小白书上经典DFS题目。

1. 递归实现

// from: https://www.cnblogs.com/huaszjh/p/4686092.html

#include <stdio.h>
#include <string.h>
#define maxn 105
unsigned char data[maxn][maxn];
int m, n, vis[maxn][maxn]; void dfs(int x, int y, int ans) {
if (x < 0 || x >= m || y < 0 || y >= n) return; //出界
if (vis[x][y] > 0 || data[x][y] == '*') return; //非'@'或已经访问
vis[x][y] = ans; //连通分量编号
for (int k = -1; k <= 1; k++) {
for (int t = -1; t <= 1; t++) {
if (k != 0 || t != 0) { //自身格子不需要重复判断
dfs(x + k, y + t, ans);
}
}
}
} #define DEBUG
int main() {
#ifdef DEBUG
const char* input_txt_pth = "F:/zhangzhuo/debug/OJ/UVA-572.txt";
freopen(input_txt_pth, "r", stdin);
#endif int i, j;
while (scanf("%d %d", &m, &n) && m &&n) {
int count = 0; //连通块
memset(vis, 0, sizeof(vis));
for (i = 0; i < m; i++) {
scanf("%s", data[i]);
}
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
//对未访问且为`@`的格子进行访问
if (vis[i][j] == 0 && data[i][j] == '@') {
dfs(i, j, ++count);
}
}
}
printf("%d\n", count);
#ifdef DEBUG
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
printf("%3d", vis[i][j]);
}
printf("\n");
}
printf("\n");
#endif
}
return 0;
}

2. 递归dfs函数用迭代实现

每个节点的dfs递归调用,改成用stack容器就地计算,是个while循环,本质上还是栈,但是避免了递归时嵌套产生的开销造成的潜在风险。

C++的stack、vector容器用起来比较顺手。另外就是把坐标简单封装为一个结构体。

#include <stdio.h>
#include <string.h>
#include <iostream>
#include <stack>
#include <vector> typedef struct Coord {
char x, y;
} Coord; #define DEBUG
int main() {
#ifdef DEBUG
const char* input_txt_pth = "F:/zhangzhuo/debug/OJ/UVA-572.txt";
freopen(input_txt_pth, "r", stdin);
#endif int m, n, i, j; #define maxn 105
unsigned char data[maxn][maxn];
int vis[maxn][maxn]; while (scanf("%d %d", &m, &n) && m &&n) {
int count = 0; //连通块
memset(vis, 0, sizeof(vis));
for (i = 0; i < m; i++) {
scanf("%s", data[i]);
} std::stack<Coord> stk;
Coord cd;
std::vector<Coord>offset;
cd.x = -1; cd.y = -1; offset.push_back(cd);
cd.x = -1; cd.y = 0; offset.push_back(cd);
cd.x = -1; cd.y = 1; offset.push_back(cd);
cd.x = 0; cd.y = -1; offset.push_back(cd);
cd.x = 0; cd.y = 1; offset.push_back(cd);
cd.x = 1; cd.y = -1; offset.push_back(cd);
cd.x = 1; cd.y = 0; offset.push_back(cd);
cd.x = 1; cd.y = 1; offset.push_back(cd); for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
cd.x = i; cd.y = j;
if (vis[cd.x][cd.y] > 0 || data[cd.x][cd.y] != '@') continue;
count++; stk.push(cd);
while (!stk.empty()) {
cd = stk.top();
stk.pop();
vis[cd.x][cd.y] = count; Coord tmp;
for (size_t k = 0; k < offset.size(); k++) {
tmp.x = cd.x + offset[k].x;
tmp.y = cd.y + offset[k].y;
if (tmp.x < 0 || tmp.x >= m || tmp.y < 0 || tmp.y >= n) continue;
if (vis[tmp.x][tmp.y] > 0 || data[tmp.x][tmp.y] != '@') continue;
stk.push(tmp);
}
}
}
} printf("%d\n", count); #ifdef DEBUG
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
printf("%3d", vis[i][j]);
}
printf("\n");
}
printf("\n");
#endif
}
return 0;
}

