golang json字符串合并操作

用于两个json格式的字符串合并，当B向A合并时，共有的字段，将用B字段的值（伴随类型一起覆盖），非共有的，A的字段保留，B的字段新增。

example代码：

package main

import (
	"encoding/json"
	"fmt"
)

type S struct {
	A uint32 `json:"a"`
	B string `json:"b"`
	C uint32 `json:"c"`
}

type S1 struct {
	B string `json:"b"`
	C uint32 `json:"c"`
	D uint32 `json:"d"`
}

func main() {
	s := S{
		A: 12,
		C: 2,
	}
	s1 := S1{
		B: "123",
		C: 99999,
		D: 10,
	}
	js, _ := json.Marshal(s)
	js1, _ := json.Marshal(s1)

	var m map[string]interface{}
	json.Unmarshal(js, &m)
	json.Unmarshal(js1, &m)

	res, _ := json.Marshal(m)

	fmt.Println(string(res)) // {"a":12,"b":"123","c":99999,"d":10}
}

　　ref：https://stackoverrun.com/cn/q/11154146

这样的方法无法递归合并，新方法可递归：

package main

import (
	"encoding/json"
	"fmt"
	"reflect"
)

var jsonMergeDepth = 32

func main() {
	buf1 := []byte(`{"a":1,"b":2}`)
	buf2 := []byte(`{"c":3,"d":4,"a":"aaa"}`)

	var m1, m2 map[string]interface{}

	json.Unmarshal(buf1, &m1)
	json.Unmarshal(buf2, &m2)

	merged := JsonMerge(m1, m2)

	fmt.Println(merged)
}

func JsonMerge(dst, src map[string]interface{}) map[string]interface{} {
	return jsMerge(dst, src, 0)
}

func jsMerge(dst, src map[string]interface{}, depth int) map[string]interface{} {
	if dst == nil {
		dst = make(map[string]interface{})
	}
	if depth > jsonMergeDepth {
		return dst
		// panic("too deep!")
	}

	for key, srcVal := range src {

		if dstVal, ok := dst[key]; ok {

			srcMap, srcMapOk := jsMapify(srcVal)
			dstMap, dstMapOk := jsMapify(dstVal)

			if srcMapOk && dstMapOk {
				srcVal = jsMerge(dstMap, srcMap, depth+1)
			}
		}

		dst[key] = srcVal
	}

	return dst
}

func jsMapify(i interface{}) (map[string]interface{}, bool) {

	value := reflect.ValueOf(i)

	if value.Kind() == reflect.Map {

		m := map[string]interface{}{}

		for _, k := range value.MapKeys() {
			m[k.String()] = value.MapIndex(k).Interface()
		}

		return m, true
	}

	return map[string]interface{}{}, false
}

　　

　　

　　ref：https://golangnote.com/topic/209.html