【原】KMeans与深度学习模型结合提高聚类效果

这几天在做用户画像，特征是用户的消费商品的消费金额，原始数据（部分）是这样的：

 id      goods_name goods_amount
     男士手袋       1882.0
     淑女装       2491.0
     女士手袋       345.0
     基础内衣       328.0
     商务正装       4985.0
     时尚               969.0
     女饰品       86.0
     专业运动       399.0
     童装（中大童) 2033.0
     男士配件       38.0

我们看到同一个id下面有不同的消费记录，这个数据不能直接拿来用，写了python程序来进行处理：test.py

 #!/usr/bin/python
 #coding:utf-8
 #Author：Charlotte
 import pandas as pd
 import numpy as np
 import time

 #加载数据文件(你可以加载自己的文件，文件格式如上所示)
 x=pd.read_table('test.txt',sep = " ")

 #去除NULL值
 x.dropna()

 a1=list(x.iloc[:,0])
 a2=list(x.iloc[:,1])
 a3=list(x.iloc[:,2])

 #A是商品类别
 dicta=dict(zip(a2,zip(a1,a3)))
 A=list(dicta.keys())
 #B是用户id
 B=list(set(a1))

 # data_class = pd.DataFrame(A,lista)

 #创建商品类别字典
 a = np.arange(len(A))
 lista = list(a)
 dict_class = dict(zip(A,lista))
 print dict_class

 f=open('class.txt','w')
 for k ,v in dict_class.items():
     f.write(str(k)+'\t'+str(v)+'\n')
 f.close()

 #计算运行时间
 start=time.clock()

 #创建大字典存储数据
 dictall = {}
 for i in xrange(len(a1)):
     if a1[i] in dictall.keys():
         value = dictall[a1[i]]
         j = dict_class[a2[i]]
         value[j] = a3[i]
         dictall[a1[i]]=value
     else:
         value = list(np.zeros(len(A)))
         j = dict_class[a2[i]]
         value[j] = a3[i]
         dictall[a1[i]]=value

 #将字典转化为dataframe
 dictall1 = pd.DataFrame(dictall)
 dictall_matrix = dictall1.T
 print dictall_matrix

 end = time.clock()
 print "赋值过程运行时间是:%f s"%(end-start)

输出结果：

{'\xe4\xb8\x93\xe4\xb8\x9a\xe8\xbf\x90\xe5\x8a\xa8': 4, '\xe7\x94\xb7\xe5\xa3\xab\xe6\x89\x8b\xe8\xa2\x8b': 1, '\xe5\xa5\xb3\xe5\xa3\xab\xe6\x89\x8b\xe8\xa2\x8b': 2, '\xe7\xab\xa5\xe8\xa3\x85\xef\xbc\x88\xe4\xb8\xad\xe5\xa4\xa7\xe7\xab\xa5)': 3, '\xe7\x94\xb7\xe5\xa3\xab\xe9\x85\x8d\xe4\xbb\xb6': 9, '\xe5\x9f\xba\xe7\xa1\x80\xe5\x86\x85\xe8\xa1\xa3': 8, '\xe6\x97\xb6\xe5\xb0\x9a': 6, '\xe6\xb7\x91\xe5\xa5\xb3\xe8\xa3\x85': 7, '\xe5\x95\x86\xe5\x8a\xa1\xe6\xad\xa3\xe8\xa3\x85': 5, '\xe5\xa5\xb3\xe9\xa5\xb0\xe5\x93\x81': 0}

    0     1    2     3    4     5    6     7    8   9
1   0  1882    0     0    0     0    0     0    0   0
2   0     0  345     0    0     0    0  2491    0   0
4   0     0    0     0    0     0    0     0  328   0
5  86     0    0     0    0  4985  969     0    0   0
6   0     0    0  2033  399     0    0     0    0  38
赋值过程运行时间是:0.004497 s

linux环境下字符编码不同，class.txt:
专业运动    4
男士手袋    1
女士手袋    2
童装（中大童)    3
男士配件    9
基础内衣    8
时尚    6
淑女装    7
商务正装    5
女饰品    0

得到的dicta_matrix 就是我们拿来跑数据的格式，每一列是商品名称，每一行是用户id

　　　现在我们来跑AE模型（Auto-encoder），简单说说AE模型，主要步骤很简单，有三层，输入-隐含-输出，把数据input进去，encode然后再decode，cost_function就是output与input之间的“差值”（有公式），差值越小，目标函数值越优。简单地说，就是你输入n维的数据，输出的还是n维的数据，有人可能会问，这有什么用呢，其实也没什么用，主要是能够把数据缩放，如果你输入的维数比较大，譬如实际的特征是几千维的，全部拿到算法里跑，效果不见得好，因为并不是所有特征都是有用的，用AE模型后，你可以压缩成m维（就是隐含层的节点数），如果输出的数据和原始数据的大小变换比例差不多，就证明这个隐含层的数据是可用的。这样看来好像和降维的思想类似，当然AE模型的用法远不止于此，具体贴一篇梁博的博文

