1058 A+B in Hogwarts (20 分)
If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut(Galleon is an integer in [0,107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28
分析:水题,注意可能溢出,用long long保险点
/**
* Copyright(c)
* All rights reserved.
* Author : Mered1th
* Date : 2019-02-24-01.29.25
* Description : A1058
*/
#include<cstdio>
#include<cstring>
#include<iostream>
#include<cmath>
#include<algorithm>
#include<string>
#include<unordered_set>
#include<map>
#include<vector>
#include<set>
using namespace std;
int main(){
#ifdef ONLINE_JUDGE
#else
freopen("1.txt", "r", stdin);
#endif
int b,c;
int e,f;
,i=;
;
scanf("%lld.%d.%d %lld.%d.%d",&a,&b,&c,&d,&e,&f);
i=f+c;
){
i-=;
h++;
}
h=h+b+e;
){
h-=;
g++;
}
g=g+a+d;
printf("%lld.%d.%d",g,h,i);
;
}
1058 A+B in Hogwarts (20 分)的更多相关文章
- PAT 甲级 1058 A+B in Hogwarts (20 分) (简单题)
1058 A+B in Hogwarts (20 分) If you are a fan of Harry Potter, you would know the world of magic ha ...
- 1058 A+B in Hogwarts (20分)
1058 A+B in Hogwarts (20分) 题目: If you are a fan of Harry Potter, you would know the world of magic h ...
- PAT Advanced 1058 A+B in Hogwarts (20 分)
If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- a ...
- 【PAT甲级】1058 A+B in Hogwarts (20 分)
题意: 输入两组,每组三个非负整数A,B,C(A<=1e7,B<17,C<29),输出相加的和.(类似个位上29进制,十位上17进制运算) AAAAAccepted code: #d ...
- 1058 A+B in Hogwarts (20分)(水)
If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- a ...
- 1058 A+B in Hogwarts (20)
#include <stdio.h> int main() { ]; ]; ],&ans1[],&ans1[],&ans2[],&ans2[],&a ...
- PAT (Advanced Level) 1058. A+B in Hogwarts (20)
简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #in ...
- PAT甲题题解-1058. A+B in Hogwarts (20)-大水题
无语,这种水题还出,浪费时间,但又不得不A... #include <iostream> #include <cstdio> #include <algorithm> ...
- pat 1058 A+B in Hogwarts(20 分)
1058 A+B in Hogwarts(20 分) If you are a fan of Harry Potter, you would know the world of magic has i ...
随机推荐
- 【LeetCode 234_链表】Palindrome Linked List
ListNode* ReverseList(ListNode *p) { if (p == NULL || p->next == NULL) return p; ListNode *pre = ...
- 团队项目之UML图设计
团队 学号 姓名 本次作业博客链接 031602428 苏路明(组长) https://www.cnblogs.com/Sulumer/p/9822854.html 031602401 陈瀚霖 htt ...
- SQL SERVER 压缩数据库日志文件
ALTER DATABASE DBNAME SET RECOVERY SIMPLE --设置为简单恢复模式 GO DBCC SHRINKFILE (DBNAME_log, 1) GO ALTER DA ...
- CentOS 下安装和使用 Docker
引言: 在服务器开发过程中,环境部署无疑是及其繁琐的事情,特别是当项目数量和规模达到一定级别之后,在一台新的机器上部署项目环境无疑是极其漫长而痛苦的,那么什么办法能够实现我们的目标:在开发环境的一次配 ...
- Vue 2.0 学习路线
「 Vue很难学吗 」 对于我这种从0.x版本就开始体验 vuejs 的人来说,当然不算难,那时候没各种脚手架和复杂搭配,仅仅是一个mvvm的解决方案库而已,解决了jq带来的繁琐操作dom痛点,所以就 ...
- OpenCV-bwLabel-实现图像连通组件标记与分析
OpenCV实现图像连通组件标记与分析- matlab bwLabel; code: #include <opencv2/opencv.hpp> #include <iostream ...
- NVIDIA GeForce GTX 960 设备是不可移动的,无法弹出
系统环境 系统:win7_x64; matlab版本:matlab2017b试用版: GPU:NVIDIA GeForce GTX 960: 问题描述: 第一次使用深度学习实现代码,运行的是matla ...
- C++ 备忘录 (1)
取模: 1. 转载自:http://ceeji.net/blog/mod-in-real/ 背景 最近在一道 Java 习题中,看到这样的一道题: What is the output when th ...
- 关于FormData及其用法
XMLHttpRequest Level 2添加了一个新的接口FormData.利用FormData对象,我们可以通过JavaScript用一些键值对来模拟一系列表单控件,我们还可以使用XMLHttp ...
- HPU 1166: 阶乘问题(一)
1166: 阶乘问题(一) [数学] 时间限制: 1 Sec 内存限制: 128 MB提交: 58 解决: 24 统计 题目描述 小H对阶乘!很感兴趣.现在他想知道N!N!的位数,由于NN太大了,所以 ...