this problem is a very classic problem which can use stack to solve. the problem can be searched through many source site.

#include<cstdio>
#include<stack>//表明要调用关于栈的文件吧;
using namespace std;
const int maxn=+;
使用栈
int n,target[maxn];
int main()
{
while(scanf("%d",&n)==)
{
stack<int> s;//生成一个元素为int的栈吧;
int A=,B=;
for(int i=;i<=n;i++)
scanf("%d",&target[i]);//读入出栈顺序;
int ok =;
while(B<=n)
{
if(A==target[B]){A++;B++;}//进等于出就直接出;
else if(!s.empty()&&s.top()==target[B])
{s.pop();B++;}//如果S不为空栈并且s的栈顶元素正好为需要的B元素就直接把顶端元素放出去;
else if(A<=n)s.push(A++);//还有合法的未进栈元素就让其进栈;
else {ok=;break;}
}
printf("%s\n",ok?"Yes":"No");
}
return ;
}

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