不过梁博的博文是用c++写的，这里使用python写的代码（开源代码，有少量改动）：

 #/usr/bin/python
 #coding:utf-8

 import pandas as pd
 import numpy as np
 import matplotlib.pyplot as plt
 from sklearn import preprocessing

 class AutoEncoder():
     """ Auto Encoder
     layer      1     2    ...    ...    L-1    L
       W        0     1    ...    ...    L-2
       B        0     1    ...    ...    L-2
       Z              0     1     ...    L-3    L-2
       A              0     1     ...    L-3    L-2
     """

     def __init__(self, X, Y, nNodes):
         # training samples
         self.X = X
         self.Y = Y
         # number of samples
         self.M = len(self.X)
         # layers of networks
         self.nLayers = len(nNodes)
         # nodes at layers
         self.nNodes = nNodes
         # parameters of networks
         self.W = list()
         self.B = list()
         self.dW = list()
         self.dB = list()
         self.A = list()
         self.Z = list()
         self.delta = list()
         for iLayer in range(self.nLayers - 1):
             self.W.append( np.random.rand(nNodes[iLayer]*nNodes[iLayer+1]).reshape(nNodes[iLayer],nNodes[iLayer+1]) )
             self.B.append( np.random.rand(nNodes[iLayer+1]) )
             self.dW.append( np.zeros([nNodes[iLayer], nNodes[iLayer+1]]) )
             self.dB.append( np.zeros(nNodes[iLayer+1]) )
             self.A.append( np.zeros(nNodes[iLayer+1]) )
             self.Z.append( np.zeros(nNodes[iLayer+1]) )
             self.delta.append( np.zeros(nNodes[iLayer+1]) )

         # value of cost function
         self.Jw = 0.0
         # active function (logistic function)
         self.sigmod = lambda z: 1.0 / (1.0 + np.exp(-z))
         # learning rate 1.2
         self.alpha = 2.5
         # steps of iteration 30000
         self.steps = 10000

     def BackPropAlgorithm(self):
         # clear values
         self.Jw -= self.Jw
         for iLayer in range(self.nLayers-1):
             self.dW[iLayer] -= self.dW[iLayer]
             self.dB[iLayer] -= self.dB[iLayer]
         # propagation (iteration over M samples)
         for i in range(self.M):
             # Forward propagation
             for iLayer in range(self.nLayers - 1):
                 if iLayer==0: # first layer
                     self.Z[iLayer] = np.dot(self.X[i], self.W[iLayer])
                 else:
                     self.Z[iLayer] = np.dot(self.A[iLayer-1], self.W[iLayer])
                 self.A[iLayer] = self.sigmod(self.Z[iLayer] + self.B[iLayer])
             # Back propagation
             for iLayer in range(self.nLayers - 1)[::-1]: # reserve
                 if iLayer==self.nLayers-2:# last layer
                     self.delta[iLayer] = -(self.X[i] - self.A[iLayer]) * (self.A[iLayer]*(1-self.A[iLayer]))
                     self.Jw += np.dot(self.Y[i] - self.A[iLayer], self.Y[i] - self.A[iLayer])/self.M
                 else:
                     self.delta[iLayer] = np.dot(self.W[iLayer].T, self.delta[iLayer+1]) * (self.A[iLayer]*(1-self.A[iLayer]))
                 # calculate dW and dB
                 if iLayer==0:
                     self.dW[iLayer] += self.X[i][:, np.newaxis] * self.delta[iLayer][:, np.newaxis].T
                 else:
                     self.dW[iLayer] += self.A[iLayer-1][:, np.newaxis] * self.delta[iLayer][:, np.newaxis].T
                 self.dB[iLayer] += self.delta[iLayer]
         # update
         for iLayer in range(self.nLayers-1):
             self.W[iLayer] -= (self.alpha/self.M)*self.dW[iLayer]
             self.B[iLayer] -= (self.alpha/self.M)*self.dB[iLayer]

     def PlainAutoEncoder(self):
         for i in range(self.steps):
             self.BackPropAlgorithm()
             print "step:%d" % i, "Jw=%f" % self.Jw

     def ValidateAutoEncoder(self):
         for i in range(self.M):
             print self.X[i]
             for iLayer in range(self.nLayers - 1):
                 if iLayer==0: # input layer
                     self.Z[iLayer] = np.dot(self.X[i], self.W[iLayer])
                 else:
                     self.Z[iLayer] = np.dot(self.A[iLayer-1], self.W[iLayer])
                 self.A[iLayer] = self.sigmod(self.Z[iLayer] + self.B[iLayer])
                 print "\t layer=%d" % iLayer, self.A[iLayer]        

 data=[]
 index=[]
 f=open('./data_matrix.txt','r')
 for line in f.readlines():
     ss=line.replace('\n','').split('\t')
     index.append(ss[0])
     ss1=ss[1].split(' ')
     tmp=[]
     for i in xrange(len(ss1)):
         tmp.append(float(ss1[i]))
     data.append(tmp)
 f.close()

 x = np.array(data)
 #归一化处理
 xx = preprocessing.scale(x)
 nNodes = np.array([ 10, 5, 10])
 ae3 = AutoEncoder(xx,xx,nNodes)
 ae3.PlainAutoEncoder()
 ae3.ValidateAutoEncoder()

