Robot Motion(imitate)
| Time Limit: 1000MS | Memory Limit: 10000K | |
| Total Submissions: 11065 | Accepted: 5378 |
Description
A robot has been programmed to follow the instructions in its path. Instructions for the next direction the robot is to move are laid down in a grid. The possible instructions are N north (up the page) S south (down the page) E east (to the right on the page) W west (to the left on the page)
For example, suppose the robot starts on the north (top) side of Grid 1 and starts south (down). The path the robot follows is shown. The robot goes through 10 instructions in the grid before leaving the grid.
Compare what happens in Grid 2: the robot goes through 3 instructions only once, and then starts a loop through 8 instructions, and never exits.
You are to write a program that determines how long it takes a robot to get out of the grid or how the robot loops around.
Input
Output
Sample Input
3 6 5
NEESWE
WWWESS
SNWWWW
4 5 1
SESWE
EESNW
NWEEN
EWSEN
0 0 0
Sample Output
10 step(s) to exit
3 step(s) before a loop of 8 step(s)
Source
#include<stdio.h>
#include<string.h>
#include<iostream>
using namespace std;
int row , col , o ;
char map[][] ;
int a[][] ;
int x , y ; void loop (char dir)
{
switch (dir)
{
case 'N' : printf ("%d step(s) before a loop of %d step(s)\n" , a[x][y] - , a[x + ][y] - a[x][y] + ) ; break ;
case 'E' : printf ("%d step(s) before a loop of %d step(s)\n" , a[x][y] - , a[x][y - ] - a[x][y] + ) ; break ;
case 'S' : printf ("%d step(s) before a loop of %d step(s)\n" , a[x][y] - , a[x - ][y] - a[x][y] + ) ; break ;
case 'W' : printf ("%d step(s) before a loop of %d step(s)\n" , a[x][y] - , a[x][y + ] - a[x][y] + ) ; break ;
}
}
void solve ()
{
x = , y = o ;
bool flag = ;
char temp ;
a[x][y] = ;
while (x >= && x <= row && y >= && y <= col) {
switch (map[x][y])
{
case 'N' : x-- ; if (a[x][y]) flag = ;
if (!flag)
a[x][y] = a[x + ][y] + ;
else
temp = 'N' ; break ;
case 'E' : y++ ; if (a[x][y]) flag = ;
if (!flag)
a[x][y] = a[x][y - ] + ;
else
temp = 'E' ; break ;
case 'S' : x++ ; if (a[x][y]) flag = ;
if (!flag)
a[x][y] = a[x - ][y] + ;
else
temp = 'S' ; break ;
case 'W' : y-- ; if (a[x][y]) flag = ;
if (!flag)
a[x][y] = a[x][y + ] + ;
else
temp = 'W' ; break ;
}
if (flag) {
loop (temp) ;
break ;
}
}
if (!flag)
printf ("%d step(s) to exit\n" , a[x][y] - ) ;
}
int main ()
{
// freopen ("a.txt" , "r" , stdin) ;
while (~ scanf ("%d%d%d" , &row , &col , &o)) {
if (row == && col == && o == )
break ;
memset (a , , sizeof(a)) ;
for (int i = ; i <= row ; i++)
for (int j = ; j <= col ; j++)
cin >> map[i][j] ; solve () ;
/* for (int i = 1 ; i <= row ; i++) {
for (int j = 1 ; j <= col ; j++) {
printf ("%d " , a[i][j]) ;
}
puts ("") ;
}
printf ("\n\n") ;*/
}
return ;
}
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