3.纯C,DFS非递归,自定义栈ADT,函数指针

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <string.h> typedef struct Coord Coord;
struct Coord {
char x, y;
}; typedef struct CoordOffset CoordOffset;
struct CoordOffset {
size_t num;
int* x;
int* y;
}; typedef struct ListNode ListNode;
struct ListNode
{
ListNode* next;
void* data;
}; typedef struct Stack Stack; struct Stack {
ListNode* head;
size_t len;
void(*push_coord)(Stack* stk, Coord* coord);
void (*pop_coord)(Stack* stk);
void (*top_coord)(Stack* stk, Coord* coord);
}; void stack_push_coord(Stack* stk, Coord* coord) {
ListNode* new_head = (ListNode*)malloc(sizeof(ListNode));
/* new_head->data = coord; */
new_head->data = (Coord*)malloc(sizeof(ListNode));
memcpy(new_head->data, coord, sizeof(Coord)); new_head->next = stk->head;
stk->head = new_head;
stk->len++;
} void stack_pop_coord(Stack* stk) {
if (stk->head != NULL) {
ListNode* new_head = stk->head->next;
free(stk->head->data);
free(stk->head);
stk->head = new_head;
stk->len--;
}
} void stack_top_coord(Stack* stk, Coord* coord) {
if (stk->head != NULL) {
Coord* t_coord = (Coord*)(stk->head->data);
coord->x = t_coord->x;
coord->y = t_coord->y;
}
} void make_stack(Stack** _stk) {
Stack* stk = (Stack*)malloc(sizeof(Stack));
stk->head = NULL;
stk->len = 0;
stk->push_coord = stack_push_coord;
stk->pop_coord = stack_pop_coord;
stk->top_coord = stack_top_coord; /* write back */
*_stk = stk;
} void free_stack(Stack* stk) {
ListNode* cur = stk->head;
ListNode* temp;
size_t i;
for (i = 0; i < stk->len; i++) {
temp = cur->next;
free(cur->data);
free(cur);
cur = temp;
}
free(stk);
stk = NULL;
} void make_8coord_offset(CoordOffset** _offset) {
CoordOffset* offset = (CoordOffset*)malloc(sizeof(CoordOffset));
offset->num = 8;
offset->x = (int*)malloc(sizeof(int)*offset->num);
offset->y = (int*)malloc(sizeof(int)*offset->num); offset->x[0] = -1; offset->y[0] = -1;
offset->x[1] = -1; offset->y[1] = 0;
offset->x[2] = -1; offset->y[2] = 1;
offset->x[3] = 0; offset->y[3] = -1;
offset->x[4] = 0; offset->y[4] = 1;
offset->x[5] = 1; offset->y[5] = -1;
offset->x[6] = 1; offset->y[6] = 0;
offset->x[7] = 1; offset->y[7] = 1; /* write back */
*_offset = offset;
} void free_coord_offset(CoordOffset* offset) {
if (offset) {
if (offset->x) {
free(offset->x);
offset->x = NULL;
}
if (offset->y) {
free(offset->y);
offset->y = NULL;
}
free(offset);
offset = NULL;
}
} /* #define DEBUG */
int main() {
#ifdef DEBUG
const char* input_txt_pth = "F:/zhangzhuo/debug/OJ/UVA-572.txt";
freopen(input_txt_pth, "r", stdin);
#endif int m, n, i, j;
size_t k; #define maxn 105
unsigned char data[maxn][maxn];
int vis[maxn][maxn]; /* here we use 8 neighbours */
CoordOffset* offset = NULL;
make_8coord_offset(&offset); while (scanf("%d %d", &m, &n) && m &&n) {
int count = 0; /* 连通块 */
memset(vis, 0, sizeof(vis));
for (i = 0; i < m; i++) {
scanf("%s", data[i]);
} /* std::stack<Coord> stk; */
Stack* stk;
make_stack(&stk); Coord cd; for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
cd.x = i; cd.y = j;
if (vis[cd.x][cd.y] > 0 || data[cd.x][cd.y] != '@') continue;
count++; /* stk.push(cd); */
stack_push_coord(stk, &cd);
/* while (!stk.empty()) { */
while(stk->len!=0) {
/* cd = stk.top(); */
/* stack_top_coord(stk, &cd); */
stk->top_coord(stk, &cd);
/* stk.pop(); */
/* stack_pop_coord(stk); */
stk->pop_coord(stk); vis[cd.x][cd.y] = count; Coord tmp;
for (k = 0; k < offset->num; k++) {
tmp.x = cd.x + offset->x[k];
tmp.y = cd.y + offset->y[k];
if (tmp.x < 0 || tmp.x >= m || tmp.y < 0 || tmp.y >= n) continue;
if (vis[tmp.x][tmp.y] > 0 || data[tmp.x][tmp.y] != '@') continue;
/* stk.push(tmp); */
/* stack_push_coord(stk, &tmp); */
stk->push_coord(stk, &tmp);
}
}
}
}
free_stack(stk); printf("%d\n", count); #ifdef DEBUG
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
printf("%3d", vis[i][j]);
}
printf("\n");
}
printf("\n");
#endif
} free_coord_offset(offset);
return 0;
}

