CodeForces Round #521 (Div.3) D. Cutting Out
http://codeforces.com/contest/1077/problem/D
You are given an array ss consisting of nn integers.
You have to find any array tt of length kk such that you can cut out maximum number of copies of array tt from array ss.
Cutting out the copy of tt means that for each element titi of array tt you have to find titi in ss and remove it from ss. If for some titi you cannot find such element in ss, then you cannot cut out one more copy of tt. The both arrays can contain duplicate elements.
For example, if s=[1,2,3,2,4,3,1]s=[1,2,3,2,4,3,1] and k=3k=3 then one of the possible answers is t=[1,2,3]t=[1,2,3]. This array tt can be cut out 22 times.
- To cut out the first copy of tt you can use the elements [1,2––,3,2,4,3––,1––][1,2_,3,2,4,3_,1_] (use the highlighted elements). After cutting out the first copy of tt the array ss can look like [1,3,2,4][1,3,2,4].
- To cut out the second copy of tt you can use the elements [1––,3––,2––,4][1_,3_,2_,4]. After cutting out the second copy of tt the array ss will be [4][4].
Your task is to find such array tt that you can cut out the copy of tt from ss maximum number of times. If there are multiple answers, you may choose any of them.
The first line of the input contains two integers nn and kk (1≤k≤n≤2⋅1051≤k≤n≤2⋅105) — the number of elements in ss and the desired number of elements in tt, respectively.
The second line of the input contains exactly nn integers s1,s2,…,sns1,s2,…,sn (1≤si≤2⋅1051≤si≤2⋅105).
Print kk integers — the elements of array tt such that you can cut out maximum possible number of copies of this array from ss. If there are multiple answers, print any of them. The required array tt can contain duplicate elements. All the elements of tt (t1,t2,…,tkt1,t2,…,tk) should satisfy the following condition: 1≤ti≤2⋅1051≤ti≤2⋅105.
7 3
1 2 3 2 4 3 1
1 2 3
10 4
1 3 1 3 10 3 7 7 12 3
7 3 1 3
15 2
1 2 1 1 1 2 1 1 2 1 2 1 1 1 1
1 1
The first example is described in the problem statement.
In the second example the only answer is [7,3,1,3][7,3,1,3] and any its permutations. It can be shown that you cannot choose any other array such that the maximum number of copies you can cut out would be equal to 22.
In the third example the array tt can be cut out 55 times.
代码:
#include <bits/stdc++.h>
using namespace std; const int maxn = 2e5 + 10;
int n, k;
int a[maxn];
int times[maxn]; bool can(int x) {
int cnt = 0;
for(int i = 1; i < maxn; i ++)
cnt += times[i] / x;
if(cnt >= k) return true;
return false;
} int main() {
memset(times, 0, sizeof(times));
scanf("%d%d", &n, &k);
for(int i = 1; i <= n; i ++) {
scanf("%d", &a[i]);
times[a[i]] ++;
} int l = 1, r = n, mid, maxx = 1;
while(l <= r) {
mid = (r - l) / 2 + l;
if(can(mid)) maxx = mid, l = mid + 1;
else r = mid - 1;
} int ans[maxn];
int rec = 0;
for(int i = 1; i < maxn; i ++) {
if(times[i] >= maxx)
for(int j = 1; j <= times[i] / maxx; j ++) {
ans[rec ++] = i;
if(rec == k) break;
}
} for(int i = 0; i < k; i ++) {
printf("%d", ans[i]);
printf("%s", i != k - 1 ? " " : "\n");
}
return 0;
}
今天是丧气的一天
CodeForces Round #521 (Div.3) D. Cutting Out的更多相关文章
- Codeforces Round #521 (Div. 3) D. Cutting Out 【二分+排序】
任意门:http://codeforces.com/contest/1077/problem/D D. Cutting Out time limit per test 3 seconds memory ...
- Codeforces Round #521 (Div. 3) E. Thematic Contests(思维)
Codeforces Round #521 (Div. 3) E. Thematic Contests 题目传送门 题意: 现在有n个题目,每种题目有自己的类型要举办一次考试,考试的原则是每天只有一 ...