 #这是个例子，输出的结果也是这个
 # xx = np.array([[0,0,0,0,0,0,0,1], [0,0,0,0,0,0,1,0], [0,0,0,0,0,1,0,0], [0,0,0,0,1,0,0,0],[0,0,0,1,0,0,0,0], [0,0,1,0,0,0,0,0]])
 # nNodes = np.array([ 8, 3, 8 ])
 # ae2 = AutoEncoder(xx,xx,nNodes)
 # ae2.PlainAutoEncoder()
 # ae2.ValidateAutoEncoder()

这里我拿的例子做的结果，真实数据在服务器上跑，大家看看这道啥意思就行了

[0 0 0 0 0 0 0 1]
     layer=0 [ 0.76654705  0.04221051  0.01185895]
     layer=1 [  4.67403977e-03   5.18624788e-03   2.03185410e-02   1.24383559e-02
   1.54423619e-02   1.69197292e-03   2.34471751e-05   9.72956513e-01]
[0 0 0 0 0 0  0]
     layer=0 [ 0.08178768  0.96348458  0.98583155]
     layer=1 [  8.18926274e-04   7.30041977e-04   1.06452565e-02   9.94423121e-03
   3.47329848e-03   1.32582980e-02   9.80648863e-01   8.42319408e-08]
[0 0 0 0 0  0 0]
     layer=0 [ 0.04752084  0.01144966  0.67313608]
     layer=1 [  4.38577163e-03   4.12704649e-03   1.83408905e-02   1.59209302e-05
   2.32400619e-02   9.71429772e-01   1.78538577e-02   2.20897151e-03]
[0 0 0 0  0 0 0]
     layer=0 [ 0.00819346  0.37410028  0.0207633 ]
     layer=1 [  8.17965283e-03   7.94760145e-03   4.59916741e-05   2.03558668e-02
   9.68811657e-01   2.09241369e-02   6.19909778e-03   1.51964053e-02]
[0 0 0  0 0 0 0]
     layer=0 [ 0.88632868  0.9892662   0.07575306]
     layer=1 [  1.15787916e-03   1.25924912e-03   3.72748604e-03   9.79510789e-01
   1.09439392e-02   7.81892291e-08   1.06705286e-02   1.77993321e-02]
[0 0  0 0 0 0 0]
     layer=0 [ 0.9862938   0.2677048   0.97331042]
     layer=1 [  6.03115828e-04   6.37411444e-04   9.75530999e-01   4.06825647e-04
   2.66386294e-07   1.27802666e-02   8.66599313e-03   1.06025228e-02]

可以很明显看layer1和原始数据是对应的，所以我们可以把layer0作为降维后的新数据。

最后在进行聚类，这个就比较简单了，用sklearn的包，就几行代码：

 # !/usr/bin/python
 # coding:utf-8
 # Author :Charlotte

 from matplotlib import pyplot
 import scipy as sp
 import numpy as np
 import matplotlib.pyplot as plt
 from sklearn.cluster   import KMeans
 from scipy import sparse
 import pandas as pd
 import Pycluster as pc
 from sklearn import preprocessing
 from sklearn.preprocessing import StandardScaler
 from sklearn import metrics
 import pickle
 from sklearn.externals import joblib

 #加载数据
 data = pd.read_table('data_new.txt',header = None,sep = " ")
 x = data.ix[:,1:141]
 card = data.ix[:,0]
 x1 = np.array(x)
 xx = preprocessing.scale(x1)
 num_clusters = 5

 clf = KMeans(n_clusters=num_clusters,  n_init=1, n_jobs = -1,verbose=1)
 clf.fit(xx)
 print(clf.labels_)
 labels = clf.labels_
 #score是轮廓系数
 score = metrics.silhouette_score(xx, labels)
 # clf.inertia_用来评估簇的个数是否合适，距离越小说明簇分的越好
 print clf.inertia_
 print score

　　这个数据是拿来做例子的，维度少，效果不明显，真实环境下的数据是30W*142维的，写的mapreduce程序进行数据处理，然后通过AE模型降到50维后，两者的clf.inertia_和silhouette(轮廓系数)有显著差异:

	clf.inertia_	silhouette
base版本	252666.064229	0.676239435
AE模型跑后的版本	662.704257502	0.962147623

所以可以看到没有用AE模型直接聚类的模型跑完后的clf.inertia_比用了AE模型之后跑完的clf.inertia_大了几个数量级，AE的效果还是很显著的。

以上是随手整理的，如有错误，欢迎指正：）