4.DFS+并查集实现

#include <stdio.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h> int fa[10500];
int m, n, cnt, vis[105][105];
char mp[105][105];
int find(int x) {
if (fa[x] == x) return x;
fa[x] = find(fa[x]);
return fa[x];
} void merge(int x, int y) {
int fx = find(x);
int fy = find(y);
if (fx == fy) return;
fa[fx] = fy;
} void dfs(int x, int y, int fx, int fy) {
if (x < 0 || x >= m || y < 0 || y >= n) return;
if (vis[x][y] || mp[x][y] == '*') return;
vis[x][y] = 1;
/* cout<<"x || y || fx || fy : "<<x<<" || "<<y<<" || "<<fx<<" || "<<fy<<endl; */
if (fx != -1) {
merge(x*m + y, fx*m + fy);
}
int i, j;
for (i = -1; i < 2; i++) {
for (j = -1; j < 2; j++) {
if (!i && !j) continue;
dfs(x + i, y + j, x, y);
}
}
} /* #define LOCAL */
int main() {
#ifdef LOCAL
const char* input_txt = "F:/zhangzhuo/debug/OJ/UVA-572.txt";
freopen(input_txt, "r", stdin);
#endif
int i, j;
while (scanf("%d%d", &m, &n) == 2 && m && n) {
cnt = 0;
memset(vis, 0, sizeof(vis));
for (i = 0; i < m; i++) {
scanf("%s", mp[i]);
}
for (i = 0; i < 10500; i++) {
fa[i] = i;
}
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
if (!vis[i][j] && mp[i][j] == '@') {
dfs(i, j, -1, -1);
cnt++;
}
}
}
printf("%d\n", cnt); #ifdef LOCAL
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
printf("%3d", vis[i][j]);
}
printf("\n");
}
printf("\n");
#endif }
return 0;
}

5.DFS+并查集+不使用全局变量+简单封装为结构体

修改自 UVA572 (并查集解法) 。这种写法有点问题:已经用了dfs,dfs里用并查集多此一举,如果用并查集就不应该递归调用dfs。

#include <stdio.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h> typedef struct FSU_Node {
int p; /* parent id */
int rank;
int vis; /* group(connected component) id */
} FSU_Node; /*
get node's root id
@param x: node id
@param nodes: all nodes in map
*/
int fus_find(int x, FSU_Node* nodes) {
if (nodes[x].p == x) return x; nodes[x].p = fus_find(nodes[x].p, nodes);
return nodes[x].p;
} /*
merge two node groups
@param a: a node from one node group
@param b: a node from another node group
*/
void fus_union(int a, int b, FSU_Node* nodes)
{
int ra = fus_find(a, nodes); /* ra: root id of a */
int rb = fus_find(b, nodes); /* rb: root id of b */
if (ra == rb) {
return;
} if (nodes[ra].rank > nodes[rb].rank)
{
nodes[rb].p = ra;
}
else {
if (nodes[ra].rank == nodes[rb].rank)
{
nodes[rb].rank++;
}
nodes[ra].p = rb;
}
} typedef struct ImageSize {
int w, h;
} ImageSize; typedef struct Coord {
int row, col;
} Coord; void fus_dfs(const Coord* pt, const Coord* f_pt, FSU_Node* nodes, ImageSize* sz, unsigned char* mp) {
int row = pt->row;
int col = pt->col; int f_row = f_pt->row;
int f_col = f_pt->col; if (row < 0 || row >= sz->h || col < 0 || col >= sz->w) return; int id = row * sz->w + col;
int fid = f_row * sz->w + f_col; /* if (vis[id] || mp[id] == '*') return; */
if (nodes[id].vis || mp[id] == '*') return;
/* vis[id] = 1; */
nodes[id].vis = 1; if (f_row != -1) {
fus_union(id, fid, nodes);
} int i, j;
Coord neighbor;
for (i = -1; i < 2; i++) {
for (j = -1; j < 2; j++) {
if (!i && !j) continue;
neighbor.row = row + i;
neighbor.col = col + j;
fus_dfs(&neighbor, pt, nodes, sz, mp);
}
}
} /*#define LOCAL*/
int main() {
#ifdef LOCAL
const char* input_txt = "F:/zhangzhuo/debug/OJ/UVA-572.txt";
freopen(input_txt, "r", stdin);
#endif #define MAXN 105
int m, n, cnt, i, j; /* int vis[MAXN*MAXN]; */
unsigned char mp[MAXN*MAXN];
FSU_Node nodes[MAXN*MAXN]; int idx; while (scanf("%d%d", &m, &n) == 2 && m && n) {
cnt = 0;
/* memset(vis, 0, sizeof(int)*MAXN*MAXN); */
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
idx = i * n + j;
scanf(" %c", &mp[idx]);
/* printf("! %c !", mp[idx]); */
}
}
for (i = 0; i < m*n; i++) {
nodes[i].p = idx;
nodes[i].rank = 1;
nodes[i].vis = 0;
} ImageSize im_sz;
im_sz.h = m;
im_sz.w = n;
Coord pt;
Coord f_pt;
f_pt.row = -1;
f_pt.col = -1; for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
idx = i * n + j;
/* if (!vis[idx] && mp[idx] == '@') { */
if (!nodes[idx].vis && mp[idx] == '@') {
/* dfs(i, j, -1, -1); */
pt.row = i;
pt.col = j;
/* fus_dfs(&pt, &f_pt, nodes, &im_sz, vis, mp); */
fus_dfs(&pt, &f_pt, nodes, &im_sz, mp);
cnt++;
}
}
}
printf("%d\n", cnt); #ifdef LOCAL
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
idx = i * m + j;
/* printf("%3d", vis[idx]); */
printf("%c", mp[idx]);
}
printf("\n");
}
printf("\n");
#endif
} return 0;
}

