题意:每次可以对a进行两种操作,1:如果是偶数,则变成3*a/2;2:变成a-1

显然当a=1时,b只能为1

a=2或3时,b只能为123

a>3时,b可以为任意数

代码:

#include<iostream>
#include<cstdio>
#include<cstdlib>
#define ll long long
using namespace std;
int T;
ll a,b,fl;
int main()
{
scanf("%d",&T);
while(T--)
{
scanf("%I64d%I64d",&a,&b);
if(a==b)fl=;
else
{
if(a>b)fl=;
else
{
if(a==)fl=;
if(a== && b>)fl=;
if(a== && b==)fl=;
if(a==)fl=;
if(a>)fl=;
}
}
printf(fl?"YES\n":"NO\n");
}
return ;
}

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