- CodeForces Round #521 (Div.3) E. Thematic Contests
http://codeforces.com/contest/1077/problem/E output standard output Polycarp has prepared nn competi ...
- Codeforces Round #521 (Div. 3) F1. Pictures with Kittens (easy version)
F1. Pictures with Kittens (easy version) 题目链接:https://codeforces.com/contest/1077/problem/F1 题意: 给出n ...
- CodeForces Round #521 (Div.3) B. Disturbed People
http://codeforces.com/contest/1077/problem/B There is a house with nn flats situated on the main str ...
- CodeForces Round #521 (Div.3) A. Frog Jumping
http://codeforces.com/contest/1077/problem/A A frog is currently at the point 00 on a coordinate axi ...
- Codeforces Round #521 (Div.3)题解
A过水,不讲 题解 CF1077B [Disturbed People] 这题就是个显而易见的贪心可是我考场上差点没想出来 显然把一户被打扰的人家的右边人家的灯关掉肯定比把左边的灯关掉 从左到右扫一遍 ...
- Codeforces Round #521 (Div. 3)
B 题过的有些牵强,浪费了很多时间,这种题一定想好思路和边界条件再打,争取一发过. D 题最开始读错题,后面最后发现可以重复感觉就没法做了,现在想来,数据量大,但是数据范围小枚举不行,二分还是可以的 ...
- Codeforces Round #521 Div. 3 玩耍记
A:签到. #include<iostream> #include<cstdio> #include<cmath> #include<cstdlib> ...
随机推荐
- .net mvc里AutoMapper更为便捷的使用方法
前言:AutoMapper的下载安装我就不多说了,网上百度一大堆.今天我就说说它的更为简单的使用,什么叫更为简单呢?按照一般的使用方法,我们首先建DTO,然后建每个对应的Profile,然后还要把每个 ...
- php第一节(入门语法、数据类型)
<?php /** * 变量命名用 $ 符 * 变量名称的命名规范 * 1.变量名称以$标示 * 2.变量名称只能以字母和下划线开头 * 3.变量的名称只能包含字母.下划线.数字 * 4.变量名 ...
- 在C++中如何实现文件的读写
一.ASCII 输出为了使用下面的方法, 你必须包含头文件<fstream.h>(译者注:在标准C++中,已经使用<fstream>取代< fstream.h>,所 ...
- CentOS7下PHP7.2安装redis扩展
1.安装phpize(存在忽略) yum install php-devel 2.下载扩展源码包,直接用wget,一般放在 /usr/local/src wget https://github.com ...
- 【TCP/IP实现磁盘资源的分享-----ISCSI(互联网最小应用程序接口)】
Iscsi server: 首先把多块磁盘合并为RAID5,便于后期iscis client访问以及服务端的管理 安装 targted服务端包,以及targtedcli创建iscsi TCP/IP共享 ...
- Windows和Linux系统下,虚拟环境安装的全面说明和详细步骤
虚拟环境的创建和使用 用途: 1.在同一台电脑安装同一个包的不同版本 2.记录项目所用的所有的包的版本,方便部署. 如何使用: 1.创建虚拟环境 mkvirtualenv 虚拟环境名 -p pyt ...
- python更新mysql数据
>>>cur.execute("update users set username=%s where id=2",("mypython")) ...
- while,格式化输出
1. while循环: while 条件: 代码块(循环体) num=1 while num<=5: print(num) num+=1 break:结束循环;停止当前本层循环 continue ...
- R语言学习笔记(十四):零碎知识点(41-45)
41--ls( ) ls()可以用来列出现存的所有对象. pattern是一个具名参数,可以列出所有名称中含有字符串"s"的对象. > ls() [1] "s&qu ...
- gp更新来的太快
意外总是会发生 添加一个判断function的分支,过滤掉function,其实也考虑再进一步去分析它的作用,稍后再议. 更新一下 var gnp = { get: function(url) { r ...