python算法&二分查找法

import random

def random_list(n):
    result = []
    ids = list(range(1001,1001+n))
    a1 = ["赵","钱","孙","李","周","吴","郑","王","冯","陈","褚","卫","蒋","沈","韩","杨","朱","秦","尤","许","何","吕","施","张"]
    a2 = ["","明","俊","辞","泽","鹏","振","镇","苗","华","国","澄","邈","德","泽","海","超","曦","阳","荣","逸","昌","钰","玥""菲","雯","嘉","麟","芸","希","瀚"]
    a3 = ["克","智","诚","宇","华","","杰","天","锋","巍","荣","凯","海","瑶","涵","雅","晨","曦","麟","炜","茜","萱","玥","菲","雯","嘉","麟","芸","希","瀚"]
    for i in range(n):
        age = random.randint(18,60)
        id = ids [i]
        name = random.choice(a1)+random.choice(a2)+random.choice(a3)
        dict = {"id":id,"name":name,"age":age}
        result.append(dict)
    return  result

'''
输入学生id，输出该学生在列表中的下标，并输出完整学生信息
'''
def bin_search(data_set,val):
    low = 0
    high = len(data_set) - 1
    while low <= high :
        mid = (low + high) // 2
        if data_set[mid]["id"] == val:
            return data_set[mid]
        elif data_set[mid]["id"] > val:
            high = mid - 1
        else:
            low = mid + 1
    return
userlist = random_list(100)
u = bin_search(userlist,1051)
print(u)