http://codeforces.com/contest/1077/problem/E

output

standard output

Polycarp has prepared nn competitive programming problems. The topic of the ii-th problem is aiai, and some problems' topics may coincide.

Polycarp has to host several thematic contests. All problems in each contest should have the same topic, and all contests should have pairwise distinct topics. He may not use all the problems. It is possible that there are no contests for some topics.

Polycarp wants to host competitions on consecutive days, one contest per day. Polycarp wants to host a set of contests in such a way that:

  • number of problems in each contest is exactly twice as much as in the previous contest (one day ago), the first contest can contain arbitrary number of problems;
  • the total number of problems in all the contests should be maximized.

Your task is to calculate the maximum number of problems in the set of thematic contests. Note, that you should not maximize the number of contests.

Input

The first line of the input contains one integer nn (1≤n≤2⋅1051≤n≤2⋅105) — the number of problems Polycarp has prepared.

The second line of the input contains nn integers a1,a2,…,ana1,a2,…,an (1≤ai≤1091≤ai≤109) where aiai is the topic of the ii-th problem.

Output

Print one integer — the maximum number of problems in the set of thematic contests.

Examples
input

Copy
18
2 1 2 10 2 10 10 2 2 1 10 10 10 10 1 1 10 10
output

Copy
14
input

Copy
10
6 6 6 3 6 1000000000 3 3 6 6
output

Copy
9
input

Copy
3
1337 1337 1337
output

Copy
3
Note

In the first example the optimal sequence of contests is: 22 problems of the topic 11, 44 problems of the topic 22, 88 problems of the topic 1010.

In the second example the optimal sequence of contests is: 33 problems of the topic 33, 66 problems of the topic 66.

In the third example you can take all the problems with the topic 13371337 (the number of such problems is 33 so the answer is 33) and host a single contest.

代码:

    #include <bits/stdc++.h>
using namespace std; const int maxn = 2e5 + 10;
const int N = 1e6 + 5;
int n;
int a[N]; int main() {
scanf("%d", &n);
int cnt = 0;
map<int, int> mp;
for(int i = 1; i <= n; i ++) {
int x;
scanf("%d", &x);
if(!mp[x]) {
cnt ++;
mp[x] = cnt;
}
a[mp[x]] ++;
}
sort(a + 1, a + 1 + cnt);
int ans = 0; for(int i = 1; i <= n; i ++) {
int st = 1;
int m = 0;
for(int k = i; k <= n; k *= 2) {
int pos = lower_bound(a + st, a + 1 + cnt, k) - a;
if(pos == cnt + 1) break;
m += k;
st = pos + 1;
}
ans = max(ans, m);
}
printf("%d\n", ans);
return 0;
}

  

CodeForces Round #521 (Div.3) E. Thematic Contests的更多相关文章

  1. Codeforces Round #521 (Div. 3) E. Thematic Contests(思维)

    Codeforces Round #521 (Div. 3)  E. Thematic Contests 题目传送门 题意: 现在有n个题目,每种题目有自己的类型要举办一次考试,考试的原则是每天只有一 ...

  2. Codeforces Round #521 (Div. 3) E. Thematic Contests (离散化,二分)

    题意:有\(n\)个话题,每次都必须选取不同的话题,且话题数必须是上次的两倍,第一次的话题数可以任意,问最多能选取多少话题数. 题解:我们首先用桶来记录不同话题的数量,因为只要求话题的数量,与话题是多 ...

  3. Codeforces Round #521 (Div. 3) D. Cutting Out 【二分+排序】

    任意门:http://codeforces.com/contest/1077/problem/D D. Cutting Out time limit per test 3 seconds memory ...

  4. CodeForces Round #521 (Div.3) D. Cutting Out

    http://codeforces.com/contest/1077/problem/D You are given an array ss consisting of nn integers. Yo ...

  5. Codeforces Round #521 (Div. 3) F1. Pictures with Kittens (easy version)

    F1. Pictures with Kittens (easy version) 题目链接:https://codeforces.com/contest/1077/problem/F1 题意: 给出n ...

  6. CodeForces Round #521 (Div.3) B. Disturbed People

    http://codeforces.com/contest/1077/problem/B There is a house with nn flats situated on the main str ...

  7. CodeForces Round #521 (Div.3) A. Frog Jumping

    http://codeforces.com/contest/1077/problem/A A frog is currently at the point 00 on a coordinate axi ...

  8. Codeforces Round #521 (Div. 3)

    B 题过的有些牵强,浪费了很多时间,这种题一定想好思路和边界条件再打,争取一发过.  D 题最开始读错题,后面最后发现可以重复感觉就没法做了,现在想来,数据量大,但是数据范围小枚举不行,二分还是可以的 ...

  9. Codeforces Round #521 Div. 3 玩耍记

    A:签到. #include<iostream> #include<cstdio> #include<cmath> #include<cstdlib> ...

随机推荐

  1. 开发一个c#的数据库连接池

    c#操作数据库是一个经典,用习惯了以后真感觉不错,很简单的.现在很多关系数据库都支持c#.c#的ADO.NET规范都遵守. 对于一般的设置,ADO.NET都放在数据库连接字符串上.比如池化,连接超时等 ...

  2. 【Nowcoder 上海五校赛】1 + 2 = 3?(斐波那契规律)

    题目描述 小Y在研究数字的时候,发现了一个神奇的等式方程,他屈指算了一下有很多正整数x满足这个等式,比如1和2,现在问题来了,他想知道从小到大第N个满足这个等式的正整数,请你用程序帮他计算一下. (表 ...

  3. Percona-Tookit工具包之pt-show-grants

      Preface       User privileges regulation is pretty important in DBAs routine job.As we all know,it ...

  4. Shell 脚本进程并发&进程数控制

    Shell 都以串行的方式自上而下执行命令,不适用需要大量作业的场景. 学习此篇shell脚本进程并发,能够大大提高工作效率~ 通过wait 和 & 后台符号 可以实现并行,但无法控制进程数. ...

  5. 【nat---basic,napt,easy ip】

    display nat :显示nat 信息 debugging nat :对nat进行调试 reset nat session:擦除nat连接配置 basic-nat:公网->私网(一对一) n ...

  6. Python的Bottle框架中实现最基本的get和post的方法的教程

    这篇文章主要介绍了Python的Bottle框架中实现最基本的get和post的方法的教程,Bottle框架在Python开发者中的人气很高,需要的朋友可以参考下 1.GET方式: # -*- cod ...

  7. lnmp配置支持thinkphp和nginx路由url重写

    ThinkPHP3.2.3项目放到lnmp环境之后只能打开首页,或者通过传参方式打开控制器,否则就一直显示404页面.搞了一上午,终于解决了 step1: 修改php.ini cgi.fix_path ...

  8. python应用:爬虫实例(静态网页)

    爬取起点中文网某本小说实例: # -*-coding:utf8-*- import requests import urllib import urllib2 from bs4 import Beau ...

  9. 数据分析处理库Pandas——时间

    时间戳 向后推的时间戳 备注:五天后的时间. 指定日期和时间 时间的Series结构 按要求显示时间(开始时间,时间间隔,时间个数) 转换为时间格式,并设置时间列为索引列 方法一 方法二 筛选显示 方 ...

  10. javaWeb总结

    url传值时:如out.println("<td><a href = 'delete.jsp?user=" + user + "'>删除</ ...