70 63 88 61 65
YES
Sample Input 2:
8
88 70 61 96 120 90 65 68
Sample Output 2:
88 65 96 61 70 90 120 68
NO
#include<iostream>
#include<math.h>
#include<queue>
using namespace std;
struct node{
int value, depth;
node* l=NULL;
node* r=NULL;
node(int v): value(v), depth(0), l(NULL), r(NULL){
}
};
int getheight(node* root){
return root==NULL?0:max(getheight(root->l), getheight(root->r))+1;
}
node* RotationLL(node* root){
node* temp=root->l;
root->l=temp->r;
temp->r=root;
temp->depth=getheight(temp);
root->depth=getheight(root);
return temp;
}
node* RotationRR(node* root){
node* temp=root->r;
root->r=temp->l;
temp->l=root;
temp->depth=getheight(temp);
root->depth=getheight(root);
return temp;
}
node* RotationLR(node* root){
root->l=RotationRR(root->l);
return RotationLL(root);
}
node* RotationRL(node* root){
root->r=RotationLL(root->r);
return RotationRR(root);
}
node* insert(node* root, int val){
if(root==NULL){
root=new node(val);
return root;
}else if(val<root->value){
root->l=insert(root->l, val);
if(getheight(root->l)-getheight(root->r)==2)
if(val<root->l->value)
root=RotationLL(root);
else
root=RotationLR(root);
}else{
root->r=insert(root->r, val);
if(getheight(root->l)-getheight(root->r)==-2)
if(val<root->r->value)
root=RotationRL(root);
else
root=RotationRR(root);
}
root->depth=getheight(root);
return root;
}
int main(){
int n, flag=0, ans=0, first=0;
cin>>n;
node* root=NULL;
for(int i=0; i<n; i++){
int val;
cin>>val;
root=insert(root, val);
}
queue<node*> q;
q.push(root);
while(!q.empty()){
node* temp=q.front();
first++==0?cout<<temp->value:cout<<" "<<temp->value;
q.pop();
if(temp->l!=NULL){
q.push(temp->l);
flag==1?ans=1:ans=ans;
}
else
flag=1;
if(temp->r!=NULL){
q.push(temp->r);
flag==1?ans=1:ans=ans;
}
else
flag=1;
}
cout<<endl;
ans==1?cout<<"NO"<<endl:cout<<"YES"<<endl;
return 0;
}
PAT 1123 Is It a Complete AVL Tree的更多相关文章
- PAT 1123. Is It a Complete AVL Tree (30)
AVL树的插入,旋转. #include<map> #include<set> #include<ctime> #include<cmath> #inc ...
- PAT甲级1123. Is It a Complete AVL Tree
PAT甲级1123. Is It a Complete AVL Tree 题意: 在AVL树中,任何节点的两个子树的高度最多有一个;如果在任何时候它们不同于一个,则重新平衡来恢复此属性.图1-4说明了 ...
- 1123 Is It a Complete AVL Tree
1123 Is It a Complete AVL Tree(30 分) An AVL tree is a self-balancing binary search tree. In an AVL t ...
- PAT甲级——1123 Is It a Complete AVL Tree (完全AVL树的判断)
嫌排版乱的话可以移步我的CSDN:https://blog.csdn.net/weixin_44385565/article/details/89390802 An AVL tree is a sel ...
- PAT Advanced 1123 Is It a Complete AVL Tree (30) [AVL树]
题目 An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child ...
- 1123. Is It a Complete AVL Tree (30)
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...
- PAT A1123 Is It a Complete AVL Tree (30 分)——AVL平衡二叉树,完全二叉树
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...
- 1123 Is It a Complete AVL Tree(30 分)
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...
- PAT甲级1123 Is It a Complete AVL Tree【AVL树】
题目:https://pintia.cn/problem-sets/994805342720868352/problems/994805351302414336 题意: 给定n个树,依次插入一棵AVL ...
随机推荐
- Spark 二项逻辑回归__二分类
package Spark_MLlib import org.apache.spark.ml.Pipeline import org.apache.spark.ml.classification.{B ...
- P4244 [SHOI2008]仙人掌图 II
传送门 仙人掌直径,以前好像模拟赛的时候做到过一道基环树的直径,打了个很麻烦的然而还错了--今天才发现那就是这个的弱化版啊-- 如果是树的话用普通的dp即可,记\(f[u]\)表示\(u\)往下最长能 ...
- 分布式消息通信(ActiveMQ)
分布式消息通信(ActiveMQ) 应用场景 异步通信 应用解耦 流量削峰 # ActiveMQ安装 下载 http://activemq.apache.org/ 压缩包上传到Linux系统 apac ...
- Springboot 三种拦截Rest API的方法-过滤器、拦截器、切片
过滤器方式实现拦截(Filter) 通过继承Servlet的Filter类来实现拦截: @Component public class TimeFilter implements Filter { @ ...
- centos 安装sysbench
安装sysbench 下载并且解压 shell> wget https://github.com/akopytov/sysbench/archive/1.0.zip -O "sysbe ...
- jQuery学习笔记(5)-事件与事件对象
一.前言 主要讲解事件的绑定与触发 二.jQuery中添加事件 1.使用bind()方法绑定事件 <input id="btn" type="button" ...
- how to do a mass update in Laravel5 ( 在Laravel 5里面怎么做大量数据更新 )
Today, I had spent 3 hours to fix one problem, The old program has a bug, originally, when a user pr ...
- WordPress腾讯云存储搭建教程,完美解决
写在前面的话: 为什么会有今天的话题:WordPress+腾讯云存储? 因为博主不想使用七牛云,也不想使用又拍云,所以才有了今天的话题. 在使用腾讯云存储的过程中是很不顺利的,万幸的是现在终于完美融合 ...
- (9)string对象上的操作2
比较string对象的比较运算符 这种由string类定义的几种比较字符串的运算符能逐一比较string对象中的字符(对大小写敏感).
- Android开发——Snackbar使用详解
http://blog.csdn.net/qq_19431333/article/details/52862348