这里的教训是,如果在双重for循环中使用变量x、y来表示坐标,容易把2维度坐标->1维坐标的计算算错。使用row,col能减少犯错可能;

另外就是数据读取,这里改成%c,则需要过滤掉换行符\n,方法是scanf时的格式串首部添加空格:scanf(" %c", &xx)

6. 并查集,去掉了DFS

思路:遍历每个像素点,每个像素点用并查集算法合并周边8邻域中为'@'的像素点。再次遍历,统计每个'@'像素对应的等价类(root节点)的值。第三次遍历,把第二次统计的值当中cnt数大于0的累计,就是区域个数。在统计连通域个数的时候顺带把每个连通域id(像素的parent值)修改为从1开始严格单调增的序列,开启LOCALLOCAL_DEBUG宏可以看到。

和通常用的模板写法略有差别,比如返回root的递归终止条件,比如root初值。

不得不说,uDebug是个好东西。

#include <stdio.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h> typedef struct FSU_Node {
int p; /* parent id */
int rank;
} FSU_Node; /*
get node's root id
@param x: node id
@param nodes: all nodes in map
*/ int fus_find(int x, FSU_Node* nodes) {
if (nodes[x].p == x) {
return x;
} nodes[x].p = fus_find(nodes[x].p, nodes);
return nodes[x].p;
} /*
merge two node groups
@param a: a node from one node group
@param b: a node from another node group
*/
void fus_union(int a, int b, FSU_Node* nodes)
{
int ra = fus_find(a, nodes); /* ra: root id of a */
int rb = fus_find(b, nodes); /* rb: root id of b */
if (ra == rb) {
return;
} if (nodes[ra].rank > nodes[rb].rank) {
nodes[rb].p = ra;
}
else {
if (nodes[ra].rank == nodes[rb].rank) {
nodes[rb].rank++;
}
nodes[ra].p = rb;
}
} /* #define LOCAL */
/* #define LOCAL_DEBUG */
int main() {
#ifdef LOCAL
const char* input_txt = "F:/zhangzhuo/debug/OJ/UVA-572.txt";
freopen(input_txt, "r", stdin);
#endif #define MAXN 105
int m, n, cnt, i, j, k; int shift_x[8] = { -1, -1, -1, 0, 0, 1, 1, 1 };
int shift_y[8] = { -1, 0, 1, -1, 1, -1, 0, 1 }; unsigned char mp[MAXN*MAXN];
FSU_Node nodes[MAXN*MAXN]; int idx; while (scanf("%d%d", &m, &n) == 2 && m && n) {
cnt = 0;
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
idx = i * n + j;
scanf(" %c", &mp[idx]);
}
}
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
idx = i * n + j;
nodes[idx].p = idx;
nodes[idx].rank = 1;
}
} for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
idx = i * n + j;
if (mp[idx] != '@') continue;
for (k = 0; k < 8; k++) {
int row = i + shift_x[k];
int col = j + shift_y[k];
int neighbor_idx = row * n + col;
if (row < 0 || row >= m || col < 0 || col >= n || mp[neighbor_idx] != '@') continue;
fus_union(idx, neighbor_idx, nodes);
}
}
} int bowl[MAXN*MAXN] = { 0 };
int label_cnt = 0;
for (i = 0; i < m*n; i++) {
if (mp[i] != '@') continue;
int t = fus_find(i, nodes);
nodes[i].p = t;
if (bowl[t] == 0) {
label_cnt++;
bowl[t] = label_cnt;
}
}
printf("%d\n", label_cnt); #ifdef LOCAL_DEBUG
/* print out debug info */
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
idx = i * n + j ;
if (mp[idx] == '@') {
/* printf("%3d", fus_find(idx, nodes)); */
/* printf("%3d", nodes[idx].p); */
printf("%3d", bowl[nodes[idx].p]);
}
else {
printf("%3c", '*');
}
}
printf("\n");
}
printf("\n");
#endif } return 0;
}

UVA572 Oil Deposits DFS求解的更多相关文章

  1. UVa572 Oil Deposits DFS求连通块

      技巧:遍历8个方向 ; dr <= ; dr++) ; dc <= ; dc++) || dc != ) dfs(r+dr, c+dc, id); 我的解法: #include< ...

  2. HDOJ(HDU).1241 Oil Deposits(DFS)

    HDOJ(HDU).1241 Oil Deposits(DFS) [从零开始DFS(5)] 点我挑战题目 从零开始DFS HDOJ.1342 Lotto [从零开始DFS(0)] - DFS思想与框架 ...

  3. Oil Deposits(dfs)

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission( ...

  4. HDU 1241 Oil Deposits DFS(深度优先搜索) 和 BFS(广度优先搜索)

    Oil Deposits Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total ...

  5. HDU 1241 Oil Deposits (DFS/BFS)

    Oil Deposits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Tota ...

  6. HDU-1241 Oil Deposits (DFS)

    Oil Deposits Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total ...

  7. HDU_1241 Oil Deposits(DFS深搜)

    Problem Description The GeoSurvComp geologic survey company is responsible for detecting underground ...

  8. UVa 572 Oil Deposits(DFS)

     Oil Deposits  The GeoSurvComp geologic survey company is responsible for detecting underground oil ...

  9. [POJ] 1562 Oil Deposits (DFS)

    Oil Deposits Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 16655   Accepted: 8917 Des ...

随机推荐

  1. phpspreadsheet

    2019-5-9 8:20:07 星期四 昨天在看PHPExcel的时候, github上作者说已经停止更新了, 推荐使用phpspreadsheet, 查看了一下官方文档, 功能还挺强大的, 可以读 ...

  2. flow

    Flow vs Stream https://wikidiff.com/flow/stream As nouns the difference between flow and stream is t ...

  3. WPF之图片处理系列(19/590)

    https://www.cnblogs.com/Big-Head/p/12068230.html

  4. nginx使用与配置入门指南

    这是一篇关于nginx使用与配置的入门指南,但不包括nginx的编译与安装.我假定你知晓如何安装nginx.对大多数Linux系统来说,nginx都已经存在于它们的软件包里,直接使用系统提供的软件管理 ...

  5. vim设定Tab缩进长度

    在Linux系统中,vim是一款非常好用的文本编辑器,那么,如何在Linux下的vim编辑器设定Tab的缩进长度呢? Linux系统下,vim编辑器Tab键的默认长度为8个空格,在vim中可以通过修改 ...

  6. 修改Jupyter Notebook的默认打开路径

    一: (也可以直接将删除的部分修改成所要存储的文件路径,之后三个步骤就可以省去了) 二: 打开Windows的cmd,在cmd中输入jupyter notebook --generate-config ...

  7. C++中const限定符

    const基础 C++中的const,用于定义一个常量,这个常量的值不能被修改.因为const对象一旦创建就不能修改,所以const对象必须初始化.const常量特征仅仅在执行改变其本身的操作时才会发 ...

  8. 【转】python测试框架--doctest

    转自https://my.oschina.net/lionets/blog/268542 doctest 是一个 Python 发行版自带的标准模块.有两种模式可供使用. ##1 doctest 的概 ...

  9. 74HC573锁存器应用(附英文手册)

    锁存器(LATCH)概念 锁存器(Latch)是一种对脉冲电平敏感的存储单元电路,它们可以在特定输入脉冲电平作用下改变状态. 锁存,就是把信号暂存以维持某种电平状态. 锁存器作用: 缓存 完成高速的控 ...

  10. hadoop2.x大数据视频教程(十二天学会)